ÌâÄ¿ÄÚÈÝ
25¡æÊ±£¬£¨1£©¡¢½«µÈÌå»ýµÈÎïÖʵÄÁ¿Å¨¶ÈµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ÈÜÒº³Ê £¨Ìî¡°ËáÐÔ¡±£¬¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£¬ÏÂͬ£©£¬ÈÜÒºÖÐc(Na£«) c(CH3COO£)£¨Ìî¡° >¡± »ò¡°£½¡±»ò¡°<¡± £©¡£
£¨2£©¡¢pH£½3µÄ´×ËáºÍpH£½11µÄÇâÑõ»¯ÄÆÈÜÒºµÈÌå»ý»ìºÏºóÈÜÒº³Ê £¬
ÈÜÒºÖÐc(Na£«) c(CH3COO£)
£¨3£©¡¢ÎïÖʵÄÁ¿Å¨¶ÈÏàͬµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ÈÜÒºÖд×Ëá¸ùÀë×ÓºÍÄÆÀë×ÓŨ¶ÈÏàµÈ£¬Ôò»ìºÏºóÈÜÒº³Ê £¬´×ËáÌå»ý ÇâÑõ»¯ÄÆÈÜÒºÌå»ý¡£
£¨4£©¡¢½«m mol/LµÄ´×ËáºÍn mol/LµÄÇâÑõ»¯ÄÆÈÜÒºµÈÌå»ý»ìºÏºóÈÜÒºµÄpH£½7£¬Ôò´×ËáÈÜÒºÖÐc(H£«) ÇâÑõ»¯ÄÆÈÜÒºÖÐc(OH£)£¬mÓënµÄ´óС¹ØÏµÊÇ£í £î¡£
£¨5£©¡¢ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄNH4HSO4ºÍ£¨NH4£©2SO4ÈÜÒº£¬¶¼³Ê ÐÔ£¬Ç°ÕßÏÔËáÐÔµÄÖ÷ÒªÔÒòÊÇ £»ºóÕßÏÔËáÐÔµÄÖ÷ÒªÔÒòÊÇ ¡£
¹²11·Ö£¬Ã¿¿Õ1·Ö
£¨1£©¼îÐÔ£¬£¾£» £¨2£©ËáÐÔ£¬£¼£» £¨3£©ÖÐÐÔ£¬£¾£» £¨4£©£¼£¬£¾¡£
£¨5£©ËáÐÔ£» NH4HSO4µçÀë²úÉúH+ʹÈÜÒºÏÔËáÐÔ£¬ £¨NH4£©2SO4ÊÇÈõ¼îÇ¿ËáÑΣ¬Ë®½âÏÔËáÐÔ
½âÎö: