ÌâÄ¿ÄÚÈÝ

ÔĶÁÏÂÃæÁ½Ìõ¿ÆÆÕÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺

Ò»¸öÌåÖØ50kgµÄ½¡¿µÈËÉíÌåÖк¬Ìú2g£¬Õâ2gÌúÔÚÈËÌåÖв»ÊÇÒÔ½ðÊôµ¥ÖʵÄÐÎʽ´æÔÚ£¬¶øÊÇÒÔFe2+ºÍFe3+µÄÐÎʽ´æÔÚ¡£ÑÇÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬ÑÇÌúÀë×ÓµÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄÌúÀë×Ó»¹Ô­³ÉÑÇÌúÀë×Ó£¬ÓÐÀûÓÚÌúµÄÎüÊÕ£º

ÔÚÐÂÉú´úµÄº£Ë®ÀïÓÐÒ»ÖÖÌúϸ¾ú£¬ËüÃÇÌáÈ¡º£Ë®ÖеÄÑÇÌúÀë×Ó£¬ÀûÓÃøΪ´ß»¯¼Á°ÑËüת±ä³ÉËüÃǵÄƤÇÊ£¨¿ÉÒÔÓÃFe2O3À´±íʾÆäÖеÄÌú£©£¬ºóÀ´±ã³Á»ýÏÂÀ´ÐγÉÌú¿ó£º¸Ã·´Ó¦µÄÁíÒ»ÖÖ·´Ó¦ÎïÊÇCO2£¬·´Ó¦ºóCO2ת±ä³ÉÓлúÎÓü×È©CH2O±íʾ£©¡£

£¨1£©ÕâÁ½Ôò¿ÆÆÕÐÅÏ¢·Ö±ð½éÉÜÁËÈËÌåÄںͺ£Ë®ÖеÄÑÇÌúÀë×ÓÓëÌúÀë×Ó£¨»òÕßÌúµÄ¸ß¼Û»¯ºÏÎÏ໥ת»¯µÄÊÂʵ¡¢·½·¨ºÍ;¾¶¡£Õâ˵Ã÷άÉúËØC¾ßÓР     ÐÔ£¬ÌúÀë×Ó¾ßÓР      ÐÔ£¬µÚ¶þÔòÔòÐÅÏ¢ÖÐCO2ÊÇ         ¼Á¡£

£¨2£©ÌúËáÄÆ£¨Na2FeO4£©ÊÇË®´¦Àí¹ý³ÌÖÐʹÓõÄÒ»ÖÖÐÂÐ;»Ë®¼Á£¬ËüµÄÑõ»¯ÐԱȸßÃÌËá¼Ø¸üÇ¿£¬±¾ÉíÔÚ·´Ó¦Öб»»¹Ô­ÎªFe3+Àë×Ó¡£ÖÆÈ¡ÌúËáÄƵĻ¯Ñ§·½³ÌʽÈçÏ£º

__Fe£¨NO3£©3  +__ NaOH+ __Cl¡ú __Na2FeO4+__NaNO3 + __NaCl +  __H2O

¢ÙÅäƽÉÏÊö·´Ó¦£¬²¢·ÖÎö       ÔªËر»Ñõ»¯£¬µ±Éú³É3mol»¹Ô­²úÎïʱ£¬×ªÒƵç×ÓµÄ×ÜÊýΪ      £»

¢ÚÌúËáÄƳýÁËÄÜÏû¶¾Í⣬»¹¿ÉÒÔÓÃÓÚ¾»Ë®£¬Ô­ÒòÊÇ                     ¡£

 

£¨1£©»¹Ô­ Ñõ»¯ Ñõ»¯£¨2£©1£©2  16  3  2 6  6  8 Ìú3NA  2£©»¹Ô­²úÎïFe3+Ë®½âÉú³ÉFe£¨OH£©3½ºÌ壬Îü¸½Ë®ÖеÄÔÓÖʶø¾»Ë®£»

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

(6·Ö)ÔĶÁÏÂÃæÁ½Ìõ¿ÆÆÕÐÅÏ¢£¬»Ø´ðÎÊÌ⣺

      £¨1£©Ò»¸öÌåÖØ50KgµÄ½¡¿µÈ˺¬Ìú2g£¬Õâ2gÌúÔÚÈËÌåÖв»ÊÇÒÔµ¥ÖʵÄÐÎʽ´æÔÚ£¬¶øÊÇÒÔFe2+ºÍFe3+µÄÐÎʽ´æÔÚ¡£ÑÇÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬ÑÇÌúÀë×ÓµÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄÌúÀë×Ó»¹Ô­³ÉÑÇÌúÀë×Ó£¬ÓÐÀûÓÚÌúµÄÎüÊÕ¡£

£¨2£©ÔÚÐÂÉú´úµÄº£Ë®ÀïÓÐÒ»ÖÖÌúϸ¾ú£¬ËüÃÇÌáÈ¡º£Ë®ÖеÄÑÇÌúÀë×Ó£¬ÀûÓÃøΪ´ß»¯¼Á°ÑËüת±ä³ÉËüÃǵÄƤÇÊ£¨¿ÉÒÔÓÃFe2O3À´±íʾÆäÖеÄÌú£©£¬ºóÀ´±ã³Á»ýÏÂÀ´ÐγÉÌú¿ó£»¸Ã·´Ó¦µÄÁíÒ»ÖÖ·´Ó¦ÎïÊÇCO2£¬·´Ó¦ºóCO2ת±ä³ÉÓлúÎÓü×È©£ºCH2O±íʾ£©¡£

ÎÊÌ⣺

ÕâÁ½Ôò¿ÆÆÕÐÅÏ¢·Ö±ð½éÉÜÁËÈËÌåÄںͺ£Ë®ÖеÄÑÇÌúÀë×ÓÓëÌúÀë×Ó£¨»òÕßÌúµÄ¸ß¼Û»¯ºÏÎÏ໥ת»¯µÄÊÂʵ¡¢·½·¨ºÍ;¾¶¡£Õâ˵Ã÷ÑÇÌúÀë×Ó(Fe2+)¾ßÓР           ÐÔ£¬ÌúÀë×Ó(Fe3+)¾ßÓР          ÐÔ£¬

£¨1£©ÖеÄάÉúËØCÊÇ               ¼Á£¬£¨2£©ÖеÄCO2         ¼Á£¬Ð´³ö£¨2£©ÖеÄÀë×Ó·½³Ìʽ                                       ¡£

 

(14·Ö)ÔĶÁÏÂÃæÁ½Ìõ¿ÆÆÕÐÅÏ¢£¬»Ø´ðÎÊÌ⣺

¢ÙÒ»¸öÌåÖØ50KgµÄ½¡¿µÈ˺¬Ìú2g£¬Õâ2gÌúÔÚÈËÌåÖв»ÊÇÒÔµ¥ÖʽðÊôµÄÐÎʽ´æÔÚ£¬

¶øÊÇÒÔFe2+ºÍFe3+µÄÐÎʽ´æÔÚ¡£ÑÇÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬ÑÇÀë

×ÓµÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄÌúÀë×Ó»¹Ô­³ÉÑÇÌúÀë×Ó£¬ÓÐÓÚ

ÈËÌåÎüÊÕ¡£

¢ÚÔÚÐÂÉú´úµÄº£Ë®ÀïÓÐÒ»ÖÖÌúϸ¾ú£¬ËüÃÇÌáÈ¡º£Ë®ÖеÄÑÇÌúÀë×Ó£¬ÀûÓÃøΪ´ß»¯¼Á°ÑËüת±ä³ÉËüÃǵÄƤÇÊ£¨¿ÉÒÔÓÃFe2O3À´±íʾÆäÖеÄÌú£©£¬ºóÀ´±ã³Á»ýÏÂÀ´ÐγÉÌú¿ó£»

¸Ã·´Ó¦µÄÁíÒ»ÖÖ·´Ó¦ÎïÊÇCO2£¬·´Ó¦ºóCO2ת±ä³ÉÓлúÎï¼×È©£º£¨ÓÃCH2O±íʾ£©¡£

ÎÊÌ⣺

ÕâÁ½Ôò¿ÆÆÕÐÅÏ¢·Ö±ð½éÉÜÁËÈËÌåÄںͺ£Ë®ÖеÄÑÇÌúÀë×ÓÓëÌúÀë×Ó£¨»òÕßÌúµÄ¸ß¼Û»¯ºÏÎÏ໥ת»¯µÄÊÂʵ¡¢·½·¨ºÍ;¾¶

(1)ÄÜÔÚÈËÌå½øÐÐFe2+ºÍFe3+µÄת»¯£¬Õâ˵Ã÷ÑÇÌúÀë×Ó¾ßÓР         ÐÔ£¬ÌúÀë×Ó¾ßÓР          ÐÔ£»

(2)·þÓÃάÉúËØC£¬¿ÉÒÔʹʳÎïÖеÄFe3+»¹Ô­³ÉFe2+£¬Õâ¾ä»°Ö¸³öάÉúËØCÊÇ

        ¼Á£¬¾ßÓР        ÐÔ£»

(3)Êг¡³öÊÛµÄijÖÖÂóƬÖк¬ÓÐ΢Á¿µÄ¿ÅÁ£Ï¸Ð¡µÄ»¹Ô­Ìú·Û£¬ÕâЩÌú·ÛÔÚÈËÌåθËá(Ö÷Òª³É·ÖÊÇÑÎËá)µÄ×÷ÓÃÏÂת»¯³ÉÑÇÌúÑΡ£´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                        £»Àë×Ó·½³ÌʽΪ£º                                      ¡£

(4)µÚ¢ÚÌõÐÅÏ¢ÖеÄCO2×ö         ¼Á£¬Ð´³ö¢ÚÖеÄÀë×Ó·½³Ìʽ                

                                               ¡£ 

 

(6·Ö)ÔĶÁÏÂÃæÁ½Ìõ¿ÆÆÕÐÅÏ¢£¬»Ø´ðÎÊÌ⣺
£¨1£©Ò»¸öÌåÖØ50KgµÄ½¡¿µÈ˺¬Ìú2g£¬Õâ2gÌúÔÚÈËÌåÖв»ÊÇÒÔµ¥ÖʵÄÐÎʽ´æÔÚ£¬¶øÊÇÒÔFe2+ºÍFe3+µÄÐÎʽ´æÔÚ¡£ÑÇÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬ÑÇÌúÀë×ÓµÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄÌúÀë×Ó»¹Ô­³ÉÑÇÌúÀë×Ó£¬ÓÐÀûÓÚÌúµÄÎüÊÕ¡£
£¨2£©ÔÚÐÂÉú´úµÄº£Ë®ÀïÓÐÒ»ÖÖÌúϸ¾ú£¬ËüÃÇÌáÈ¡º£Ë®ÖеÄÑÇÌúÀë×Ó£¬ÀûÓÃøΪ´ß»¯¼Á°ÑËüת±ä³ÉËüÃǵÄƤÇÊ£¨¿ÉÒÔÓÃFe2O3À´±íʾÆäÖеÄÌú£©£¬ºóÀ´±ã³Á»ýÏÂÀ´ÐγÉÌú¿ó£»¸Ã·´Ó¦µÄÁíÒ»ÖÖ·´Ó¦ÎïÊÇCO2£¬·´Ó¦ºóCO2ת±ä³ÉÓлúÎÓü×È©£ºCH2O±íʾ£©¡£
ÎÊÌ⣺
ÕâÁ½Ôò¿ÆÆÕÐÅÏ¢·Ö±ð½éÉÜÁËÈËÌåÄںͺ£Ë®ÖеÄÑÇÌúÀë×ÓÓëÌúÀë×Ó£¨»òÕßÌúµÄ¸ß¼Û»¯ºÏÎÏ໥ת»¯µÄÊÂʵ¡¢·½·¨ºÍ;¾¶¡£Õâ˵Ã÷ÑÇÌúÀë×Ó(Fe2+)¾ßÓР           ÐÔ£¬ÌúÀë×Ó(Fe3+)¾ßÓР          ÐÔ£¬
£¨1£©ÖеÄάÉúËØCÊÇ               ¼Á£¬£¨2£©ÖеÄCO2         ¼Á£¬Ð´³ö£¨2£©ÖеÄÀë×Ó·½³Ìʽ                                       ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø