ÌâÄ¿ÄÚÈÝ
ijѧÉúΪ¼ìÑéŨÁòËáÓëľ̿ÔÚ¼ÓÈÈÌõ¼þÏ·´Ó¦²úÉúSO2ºÍCO2ÆøÌ壬Éè¼ÆÁËÈçÏÂͼËùʾµÄʵÑé×°Öã¬a¡¢b¡¢cΪֹˮ¼Ð£¬BÊÇÓÃÓÚ´¢ÆøµÄÆøÄÒ£¬DÖзÅÓÐÓÃI2ºÍµí·ÛµÄÀ¶É«ÈÜÒº½þʪµÄÍÑÖ¬ÃÞ¡£Çë»Ø´ðÏÂÁÐÎÊÌâ
£¨1£©Ð´³öŨÁòËáÓëľ̿ÔÚ¼ÓÈÈÌõ¼þÏ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º______________________¡£
£¨2£©´ËʵÑé³É°ÜµÄ¹Ø¼üÔÚÓÚ¿ØÖÆ·´Ó¦²úÉúÆøÌåµÄËÙÂʲ»Äܹý¿ì£¬ÓÉ´ËÉè¼ÆÁËÐé¿ò²¿·ÖµÄ×°Öã¬ÔòÕýÈ·µÄ²Ù×÷˳ÐòÊÇ________________£¨ÓòÙ×÷±àºÅÌîд£©£»¡¡¡¡
¢ÙÏòA×°ÖÃÖмÓÈëŨÁòËᣬ¼ÓÈÈ£¬Ê¹AÖÐ ²úÉúµÄÆøÌå½øÈëÆøÄÒB£¬µ±ÆøÄÒÖгäÈëÒ»¶¨Á¿ÆøÌåʱ£¬Í£Ö¹¼ÓÈÈ£»
¢Ú´ý×°ÖÃAÀäÈ´£¬ÇÒÆøÄÒBµÄÌå»ý²»Ôٱ仯ºó£¬¹Ø±Õֹˮ¼Ða£¬´ò¿ªÖ¹Ë®¼Ðb£¬ÂýÂý¼·Ñ¹ÆøÄÒ£¬Ê¹ÆøÄÒBÖÐÆøÌåÂýÂý½øÈë×°ÖÃCÖУ¬´ý´ïµ½ÊµÑéÄ¿µÄºó£¬¹Ø±Õֹˮ¼Ðb£»
¢Û´ò¿ªÖ¹Ë®¼ÐaºÍc£¬¹Ø±Õֹˮ¼Ðb£»
£¨3£©ÊµÑéʱ£¬×°ÖÃCÖеÄÏÖÏóΪ________________________________________¡£¡¡¡¡
£¨4£©µ±×°ÖÃDÖвúÉú__________£¨ÌîÑ¡Ï¶àÑ¡²»µÃ·Ö£©ÏÖÏóʱ£¬¿ÉÒÔ˵Ã÷ʹװÖÃEÖгÎÇåʯ»ÒË®±ä»ë×ǵÄÊÇCO2£¬¶ø²»ÊÇSO2£»¡¡
A£®½øÆø¿ÚÒ»¶ËÍÑÖ¬ÃÞÉÏÀ¶É«±ädz£¬³öÆø¿ÚÒ»¶ËÍÑÖ¬ÃÞÉÏÀ¶É«²»±ä
B£®ÍÑÖ¬ÃÞÉÏÀ¶É«¾ù±ädz
C£®ÍÑÖ¬ÃÞÉϵÄÀ¶É«ÍêÈ«ÍÊÈ¥
D£®ÍÑÖ¬ÃÞÉϵÄÀ¶É«²»±ä
×°ÖÃD Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ£º_________________________________¡£
£¨2£©´ËʵÑé³É°ÜµÄ¹Ø¼üÔÚÓÚ¿ØÖÆ·´Ó¦²úÉúÆøÌåµÄËÙÂʲ»Äܹý¿ì£¬ÓÉ´ËÉè¼ÆÁËÐé¿ò²¿·ÖµÄ×°Öã¬ÔòÕýÈ·µÄ²Ù×÷˳ÐòÊÇ________________£¨ÓòÙ×÷±àºÅÌîд£©£»¡¡¡¡
¢ÙÏòA×°ÖÃÖмÓÈëŨÁòËᣬ¼ÓÈÈ£¬Ê¹AÖÐ ²úÉúµÄÆøÌå½øÈëÆøÄÒB£¬µ±ÆøÄÒÖгäÈëÒ»¶¨Á¿ÆøÌåʱ£¬Í£Ö¹¼ÓÈÈ£»
¢Ú´ý×°ÖÃAÀäÈ´£¬ÇÒÆøÄÒBµÄÌå»ý²»Ôٱ仯ºó£¬¹Ø±Õֹˮ¼Ða£¬´ò¿ªÖ¹Ë®¼Ðb£¬ÂýÂý¼·Ñ¹ÆøÄÒ£¬Ê¹ÆøÄÒBÖÐÆøÌåÂýÂý½øÈë×°ÖÃCÖУ¬´ý´ïµ½ÊµÑéÄ¿µÄºó£¬¹Ø±Õֹˮ¼Ðb£»
¢Û´ò¿ªÖ¹Ë®¼ÐaºÍc£¬¹Ø±Õֹˮ¼Ðb£»
£¨3£©ÊµÑéʱ£¬×°ÖÃCÖеÄÏÖÏóΪ________________________________________¡£¡¡¡¡
£¨4£©µ±×°ÖÃDÖвúÉú__________£¨ÌîÑ¡Ï¶àÑ¡²»µÃ·Ö£©ÏÖÏóʱ£¬¿ÉÒÔ˵Ã÷ʹװÖÃEÖгÎÇåʯ»ÒË®±ä»ë×ǵÄÊÇCO2£¬¶ø²»ÊÇSO2£»¡¡
A£®½øÆø¿ÚÒ»¶ËÍÑÖ¬ÃÞÉÏÀ¶É«±ädz£¬³öÆø¿ÚÒ»¶ËÍÑÖ¬ÃÞÉÏÀ¶É«²»±ä
B£®ÍÑÖ¬ÃÞÉÏÀ¶É«¾ù±ädz
C£®ÍÑÖ¬ÃÞÉϵÄÀ¶É«ÍêÈ«ÍÊÈ¥
D£®ÍÑÖ¬ÃÞÉϵÄÀ¶É«²»±ä
×°ÖÃD Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ£º_________________________________¡£
£¨1£©2H2SO4(Ũ)+C2SO2¡ü+CO2¡ü+2H2O
£¨2£©¢Û¢Ù¢Ú
£¨3£©Æ·ºìÈÜÒºÍÊÉ«
£¨4£©AD£»SO2+I2+2H2O=4H++2I-+SO42-
£¨2£©¢Û¢Ù¢Ú
£¨3£©Æ·ºìÈÜÒºÍÊÉ«
£¨4£©AD£»SO2+I2+2H2O=4H++2I-+SO42-
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿