ÌâÄ¿ÄÚÈÝ

Ï©ÌþÔÚÒ»¶¨Ìõ¼þÏ¿ɱ»Ñõ»¯³ÉÈ©¡£

ÀýÈ磺RCH=CHR¡äRCHO+R¡äCHO

ÏÂÁпòͼÖз½¿òÄÚµÄ×Öĸ¸÷´ú±íÒ»ÖÖ·¼Ïã×廯ºÏÎÆäÖÐBµÄ½á¹¹Öв»º¬¼×»ù£¬DµÄ·Ö×ÓʽΪC9H8O2¡£Aת»¯ÎªBʱ£¬AÓëH£ºµÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º2(ÏÂÁÐÎïÖʼäת»¯ÖÐÓеÄÐèÒª¼ÓÈÈ)¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)AµÄ·Ö×ÓʽΪ______________£¬FµÄ½á¹¹¼òʽΪ______________¡£

ACµÄ»¯Ñ§·½³ÌʽΪ______________________________________¡£

(2)BµÄijЩͬ·ÖÒì¹¹ÌåÄܸúŨäåË®·´Ó¦¡£ÆäÖÐ1 molijͬ·ÖÒì¹¹Ìå¸úŨäåË®·´Ó¦Ê±£¬ÐèÏûºÄ3 mol Br2£¬ÇÒ¸Ãͬ·ÖÒì¹¹Ìå·Ö×ÓÖк¬ÓÐÒ»¸ö¼×»ù£¬ÔòÆä½á¹¹¼òʽΪ

_______________________________________________________________¡£

(3)AÊÇÒ»ÖÖ¿ÉÒÔ×÷ΪҩÎïµÄÓлúÎ½«AÔÚÒ»¶¨Ìõ¼þÏÂÑõ»¯ºó¿ÉÒԵõ½Á½ÖÖÓлúËáXºÍY£¬ÆäÖÐYÊǶþÔªËá¡£ÔòXµÄ½á¹¹¼òʽΪ______________£¬YµÄ½á¹¹¼òʽΪ______________¡£

(1)C9H8O

C6H5CH£½CHCHO+2Ag(NH3)2OHC6H5CH=CHCOONH4+2Ag+3NH3+H2O

(2)        (3)     HOOC¡ªCOOH


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø