ÌâÄ¿ÄÚÈÝ

´¿Èý·ú»¯µª(NF3)ÔÚ¼¯³Éµç·¡¢´óÐÍÆÁĻҺ¾§ÏÔʾÆÁ(TFT-LCD)µÄÉú²úÖУ¬×÷ΪÇåÏ´¼ÁÖ®Óá£Èý·ú»¯µªÔÚ³±ÊªµÄ¿ÕÆøÖÐÓëË®ÕôÆøÄÜ·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬Æä·´Ó¦µÄ²úÎïÓУºHF¡¢NOºÍHNO3£¬Çë¸ù¾ÝÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©NF3µÄµç×ÓʽΪ         ¡£

£¨2£©Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡£               ¡£

£¨3£©NF3ÊÇÒ»ÖÖÎÞÉ«¡¢ÎÞ³ôµÄÆøÌ壬µ«Ò»µ©NF3ÔÚ¿ÕÆøÖÐй©£¬»¹ÊÇÒ×ÓÚ·¢ÏÖ¡£ÄãÅжϸÃÆøÌåй©ʱµÄÏÖÏóÊÇ                     ¡£

£¨4£©Ò»µ©NF3й©£¬¿ÉÒÔÓÃÅçÁÜ                   ÈÜÒºµÄ·½·¨¼õÉÙÎÛȾ¡£

£¨5£©Ò»ÖÖÉú²úNF3µÄ·½·¨£º·úÆøÓëҺ̬·ú»¯Çâ泥¨NH4HF2£©·´Ó¦£¬²úÉúNF3¡£Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                      

£¨1£©ÂÔ

£¨2£© 3NF3+5 H2O  =  2 NO+HNO3+9 HF ¡£

£¨3£©²úÉúºì×ØÉ«ÆøÌå¡¢²úÉú°×Îí¡£

£¨4£©NaOH

£¨5£©3F2 + NH4HF2 = NF3 + 5HF

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø