ÌâÄ¿ÄÚÈÝ

£¨6·Ö£©ÓÉÓÚÎÂÊÒЧӦºÍ×ÊÔ´¶ÌȱµÈÎÊÌ⣬ÈçºÎ½µµÍ´óÆøÖеÄCO2º¬Á¿²¢¼ÓÒÔ¿ª·¢ÀûÓã¬ÒýÆðÁ˸÷¹úµÄÆÕ±éÖØÊÓ¡£Ä¿Ç°¹¤ÒµÉÏÓÐÒ»ÖÖ·½·¨ÊÇÓÃCO2Éú²úȼÁϼ״¼¡£
£¨1£©ÔÚ250C¡¢101KPaʱ£¬3.2¿Ë¼×´¼£¨CH30H£©ÍêȫȼÉÕÉú³ÉCO2ºÍҺ̬ˮʱ·ÅÈÈ72.576kJ£¬ÔòÄܱíʾ¼×´¼È¼ÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ___________________¡£
£¨2£©ÎªÌ½¾¿·´Ó¦Ô­Àí£¬ÏÖ½øÐÐÈçÏÂʵÑ飬ÔÚÌå»ýΪ2 LµÄÃܱÕÈÝÆ÷ÖУ¬³äÈë2mol CO2ºÍ6mol H2£¬Ò»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£ºCO2(g)£«3H2(g)CH3OH(g)£«H2O(g) ¡÷H£½¡ª49kJ/mol£¬²âµÃCO2ºÍH2O (g)µÄŨ¶ÈËæʱ¼ä±ä»¯ÈçͼËùʾ¡£

¢Ù´Ó·´Ó¦¿ªÊ¼µ½Æ½ºâ£¬ÇâÆøµÄƽ¾ù·´Ó¦ËÙÂÊv(H2)£½__________mol/(L¡¤min)¡£
¢ÚÏÂÁдëÊ©ÖÐÄÜʹn(H2O)£¯n(CO2)Ôö´óµÄÊÇ________¡£
A£®Éý¸ßζȠ                      B£®ÔÙ³äÈë3mol H2
C£®½«CH3OH (g)´ÓÌåϵÖзÖÀë        D£®³äÈëHe(g)£¬Ê¹ÌåϵѹǿÔö´ó
£¨6·Ö£©£¨1£©CH3OH(l)+3/2O2(g)=CO2(g)+2H2O(l) ¡÷H=-725.76kJ¡¤mol-1
£¨2£©¢Ù0.225 mol/(L¡¤min)¡£¢ÚB C £¨Ã¿¿Õ2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨14·Ö£©
µª¿ÉÐγɶàÖÖÑõ»¯ÎÈçNO¡¢NO2¡¢N2O4µÈ£¬NO2ºÍN2O4¿ÉÒÔÏ໥ת»¯¡£
£¨1£©¶Ô·´Ó¦2NO2£¨g£©    N2O4£¨g£©¡÷H=-57.2kJ¡¤mol-1
¢ÙÔÚζÈΪT1¡¢ T2ʱ£¬Æ½ºâÌåϵÖÐNO2µÄÌå»ý·ÖÊýËæѹǿ±ä»¯ÇúÏßÈçͼËùʾ¡£T1   T2
£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£»

¢ÚA¡¢CÁ½µãÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿£ºA          C£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡¡±»ò¡°µÈÓÚ¡±£©
£¨2£©ÔÚ100¡æʱ£¬½«0.40molµÄNO2ÆøÌå³äÈë2LµÄÃܱÕÈÝÆ÷ÖУ¬Ã¿¸ôÒ»¶¨Ê±¼ä¾Í¶Ô¸ÃÈÝÆ÷ÄÚµÄÎïÖʽøÐзÖÎö£¬µÃµ½ÈçϱíÊý¾Ý£º
ʱ¼ä£¨s£©
0
20
40
60
80
n£¨NO2£©/mol
0.40
n1
0.26
n3
n 4
n£¨N2O4£©/mol
0.00
0.05
n 2
0.08
0.08
¢ÙÔÚÉÏÊöÌõ¼þÏ£¬´Ó·´Ó¦¿ªÊ¼Ö±ÖÁ20sʱ£¬¶þÑõ»¯µªµÄƽ¾ù·´Ó¦ËÙÂÊΪ          ¡£
¢Ú¸ÃÌõ¼þÏÂƽºâ³£ÊýKµÄֵΪ       ¡£
¢ÛÈôÆäËûÌõ¼þ²»±ä£¬ÏÂÁмÈÄܼӿìÕý·´Ó¦ËÙÂÊÓÖÄÜÌá¸ßNO2ת»¯ÂʵĴëÊ©ÊÇ
A£®³é³öN2O4   B£®½µµÍζȠ  C£®¼Óѹ  D£®¼ÓÈë´ß»¯¼Á
¢ÜÈôÔÚÏàͬÇé¿öÏÂ×î³õÏò¸ÃÈÝÆ÷³äÈëµÄÊÇN2O4ÆøÌ壬Ҫ´ïµ½ÉÏÊöͬÑùµÄƽºâ״̬£¬
N2O4µÄÆðʼµÄÎïÖʵÄÁ¿ÊÇ        ¡£
¢ÝÈôÆäËüÌõ¼þ²»±ä£¬Ö»½«ÈÝÆ÷¸ÄΪ´ø»îÈûµÄºãѹÈÝÆ÷£¬
ÔòƽºâʱN2O4µÄÁ¿         0.08mol¡££¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø