ÌâÄ¿ÄÚÈÝ
ÒÑÖª³ýȼÉÕ·´Ó¦Í⣬´¼Àà·¢ÉúÆäËûÀàÐ͵ÄÑõ»¯·´Ó¦µÄʵÖÊ£¬¶¼ÊÇÔÚ´¼·Ö×ÓÖÐÓëôÇ»ùÖ±½ÓÏàÁ¬µÄ̼Ô×ÓÉϵÄÒ»¸öÇâÔ×Ó±»Ñõ»¯ÎªÒ»¸öеÄôÇ»ù£¬Ðγɲ»Îȶ¨µÄ¡°Ùɶþ´¼¡±¡£½Ó×ÅÔÚ¡°Ùɶþ´¼¡±·Ö×ÓÄÚµÄÁ½¸öôÇ»ù¼äÍÑÈ¥Ò»·Ö×ÓË®£¬Éú³ÉеÄÎïÖÊ¡£ÉÏÊö·´Ó¦»úÀí¿É±íʾΪ£º
ÊÔ¸ù¾Ý´Ë·´Ó¦»úÀí»Ø´ðÏÂÁÐÎÊÌâ(ÓлúÎïд½á¹¹¼òʽ)£º
(1)д³ö1-¶¡´¼ÔÚAgµÄ×÷ÓÃÏ·¢ÉúÑõ»¯·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_______________¡£
(2)д³öCH2C12ÔÚ165¡æ¼°¼Óѹʱ·¢ÉúÍêÈ«Ë®½âµÄ»¯Ñ§·½³Ìʽ£º(Ìáʾ£ºR¡ªx£«H2OROH¡ªHX)_______¡£
(3)Åжϲ¢Ð´³ö½«2-¼×»ù-2-±û´¼¼ÓÈëµ½ËáÐÔKMnO4ÈÜÒºÖеÄÏÖÏó£º__________¡£
´ð°¸£º(3)²»ÍÊÉ«(ÎÞÃ÷ÏÔÏÖÏó)
½âÎö£º
Ìáʾ£º
½âÎö£º
(1)CHCHCHCHOH+O2CHCHCHCHO+2HO (2)CHCl+HOHCHO+2HCl
|
Ìáʾ£º
(1)´¼±»Ñõ»¯ÎªÈ©£¬(2)Ë®½âµÃÈ©£¬(3) 2-¼×»ù-2-±û´¼²»Äܱ»ËáÐÔKMnO4Ñõ»¯
|
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿