ÌâÄ¿ÄÚÈÝ
£¨12·Ö£©´ÖÑÎÌá´¿µÄÑо¿¡£
¡¾ÓйØ×ÊÁÏ¡¿
»¯Ñ§Ê½ | CaCO3 | CaSO3 | CaC2O4 | Mg(OH)2 |
Ksp | 4.96¡Á10¡ª9 | 4.96¡Á10¡ª9 | 2.34¡Á10¡ª9 | 5.61¡Á10¡ª12 |
ijÑо¿ÐÔѧϰС×é¶Ô´ÖÑεÄÌá´¿ºÍ¼ìÑé½øÐÐÑо¿£¬²¢Ìá³öһЩеķ½°¸¡£ÒÑÖª¸Ã´ÖÑÎÑùÆ·ÖÐÖ÷Òªº¬Óв»ÈÜÐÔÔÓÖÊ¡¢Mg2+¡¢Ca2+µÈ£¨ºöÂÔSO42¡ªµÄ´æÔÚ£©£¬¸ÃС×éÉè¼ÆÁ÷³ÌÈçÏ£º
¡¾Éè¼Æ³ýÔÓ¹ý³Ì¡¿
£¨1£©²Ù×÷¢ÙÖÐÐèҪʹÓõIJ£Á§ÒÇÆ÷ÓÐ ¡¢ ¡£²Ù×÷¢ÚµÄÃû³ÆΪ ¡£
£¨2£©»ìºÏÒºAµÄÖ÷Òª³É·ÖÊÇ ¡££¨Ìѧʽ£©
¡¾¼ìÑé³ýÔÓЧ¹û¡¿
£¨3£©Îª¼ìÑéÈÜÒºBÖÐMg2+¡¢Ca2+ÊÇ·ñ³ý¾¡£¬Í¨³£·Ö±ðÈ¡ÉÙÁ¿ÈÜÒºBÓÚÁ½Ö§ÊÔ¹ÜÖУ¬½øÐÐÈçÏÂʵÑ飺
²½ÖèÒ»£º¼ìÑéMg2+ÊÇ·ñ³ý¾¡¡£ÏòÆäÖÐÒ»Ö§ÊÔ¹ÜÖмÓÈë ÈÜÒº£¨Ìѧʽ£©£¬¿´ÊÇ·ñÓгÁµíÉú³É¡£
²½Öè¶þ£º¼ìÑéCa2+ÊÇ·ñ³ý¾¡¡£ÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëijÈÜÒº£¬¿´ÊÇ·ñÓгÁµíÉú³É¡£Ð§¹û×îºÃµÄÊÇ £¨Ìî×Öĸ£©¡£A£®Na2CO3 B£®Na2SO3 C£®Na2C2O4
¡¾»ñÈ¡´¿¾»Ê³ÑΡ¿
£¨4£©¶ÔÈÜÒºB¼ÓÈȲ¢²»¶ÏµÎ¼Ó6 mol¡¤L¡ª1µÄÑÎËáÈÜÒº£¬Í¬Ê±ÓÃpHÊÔÖ½¼ì²âÈÜÒº£¬Ö±ÖÁpH=2ʱֹͣ¼ÓÑÎËᣬµÃµ½ÈÜÒºC£¬¸Ã²Ù×÷µÄÄ¿µÄÊÇ ¡£
£¨5£©½«ÈÜÒºCµ¹Èë £¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ¬¼ÓÈÈÕô·¢²¢Óò£Á§°ô²»¶Ï½Á°è£¬Ö±µ½ ʱ£¨ÌîÏÖÏ󣩣¬Í£Ö¹¼ÓÈÈ¡£
¡¾ÎÊÌâÌÖÂÛ¡¿
£¨6£©ÔÚ³ýÔÓ¹ý³ÌÖУ¬Ïò´ÖÑÎÐü×ÇÒºÖмӻìºÏÒºA£¬¸Ã²Ù×÷ÖпØÖÆÈÜÒºpH=12¿ÉÈ·±£Mg2+³ý¾¡£¬¸ù¾ÝÌṩµÄÊý¾Ý¼ÆË㣬ÈÜÒºBÖÐMg2+ÎïÖʵÄÁ¿Å¨¶È½«±»¿ØÖÆÔÚ ÒÔÏ¡£
£¨12·Ö£©
£¨1£©ÉÕ±¡¢²£Á§°ô£¬¹ýÂË £¨2·Ö£©
£¨2£©NaOH¡¢Na2CO3 £¨2·Ö£©
£¨3£©NaOH C £¨2·Ö£©
£¨4£©³ýÈ¥NaOHºÍNa2CO3 £¨2·Ö£©
£¨5£©Õô·¢Ãó Õô·¢ÃóÖÐÓдóÁ¿¹ÌÌåÎö³ö£¨2·Ö£©
£¨6£©5.61¡Á10¡ª8 mol¡¤L¡ª1¡££¨2·Ö£©
´ÖÑÎÌá´¿µÄÑо¿£®
¡¾ÓйØ×ÊÁÏ¡¿
»¯Ñ§Ê½ | CaCO3 | CaSO3 | CaC2O4 | Mg£¨OH£©2 |
Ksp | 4.96¡Á10-9 | 4.96¡Á10-9 | 2.34¡Á10-9 | 5.61¡Á10-12 |
¡¾Éè¼Æ³ýÔÓ¹ý³Ì¡¿
£¨1£©²Ù×÷¢ÙÖÐÐèҪʹÓõIJ£Á§ÒÇÆ÷ÓÐ______¡¢______£®²Ù×÷¢ÚµÄÃû³ÆΪ______£¬ÈôÔÚ²Ù×÷¢Ú½áÊøºó·¢ÏÖÈÜÒºBÂÔÓлë×Ç£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ______£®
£¨2£©»ìºÏÒºAµÄÖ÷Òª³É·ÖÊÇ______£®£¨Ìѧʽ£©
¡¾¼ìÑé³ýÔÓЧ¹û¡¿
£¨3£©Îª¼ìÑéÈÜÒºBÖÐMg2+¡¢Ca2+ÊÇ·ñ³ý¾¡£¬Í¨³£·Ö±ðÈ¡ÉÙÁ¿ÈÜÒºBÓÚÁ½Ö§ÊÔ¹ÜÖУ¬½øÐÐÈçÏÂʵÑ飺
²½ÖèÒ»£º¼ìÑéMg2+ÊÇ·ñ³ý¾¡£®ÏòÆäÖÐÒ»Ö§ÊÔ¹ÜÖмÓÈë______ÈÜÒº£¨Ìѧʽ£©£¬¿´ÊÇ·ñÓгÁµíÉú³É£®
²½Öè¶þ£º¼ìÑéCa2+ÊÇ·ñ³ý¾¡£®ÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëijÈÜÒº£¬¿´ÊÇ·ñÓгÁµíÉú³É£®Ð§¹û×îºÃµÄÊÇ______£¨Ìî×Öĸ£©£®
A¡¢Na2CO3¡¡¡¡¡¡ B¡¢Na2SO3¡¡¡¡¡¡¡¡C¡¢Na2C2O4
¡¾»ñÈ¡´¿¾»Ê³ÑΡ¿
£¨4£©¶ÔÈÜÒºB¼ÓÈȲ¢²»¶ÏµÎ¼Ó6mol?L-1µÄÑÎËáÈÜÒº£¬Í¬Ê±ÓÃpHÊÔÖ½¼ì²âÈÜÒº£¬Ö±ÖÁpH=5ʱֹͣ¼ÓÑÎËᣬµÃµ½ÈÜÒºC£®¸Ã²Ù×÷µÄÄ¿µÄÊÇ______£®
£¨5£©½«ÈÜÒºCµ¹Èë______£¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ¬¼ÓÈÈÕô·¢²¢Óò£Á§°ô²»¶Ï½Á°è£¬Ö±µ½______ʱ£¨ÌîÏÖÏ󣩣¬Í£Ö¹¼ÓÈÈ£®
¡¾ÎÊÌâÌÖÂÛ¡¿
£¨6£©ÔÚ³ýÔÓ¹ý³ÌÖУ¬Ïò´ÖÑÎÐü×ÇÒºÖмӻìºÏÒºAʱÐèÒª¼ÓÈÈ£¬Ä¿µÄÊÇ______£¬¸Ã²Ù×÷ÖпØÖÆÈÜÒºpH=12¿ÉÈ·±£Mg2+³ý¾¡£¬¸ù¾ÝÌṩµÄÊý¾Ý¼ÆË㣬ÈÜÒºBÖÐMg2+ÎïÖʵÄÁ¿Å¨¶È½«±»¿ØÖÆÔÚ______ÒÔÏ£®
´ÖÑÎÌá´¿µÄÑо¿¡£
¡¾ÓйØ×ÊÁÏ¡¿
»¯Ñ§Ê½ | CaCO3 | CaSO3 | CaC2O4 | Mg(OH)2 |
Ksp | 4.96¡Á10¨D9 | 4.96¡Á10¨D9 | 2.34¡Á10¨D9 | 5.61¡Á10¨D12 |
ijÑо¿ÐÔѧϰС×é¶Ô´ÖÑεÄÌá´¿ºÍ¼ìÑé½øÐÐÑо¿£¬²¢Ìá³öһЩеķ½°¸¡£ÒÑÖª¸Ã´ÖÑÎÑùÆ·ÖÐÖ÷Òªº¬Óв»ÈÜÐÔÔÓÖÊ¡¢Mg2+¡¢Ca2+µÈ(ºöÂÔSO42¨DµÄ´æÔÚ),¸ÃС×éÉè¼ÆÁ÷³ÌÈçÏ£º
¡¾Éè¼Æ³ýÔÓ¹ý³Ì¡¿
(1)²Ù×÷¢ÙÖÐÐèҪʹÓõIJ£Á§ÒÇÆ÷ÓÐ ¡¢ ¡£²Ù×÷¢ÚµÄÃû³ÆΪ £¬ÈôÔÚ²Ù×÷¢Ú½áÊøºó·¢ÏÖÈÜÒºBÂÔÓлë×Ç£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ_ _____________________________________________________¡£
(2)»ìºÏÒºAµÄÖ÷Òª³É·ÖÊÇ____________________¡£(Ìѧʽ)
¡¾¼ìÑé³ýÔÓЧ¹û¡¿
(3)Ϊ¼ìÑéÈÜÒºBÖÐMg2+¡¢Ca2+ÊÇ·ñ³ý¾¡£¬Í¨³£·Ö±ðÈ¡ÉÙÁ¿ÈÜÒºBÓÚÁ½Ö§ÊÔ¹ÜÖУ¬½øÐÐÈçÏÂʵÑ飺
²½ÖèÒ»£º¼ìÑéMg2+ÊÇ·ñ³ý¾¡¡£ÏòÆäÖÐÒ»Ö§ÊÔ¹ÜÖмÓÈë ÈÜÒº(Ìѧʽ)£¬¿´ÊÇ·ñÓгÁµíÉú³É¡£
²½Öè¶þ£º¼ìÑéCa2+ÊÇ·ñ³ý¾¡¡£ÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëijÈÜÒº£¬¿´ÊÇ·ñÓгÁµíÉú³É¡£Ð§¹û×îºÃµÄÊÇ (Ìî×Öĸ)¡£
A¡¢Na2CO3 B¡¢Na2SO
¡¾»ñÈ¡´¿¾»Ê³ÑΡ¿
(4)¶ÔÈÜÒºB¼ÓÈȲ¢²»¶ÏµÎ¼Ó6 mol?L¨D1µÄÑÎËáÈÜÒº£¬Í¬Ê±ÓÃpHÊÔÖ½¼ì²âÈÜÒº£¬Ö±ÖÁpH=5ʱֹͣ¼ÓÑÎËᣬµÃµ½ÈÜÒºC¡£¸Ã²Ù×÷µÄÄ¿µÄÊÇ ¡£
(5)½«ÈÜÒºCµ¹Èë (ÌîÒÇÆ÷Ãû³Æ)ÖУ¬¼ÓÈÈÕô·¢²¢Óò£Á§°ô²»¶Ï½Á°è£¬Ö±µ½ ___________ _____________ʱ(ÌîÏÖÏó)£¬Í£Ö¹¼ÓÈÈ¡£
¡¾ÎÊÌâÌÖÂÛ¡¿
(6)ÔÚ³ýÔÓ¹ý³ÌÖУ¬Ïò´ÖÑÎÐü×ÇÒºÖмӻìºÏÒºAʱÐèÒª¼ÓÈÈ£¬Ä¿µÄÊÇ £¬¸Ã²Ù×÷ÖпØÖÆÈÜÒºpH=12¿ÉÈ·±£Mg2+³ý¾¡£¬¸ù¾ÝÌṩµÄÊý¾Ý¼ÆË㣬ÈÜÒºBÖÐMg2+ÎïÖʵÄÁ¿Å¨¶È½«±»¿ØÖÆÔÚ______________ÒÔÏ¡£
¡¾ÓйØ×ÊÁÏ¡¿
»¯Ñ§Ê½ | CaCO3 | CaSO3 | CaC2O4 | Mg£¨OH£©2 |
Ksp | 4.96×10-9 | 4.96×10-9 | 2.34×10-9 | 5.61×10-12 |
¡¾Éè¼Æ³ýÔÓ¹ý³Ì¡¿
£¨1£©²Ù×÷¢ÙÖÐÐèҪʹÓõIJ£Á§ÒÇÆ÷ÓÐ______¡¢______£®²Ù×÷¢ÚµÄÃû³ÆΪ______£¬ÈôÔÚ²Ù×÷¢Ú½áÊøºó·¢ÏÖÈÜÒºBÂÔÓлë×Ç£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ______£®
£¨2£©»ìºÏÒºAµÄÖ÷Òª³É·ÖÊÇ______£®£¨Ìѧʽ£©
¡¾¼ìÑé³ýÔÓЧ¹û¡¿
£¨3£©Îª¼ìÑéÈÜÒºBÖÐMg2+¡¢Ca2+ÊÇ·ñ³ý¾¡£¬Í¨³£·Ö±ðÈ¡ÉÙÁ¿ÈÜÒºBÓÚÁ½Ö§ÊÔ¹ÜÖУ¬½øÐÐÈçÏÂʵÑ飺
²½ÖèÒ»£º¼ìÑéMg2+ÊÇ·ñ³ý¾¡£®ÏòÆäÖÐÒ»Ö§ÊÔ¹ÜÖмÓÈë______ÈÜÒº£¨Ìѧʽ£©£¬¿´ÊÇ·ñÓгÁµíÉú³É£®
²½Öè¶þ£º¼ìÑéCa2+ÊÇ·ñ³ý¾¡£®ÏòÁíÒ»Ö§ÊÔ¹ÜÖмÓÈëijÈÜÒº£¬¿´ÊÇ·ñÓгÁµíÉú³É£®Ð§¹û×îºÃµÄÊÇ______£¨Ìî×Öĸ£©£®
A¡¢Na2CO3 B¡¢Na2SO3 C¡¢Na2C2O4
¡¾»ñÈ¡´¿¾»Ê³ÑΡ¿
£¨4£©¶ÔÈÜÒºB¼ÓÈȲ¢²»¶ÏµÎ¼Ó6mol?L-1µÄÑÎËáÈÜÒº£¬Í¬Ê±ÓÃpHÊÔÖ½¼ì²âÈÜÒº£¬Ö±ÖÁpH=5ʱֹͣ¼ÓÑÎËᣬµÃµ½ÈÜÒºC£®¸Ã²Ù×÷µÄÄ¿µÄÊÇ______£®
£¨5£©½«ÈÜÒºCµ¹Èë______£¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ¬¼ÓÈÈÕô·¢²¢Óò£Á§°ô²»¶Ï½Á°è£¬Ö±µ½______ʱ£¨ÌîÏÖÏ󣩣¬Í£Ö¹¼ÓÈÈ£®
¡¾ÎÊÌâÌÖÂÛ¡¿
£¨6£©ÔÚ³ýÔÓ¹ý³ÌÖУ¬Ïò´ÖÑÎÐü×ÇÒºÖмӻìºÏÒºAʱÐèÒª¼ÓÈÈ£¬Ä¿µÄÊÇ______£¬¸Ã²Ù×÷ÖпØÖÆÈÜÒºpH=12¿ÉÈ·±£Mg2+³ý¾¡£¬¸ù¾ÝÌṩµÄÊý¾Ý¼ÆË㣬ÈÜÒºBÖÐMg2+ÎïÖʵÄÁ¿Å¨¶È½«±»¿ØÖÆÔÚ______ÒÔÏ£®