ÌâÄ¿ÄÚÈÝ

пÊÇÒ»ÖÖ³£ÓýðÊô£¬ïØ£¨Ga£©µÄ»¯ºÏÎﵪ»¯ïØ£¨GaN£©ÊÇÖÆÔìLEDµÄÖØÒª²ÄÁÏ£¬±»ÓþΪµÚÈý´ú°ëµ¼Ìå²ÄÁÏ¡£

I£®ïØ£¨Ga£©ÊÇ»ð·¨Ò±Á¶Ð¿¹ý³ÌÖеĸ±²úÆ·£¬ïØÓëÂÁͬÖ÷×åÇÒÏàÁÚ£¬»¯Ñ§ÐÔÖÊÓëÂÁÏàËÆ¡£

£¨1£©GaµÄÔ­×ӽṹʾÒâͼΪ___________________£»

£¨2£© GaN¿ÉÓÉGaºÍNH3ÔÚ¸ßÎÂÌõ¼þÏÂÖÆÈ¡£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ_______________¡£

£¨3£©ÏÂÁÐÓйØïغÍïصĻ¯ºÏÎïµÄ˵·¨ÕýÈ·µÄÊÇ____________

A£®³£ÎÂÏ£¬Ga¿ÉÓëË®¾çÁÒ·´Ó¦·Å³öÇâÆø

B£®Ò»¶¨Ìõ¼þÏ£¬Ga¿ÉÈÜÓÚÑÎËáºÍÇâÑõ»¯ÄÆ

C£®Ò»¶¨Ìõ¼þÏ£¬Ga2O3¿ÉÓëNaOH·´Ó¦Éú³ÉÑÎ

D£®Ga2O3¿ÉÓÉGa(OH)3ÊÜÈÈ·Ö½âµÃµ½

II£®Ð¿µÄÒ±Á¶·½·¨Óл𷨺Íʪ·¨¡£¹¤ÒµÉÏÀûÓÃп±ºÉ°£¨Ö÷Òªº¬Zn0¡¢ZnFe2O4£¬»¹º¬ÓÐÉÙÁ¿CaO¡¢FeO¡¢CuO¡¢NiOµÈÑõ»¯Îʪ·¨ÖÆÈ¡½ðÊôпµÄÁ÷³ÌÈçͼËùʾ£º

ÒÑÖª£ºFeµÄ»îÆÃÐÔÇ¿ÓÚNi

£¨4£©ZnFe2O4¿ÉÒÔд³ÉZnO¡¤Fe2O3£¬ZnFe2O4ÓëH2SO4·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____ _¡£

£¨5£©¾»»¯I²Ù×÷·ÖΪÁ½²½£ºµÚÒ»²½Êǽ«ÈÜÒºÖÐÉÙÁ¿µÄFe2+Ñõ»¯£»µÚ¶þ²½ÊÇ¿ØÖÆÈÜÒºpH£¬Ö»Ê¹Fe3+ת»¯ÎªFe(OH)3³Áµí¡£¾»»¯IÉú³ÉµÄ³ÁµíÖл¹º¬ÓÐÈÜÒºÖеÄÐü¸¡ÔÓÖÊ£¬ÈÜÒºÖеÄÐü¸¡ÔÓÖʱ»¹²Í¬³ÁµíµÄÔ­ÒòÊÇ________________________¡£

£¨6£©¾»»¯IIÖмÓÈëZnµÄÄ¿µÄÊÇ_______________________¡£

£¨7£©³£ÎÂÏ£¬¾»»¯IÖУ¬Èç¹ûҪʹc(Fe3+) < 10-5 mol/L£¬ÔòÓ¦¿ØÖÆÈÜÒºpHµÄ·¶Î§Îª_____________¡£ÒÑÖª£ºKsp[Fe(OH)3]=8.0¡Á10-38£»lg5=0.7

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾Ñ¡ÐÞ3£ºÎïÖʽṹÓëÐÔÖÊ¡¿£¨15·Ö£©A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GÊÇÇ°ËÄÖÜÆÚ£¨³ýÏ¡ÓÐÆøÌ壩ԭ×ÓÐòÊýÒÀ´ÎÔö´óµÄÆßÖÖÔªËØ£¬AµÄÔ­×ÓºËÍâµç×ÓÖ»ÓÐÒ»ÖÖÔ˶¯×´Ì¬£»B¡¢CµÄ¼Ûµç×Ó²ãÖÐδ³É¶Ôµç×ÓÊý¶¼ÊÇ2£»B¡¢C¡¢DͬÖÜÆÚ£»EºËÍâµÄs¡¢pÄܼ¶µÄµç×Ó×ÜÊýÏà³ï£»FÓëEͬÖÜÆÚÇÒµÚÒ»µçÀëÄܱÈEС£»GµÄ+1¼ÛÀë×Ó£¨G+£©µÄ¸÷²ãµç×ÓÈ«³äÂú¡£»Ø´ðÏÂÁÐÎÊÌ⣺£¨Ïà¹ØÎÊÌâÓÃÔªËØ·ûºÅ±íʾ£©

£¨1£©Ð´³öEµÄ»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½______________________¡£

£¨2£©BÓëC¿ÉÐγɻ¯ºÏÎïBCºÍBC2£¬BC2ÊôÓÚ__________£¨Ìî¡°¼«ÐÔ¡±¡¢¡°·Ç¼«ÐÔ¡±£©·Ö×Ó£¬1 mol BCº¬ÓЦмüΪ____________mol¡£

£¨3£©ÓÉÔªËØA¡¢C¡¢G×é³ÉµÄÀë×Ó[G£¨A2C£©4]2+ÔÚË®ÈÜÒºÖÐÏÔÌìÀ¶É«£¬²»¿¼ÂÇ¿Õ¼ä½á¹¹£¬[G£¨A2C£©4]2+µÄ½á¹¹¿ÉÓÃʾÒâͼ±íʾΪ__________£¨Åäλ¼üÓáú±ê³ö£©¡£

£¨4£©²â¶¨A¡¢DÐγɵĻ¯ºÏÎïµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ê±£¬ÊµÑé²â¶¨ÖµÒ»°ã¸ßÓÚÀíÂÛÖµµÄÔ­ÒòÊÇ_________________¡£

£¨5£©ÓÉÔªËØA¡¢B¡¢F×é³ÉµÄÔ­×Ó¸öÊý±È9 : 3 : 1µÄÒ»ÖÖÎïÖÊ£¬·Ö×ÓÖк¬Èý¸öÏàͬµÄÔ­×ÓÍÅ£¬Æä½á¹¹¼òʽΪ___________£¬·Ö×ÓÖÐFÔ­×ÓµÄÔÓ»¯·½Ê½Îª__________£¬¸ÃÎïÖÊÓöË®±¬Õ¨£¬Éú³É°×É«³ÁµíºÍÎÞÉ«ÆøÌ壬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________¡£

£¨6£©GÓ뵪ԪËØÐγɵÄijÖÖ»¯ºÏÎïµÄ¾§°û½á¹¹ÈçÓÒͼ£¬Ôò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½Îª__________£¬Èô¾§ÌåÃܶÈΪa g¡¤cm-3£¬ÁÐʽ¼ÆËãGÔ­×ÓÓ뵪ԭ×Ó×î½üµÄ¾àÀëΪ__________pm£¨²»±Ø¼ÆËã³öÊýÖµ£¬°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµÓÃNA±íʾ£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø