ÌâÄ¿ÄÚÈÝ
A-I·Ö±ð±íʾÖÐѧ»¯Ñ§Öг£¼ûµÄÒ»ÖÖÎïÖÊ£¬ËüÃÇÖ®¼äÏ໥¹ØϵÈçÏÂͼËùʾ£¨²¿·Ö·´Ó¦Îï¡¢Éú³ÉÎïûÓÐÁгö£©¡£ÒÑÖªHΪÖ÷×åÔªËصĹÌ̬Ñõ»¯ÎFÊǺìºÖÉ«ÄÑÈÜÓÚË®µÄ³Áµí£¬ÇÒA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖоùº¬Í¬Ò»ÖÖÔªËØ¡£
ÇëÌîдÏÂÁпհףº
£¨1£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖÐËùº¬µÄͬһÖÖÔªËØÔÚÔªËØÖÜÆÚ±íÖÐλÖÃ__________
£¨2£©Ð´³öC¡¢HÎïÖʵĻ¯Ñ§Ê½£ºC______£»H_______
£¨3£©Ð´³ö·´Ó¦¢Ù¡¢¢ÞµÄ»¯Ñ§·½³ÌʽºÍ¢Û¡¢¢ßµÄÀë×Ó·½³Ìʽ£º
·´Ó¦¢Ù£º________________________________
·´Ó¦¢Þ£º________________________________
·´Ó¦¢Û£º________________________________
·´Ó¦¢ß£º________________________________
£¨4£©·´Ó¦¢Þ¹ý³ÌÖеÄÏÖÏóÊÇ_____________¡£
£¨1£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖÐËùº¬µÄͬһÖÖÔªËØÔÚÔªËØÖÜÆÚ±íÖÐλÖÃ__________
£¨2£©Ð´³öC¡¢HÎïÖʵĻ¯Ñ§Ê½£ºC______£»H_______
£¨3£©Ð´³ö·´Ó¦¢Ù¡¢¢ÞµÄ»¯Ñ§·½³ÌʽºÍ¢Û¡¢¢ßµÄÀë×Ó·½³Ìʽ£º
·´Ó¦¢Ù£º________________________________
·´Ó¦¢Þ£º________________________________
·´Ó¦¢Û£º________________________________
·´Ó¦¢ß£º________________________________
£¨4£©·´Ó¦¢Þ¹ý³ÌÖеÄÏÖÏóÊÇ_____________¡£
£¨1£©µÚËÄÖÜÆÚµÚ¢ø×å
£¨2£©C£ºFeCl2£»H£ºAl2O3
£¨3£©¢Ù 8Al+3Fe3O44Al2O3+9Fe£»¢Þ4Fe(OH)2+O2+2H2O=4Fe(OH)3£»¢ÛFe3O4+8H+=Fe2++2Fe3++4H2O£»¢ß2Al+2OH-+2H2O=2AlO2-+3H2¡ü
£¨4£©Óа×É«³ÁµíѸËÙ±ä³É»ÒÂÌÉ«£¬×îÖÕ±äΪºìºÖÉ«
£¨2£©C£ºFeCl2£»H£ºAl2O3
£¨3£©¢Ù 8Al+3Fe3O44Al2O3+9Fe£»¢Þ4Fe(OH)2+O2+2H2O=4Fe(OH)3£»¢ÛFe3O4+8H+=Fe2++2Fe3++4H2O£»¢ß2Al+2OH-+2H2O=2AlO2-+3H2¡ü
£¨4£©Óа×É«³ÁµíѸËÙ±ä³É»ÒÂÌÉ«£¬×îÖÕ±äΪºìºÖÉ«
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿