ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©¹¹³ÉÎïÖʵÄ΢Á£ºÜ¶à£¬Àë×Ó¾ÍÊǹ¹³ÉÎïÖʵĻù±¾Î¢Á£Ö®Ò»£¬Ï±íÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄ¼¸ÖÖÀë×Ó£º

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©K+Àë×ӵĽṹʾÒâͼ             £¬ClÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ                  ¡£
£¨2£©½«º¬OH-Àë×ÓµÄÈÜÒºµÎÈëŨ¶ÈΪ0.1mol/LµÄAl3+ºÍNH+4µÄ»ìºÏÈÜÒºÖУ¬Èô²âµÃÈÜÒºÖÐNH+4¼õÉÙÁËÒ»°ë£¬Ôò´ËʱÈÜÒºÖР           £¨Ìî¡°´æÔÚ¡±»ò¡°²»´æÔÚ¡±£©´óÁ¿µÄAl3+¡£
£¨3£©ÎïÖÊAºÍB·Ö±ðÓÉÉϱíÖеÄÁ½ÖÖÀë×Ó×é³É£¬½«ËüÃÇ·Ö±ðÈÜÓÚË®ÖУ¬AµÄÈÜÒºÏÔËáÐÔ£¬BµÄÈÜÒºÏÔ¼îÐÔÇÒBµÄÑæÉ«·´Ó¦³Ê×ÏÉ«£¨Í¸¹ýÀ¶É«×ê²£Á§¹Û²ì£©£¬½«A¡¢BÁ½ÈÜÒº»ìºÏ£¬¼ÈÓа×É«³ÁµíÉú³É£¬ÓÖÓÐÎÞÉ«ÎÞζµÄÆøÌåÉú³É¡£ÔòAÖк¬ÓеÄÑôÀë×ÓÊÇ      £¬BÈÜÒºÏÔ¼îÐÔµÄÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³ÌʽºÍ±ØÒªµÄÎÄ×Ö˵Ã÷£©                                 ¡£
£¨4£©³£ÎÂÏ£¬½«£¨NH4£©2CO3ÈÜÓÚË®£¬µÃµ½º¬ÓдóÁ¿NH4+ºÍCO2-3µÄÈÜÒº£¬ÍùÈÜÒºÖеÎÈëÉÙÁ¿°±Ë®£¬²âµÃÈÜÒºÖÐNH+4ºÍCO2-3µÄŨ¶È±ÈΪ2£º1£¬Ôò´Ëʱ¸ÃÈÜÒºµÄpH         £¨Ìî¡°<¡±¡¢ ¡°=¡±»ò¡°>¡±£©7¡£
£¨5£©ÔÚ΢ÉúÎï×÷ÓÃϵÄÌõ¼þ£¬NH+4¿É±»¿ÕÆøÑõ»¯³ÉNO-3¡£Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ
                            ¡£


£¨¹²12·Ö£©£¨1£©¡¡£¨1·Ö£©¡¡£»µÚÈýÖÜÆÚ¢÷A£¨2·Ö£©
£¨2£©²»´æÔÚ£¨1·Ö£© 
£¨3£©Al3+£¨1·Ö£©£»BΪKHCO3£¬ÔÚÈÜÒºÖеçÀë³öK£«ºÍHCO3£­¡£HCO3£­ÔÚÈÜÒºÖдæÔÚË®½âºÍµçÀëÁ½ÖÖƽºâ£ºHCO3£­£«H2OH2CO3£«OH£­¡¢HCO3£­CO32£­£«H£«¡£ÓÉÓÚHCO3£­µÄË®½â³Ì¶È´óÓÚµçÀë³Ì¶È£¬ËùÒÔÈÜÒºÏÔ¼îÐÔ¡££¨3·Ö£©
£¨4£©£¼ ( 2·Ö )  £¨5£©NH4£«£«2O2NO3£­£«H2O£«2H£«£¨2·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨12·Ö£©¹¹³ÉÎïÖʵÄ΢Á£ºÜ¶à£¬Àë×Ó¾ÍÊǹ¹³ÉÎïÖʵĻù±¾Î¢Á£Ö®Ò»£¬Ï±íÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄ¼¸ÖÖÀë×Ó£º

    »Ø´ðÏÂÁÐÎÊÌ⣺

    £¨1£©K+Àë×ӵĽṹʾÒâͼ             £¬ClÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ                  ¡£

    £¨2£©½«º¬OH-Àë×ÓµÄÈÜÒºµÎÈëŨ¶ÈΪ0.1mol/LµÄAl3+ºÍNH+4µÄ»ìºÏÈÜÒºÖУ¬Èô²âµÃÈÜÒºÖÐNH+4¼õÉÙÁËÒ»°ë£¬Ôò´ËʱÈÜÒºÖР           £¨Ìî¡°´æÔÚ¡±»ò¡°²»´æÔÚ¡±£©´óÁ¿µÄAl3+¡£

    £¨3£©ÎïÖÊAºÍB·Ö±ðÓÉÉϱíÖеÄÁ½ÖÖÀë×Ó×é³É£¬½«ËüÃÇ·Ö±ðÈÜÓÚË®ÖУ¬AµÄÈÜÒºÏÔËáÐÔ£¬BµÄÈÜÒºÏÔ¼îÐÔÇÒBµÄÑæÉ«·´Ó¦³Ê×ÏÉ«£¨Í¸¹ýÀ¶É«×ê²£Á§¹Û²ì£©£¬½«A¡¢BÁ½ÈÜÒº»ìºÏ£¬¼ÈÓа×É«³ÁµíÉú³É£¬ÓÖÓÐÎÞÉ«ÎÞζµÄÆøÌåÉú³É¡£ÔòAÖк¬ÓеÄÑôÀë×ÓÊÇ      £¬BÈÜÒºÏÔ¼îÐÔµÄÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³ÌʽºÍ±ØÒªµÄÎÄ×Ö˵Ã÷£©                                 ¡£

    £¨4£©³£ÎÂÏ£¬½«£¨NH4£©2CO3ÈÜÓÚË®£¬µÃµ½º¬ÓдóÁ¿NH4+ºÍCO2-3µÄÈÜÒº£¬ÍùÈÜÒºÖеÎÈëÉÙÁ¿°±Ë®£¬²âµÃÈÜÒºÖÐNH+4ºÍCO2-3µÄŨ¶È±ÈΪ2£º1£¬Ôò´Ëʱ¸ÃÈÜÒºµÄpH         £¨Ìî¡°<¡±¡¢ ¡°=¡±»ò¡°>¡±£©7¡£

    £¨5£©ÔÚ΢ÉúÎï×÷ÓÃϵÄÌõ¼þ£¬NH+4¿É±»¿ÕÆøÑõ»¯³ÉNO-3¡£Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ

                                ¡£

 

£¨12·Ö£©¹¹³ÉÎïÖʵÄ΢Á£ºÜ¶à£¬Àë×Ó¾ÍÊǹ¹³ÉÎïÖʵĻù±¾Î¢Á£Ö®Ò»£¬Ï±íÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄ¼¸ÖÖÀë×Ó£º

    »Ø´ðÏÂÁÐÎÊÌ⣺

    £¨1£©K+Àë×ӵĽṹʾÒâͼ              £¬ClÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ                   ¡£

    £¨2£©½«º¬OH-Àë×ÓµÄÈÜÒºµÎÈëŨ¶ÈΪ0.1mol/LµÄAl3+ºÍNH+4µÄ»ìºÏÈÜÒºÖУ¬Èô²âµÃÈÜÒºÖÐNH+4¼õÉÙÁËÒ»°ë£¬Ôò´ËʱÈÜÒºÖР            £¨Ìî¡°´æÔÚ¡±»ò¡°²»´æÔÚ¡±£©´óÁ¿µÄAl3+¡£

    £¨3£©ÎïÖÊAºÍB·Ö±ðÓÉÉϱíÖеÄÁ½ÖÖÀë×Ó×é³É£¬½«ËüÃÇ·Ö±ðÈÜÓÚË®ÖУ¬AµÄÈÜÒºÏÔËáÐÔ£¬BµÄÈÜÒºÏÔ¼îÐÔÇÒBµÄÑæÉ«·´Ó¦³Ê×ÏÉ«£¨Í¸¹ýÀ¶É«×ê²£Á§¹Û²ì£©£¬½«A¡¢BÁ½ÈÜÒº»ìºÏ£¬¼ÈÓа×É«³ÁµíÉú³É£¬ÓÖÓÐÎÞÉ«ÎÞζµÄÆøÌåÉú³É¡£ÔòAÖк¬ÓеÄÑôÀë×ÓÊÇ       £¬BÈÜÒºÏÔ¼îÐÔµÄÔ­ÒòÊÇ£¨ÓÃÀë×Ó·½³ÌʽºÍ±ØÒªµÄÎÄ×Ö˵Ã÷£©                                  ¡£

    £¨4£©³£ÎÂÏ£¬½«£¨NH4£©2CO3ÈÜÓÚË®£¬µÃµ½º¬ÓдóÁ¿NH4+ºÍCO2-3µÄÈÜÒº£¬ÍùÈÜÒºÖеÎÈëÉÙÁ¿°±Ë®£¬²âµÃÈÜÒºÖÐNH+4ºÍCO2-3µÄŨ¶È±ÈΪ2£º1£¬Ôò´Ëʱ¸ÃÈÜÒºµÄpH          £¨Ìî¡°<¡±¡¢ ¡°=¡±»ò¡°>¡±£©7¡£

    £¨5£©ÔÚ΢ÉúÎï×÷ÓÃϵÄÌõ¼þ£¬NH+4¿É±»¿ÕÆøÑõ»¯³ÉNO-3¡£Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ

                                ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø