ÌâÄ¿ÄÚÈÝ
ÒÑÖªCl2ÔÚ70¡æµÄNaOHË®ÈÜÒºÖУ¬ÄÜͬʱ·¢ÉúÁ½¸ö×ÔÉíÑõ»¯»¹Ô·´Ó¦£¬·´Ó¦ÍêÈ«ºó²âµÃÈÜÒºÖÐNaClOÓëNaClO3µÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1£®ÏÖÓÐ49.7g Cl2£¬½«ÆäͨÈëµ½×ãÁ¿70¡æµÄNaOHË®ÈÜÒºÖУ¬·´Ó¦ÍêÈ«ºóµÃµ½500mLÈÜÒº£®
£¨1£©Ð´³öCl2ÔÚ70¡æµÄNaOHË®ÈÜÒºÖзûºÏÉÏÊöÌõ¼þµÄ×Ü·´Ó¦·½³Ìʽ
£¨2£©¼ÆËãÍêÈ«·´Ó¦ºó Éú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶È£®
£¨1£©Ð´³öCl2ÔÚ70¡æµÄNaOHË®ÈÜÒºÖзûºÏÉÏÊöÌõ¼þµÄ×Ü·´Ó¦·½³Ìʽ
£¨2£©¼ÆËãÍêÈ«·´Ó¦ºó Éú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶È£®
£¨1£©ÔÚ²»Í¬µÄÌõ¼þÏ£¬ÂÈÆøºÍÇâÑõ»¯ÄƵķ´Ó¦Îª£ºCl2+2NaOH=NaClO+NaCl+H2O£¬3Cl2+6NaOH£¨ÈÈ£©=NaClO3+5NaCl+3H2O£¬Cl2ÔÚ70¡æµÄNaOHË®ÈÜÒºÖз´Ó¦ÊÇÉÏÊöÁ½¸ö·´Ó¦µÄ×ۺϹý³Ì£¬½«Á½¸ö·´Ó¦Ïà¼ÓµÃ£º4Cl2+6NaOH=NaClO+NaClO3+6NaCl+4H2O£¬·´Ó¦ÍêÈ«ºó²âµÃÈÜÒºÖÐNaClOÓëNaClO3µÄÎïÖʵÄÁ¿Ö®±ÈΪ4£º1ʱ£¬¶Ô·½³ÌʽÅäƽºóµÃµ½£º7Cl2+14NaOH=4NaClO+NaClO3+9NaCl+7H2O£¬¹Ê´ð°¸Îª£º7Cl2+14NaOH=4NaClO+NaClO3+9NaCl+7H2O£»
£¨2£©ÉèÉú³ÉµÄÂÈËáÄƵÄÎïÖʵÄÁ¿Îªn£¬Ôò
7Cl2+14NaOH=4NaClO+NaClO3+9NaCl+7H2O
7 1
n
¼´
=
½âµÃn=0.1mol
ËùÒÔÉú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶È=
=0.2mol/L
´ð£ºÉú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.2mol/L£®
£¨2£©ÉèÉú³ÉµÄÂÈËáÄƵÄÎïÖʵÄÁ¿Îªn£¬Ôò
7Cl2+14NaOH=4NaClO+NaClO3+9NaCl+7H2O
7 1
49.7g |
71g/mol |
¼´
7 | ||
|
1 |
n |
½âµÃn=0.1mol
ËùÒÔÉú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶È=
0.1mol |
0.5L |
´ð£ºÉú³ÉÎïNaClO3µÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.2mol/L£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿