ÌâÄ¿ÄÚÈÝ

(8·Ö)ÒÑÖª£ºCH3CH2OH+NaBr+H2SO4(Ũ)  CH3CH2Br+NaHSO4 +H2O¡£
ʵÑéÊÒÖƱ¸äåÒÒÍ飨·ÐµãΪ38.4¡æ£©µÄ×°ÖúͲ½ÖèÈçÏ£º

¢Ù°´ÓÒͼËùʾÁ¬½ÓÒÇÆ÷£¬¼ì²é×°ÖõÄÆøÃÜÐÔ£¬È»ºóÏòUÐιܺʹóÉÕ±­Àï¼ÓÈë±ùË®£»¢ÚÔÚÔ²µ×ÉÕÆ¿ÖмÓÈë10mL95£¥ÒÒ´¼¡¢28mLŨÁòËᣬȻºó¼ÓÈëÑÐϸµÄ13gä廯Äƺͼ¸Á£Ëé´ÉƬ£»¢ÛС»ð¼ÓÈÈ£¬Ê¹Æä³ä·Ö·´Ó¦¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
(1)·´Ó¦Ê±Èôζȹý¸ß¿É¿´µ½Óкì×ØÉ«ÆøÌå²úÉú£¬¸ÃÆøÌåµÄ»¯Ñ§Ê½Îª
            ¡£
£¨2£©ÎªÁ˸üºÃµÄ¿ØÖÆ·´Ó¦Î¶ȣ¬³ýÓÃͼʾµÄС»ð¼ÓÈÈ£¬¸üºÃµÄ¼ÓÈÈ·½Ê½ÊÇ__________¡£
(3)·´Ó¦½áÊøºó£¬UÐιÜÖдÖÖƵÄäåÒÒÍé³Ê×Ø»ÆÉ«¡£½«UÐιÜÖеĻìºÏÎïµ¹Èë·ÖҺ©¶·ÖУ¬¾²Ö㬴ýÒºÌå·Ö²ãºó£¬·ÖÒº£¬È¡        (Ìî¡°Éϲ㡱»ò¡°Ï²㡱)ÒºÌ塣ΪÁ˳ýÈ¥ÆäÖеÄÔÓÖÊ£¬¿ÉÑ¡ÔñÏÂÁÐÊÔ¼ÁÖеĠ    (ÌîÐòºÅ)¡£
A£®Na2SO3ÈÜÒºB£®H2OC£®NaOHÈÜÒºD£®CCl4
(4)Òª½øÒ»²½ÖƵô¿¾»µÄC2H5Br£¬¿ÉÔÙÓÃˮϴ£¬È»ºó¼ÓÈëÎÞË®CaCl2¸ÉÔÔÙ½øÐР     (Ìî²Ù×÷Ãû³Æ)¡£
(4)ÏÂÁм¸ÏîʵÑé²½Ö裬¿ÉÓÃÓÚ¼ìÑéäåÒÒÍéÖеÄäåÔªËØ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£ºÈ¡ÉÙÁ¿äåÒÒÍ飬Ȼºó              (ÌîÐòºÅ)¡£
¢Ù¼ÓÈÈ  ¢Ú¼ÓÈëAgNO3ÈÜÒº  ¢Û¼ÓÈëÏ¡HNO3Ëữ  ¢Ü¼ÓÈëNaOHÈÜÒº  ¢ÝÀäÈ´
£¨7·Ö£©£¨1£©Br2          £¨2£©Ë®Ô¡¼ÓÈÈ
£¨3£©Ï²㣬A         £¨4£©ÕôÁó
£¨5£©¢Ü¢Ù¢Ý¢Û¢Ú£¨2·Ö£©
£¨1£©ÓÉÓÚŨÁòËá¾ßÓÐÑõ»¯ÐÔ£¬ÄÜÑõ»¯ä廯ÇâÉú³Éµ¥ÖÊä壬äåÕôÆûÊǺì×ØÉ«µÄ¡£
£¨2£©Ë®Ô¡¼ÓÈÈÒ×ÓÚ¿É֪ζȣ¬ËùÒÔÓ¦¸ÃÓÃˮԡ¼ÓÈÈ¡£
£¨3£©äåÒÒÍéµÄÃܶȴóÓÚË®µÄ£¬ËùÒÔȡϲãÒºÌå¡£äåÒÒÍéÖк¬Óе¥ÖÊä壬¿ÉÒÔÓÃÑÇÁòËáÄÆ»¹Ô­µ¥ÖÊäåÀ´³ýÈ¥¡£ÓÉÓÚÇâÑõ»¯ÄÆÄܺÍäåÒÒÍé·´Ó¦£¬ËùÒÔÕýÈ·µÄ´ð°¸Ñ¡A¡£
£¨4£©äåÒÒÍéÊôÓÚÓлúÎ²»ÄÜÈÜÓÚÎÞ»úÑÎÖУ¬ÕôÁó¼´¿É¡£
£¨5£©äåÒÒÍé²»ÄܵçÀë³öäåÀë×Ó£¬Òò´ËÐèÒªÏÈͨ¹ýË®½â²úÉúäåÀë×Ó£¬È»ºóÔÚ¼ÓÈëÏõËáÒøÈÜÒº¡£µ«ÓÉÓÚäåÒÒÍéË®½âÔÚ¼îÐÔÌõ¼þϽøÐУ¬¶ø¼ìÑéäåÀë×ÓÊÇÔÚËáÐÔÌõ¼þϽøÐеģ¬ËùÒÔÕýÈ·µÄ˳ÐòÊǢܢ٢ݢۢڡ£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø