ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©

I£®ÎÒ¹ú¼´½«½¨³É×Ô¼ºµÄÔØÈË¿Õ¼äÕ¾¡£ÔØÈ˺½ÌìÆ÷µÄÉú̬ϵͳÖУ¬²»½öÒªÇó·ÖÀëÈ¥³ýCO2£¬»¹ÒªÇóÌṩ³ä×ãµÄO2¡£

¢ÅijÖֵ绯ѧװÖÿÉʵÏÖÈçÏÂת»¯£º2CO2=2CO+O2£¬CO¿ÉÓÃ×÷ȼÁÏ¡£ÒÑÖª¸Ã·´Ó¦µÄij¼«·´Ó¦Îª£º4OH-£­4e-=O2¡ü+2H2O£¬ÔòÁíÒ»¼«·´Ó¦Îª£º           ¡£

¢ÆÓÐÈËÌá³ö£¬¿ÉÒÔÉè¼ÆijζÈϵķ´Ó¦£º2CO=2C+O2£¨¡÷H>O¡¢¡÷S<O£©À´Ïû³ýCOµÄÎÛȾ¡£ÇëÄãÅжϸÃζÈÏÂÉÏÊö·´Ó¦ÊÇ·ñÄÜ·¢Éú²¢ËµÃ÷ÀíÓÉÊÇ                ¡£

¢ò.´óÆø¹ÌµªÊôÓÚ×ÔÈ»¹Ìµª£¬ºÏ³É°±ÊÇÄ¿Ç°È˹¤¹ÌµªµÄÖ÷Òª·½·¨¡£¿Æѧ¼ÒÒ»Ö±ÖÂÁ¦¡°È˹¤¹Ìµª¡±Ð·½·¨µÄÑо¿¡£

¢ÅÓйشóÆø¹Ìµª(ÒÔN2+O  2NOΪÀý)¡¢È˹¤¹Ìµª(ÒÔN2+3H2  2NH3ΪÀý)·´Ó¦µÄƽºâ³£ÊýµÄÖµÈçÏÂ±í¡£

·´Ó¦

N2+02 2NO        

N2+3H22NH3

ζÈ/¡æ

 27

2000

100

400

K

 3.84¡Á10-31

 0.1

3.4¡Á109

2.0x104

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ           ¡£(Ìî×Öĸ)

a£®´óÆø¹ÌµªÓëÈ˹¤¹Ìµª¶¼ÊÇ·ÅÈÈ·´Ó¦

b£®ÈËÀàÄ£Äâ´óÆø¹ÌµªÎÞÏÖʵÒâÒå

c£®Ñ°ÕÒÔÚ³£ÎÂϺϳɰ±µÄ¸ßЧ´ß»¯¼ÁÊÇÄ¿Ç°È˹¤¹ÌµªµÄз½Ïò

d£®ÔÚ³£ÎÂÏ£¬È˹¤¹Ìµª·Ç³£ÈÝÒ×½øÐÐ

¢ÆÒÑÖª£ºN2(g)+3H2(g)  2NH3(g)     =-92.4kJ¡¤mol-1

2H2(g)+02(g)=2H20(1)        =-571.6 kJ¡¤mol-1

¾Ý±¨µÀ£¬ÔÚ³£Î¡¢³£Ñ¹¡¢¹âÕÕ¡¢´ß»¯¼ÁµÄÌõ¼þÏ£¬N2¿ÉÒÔÓëË®·´Ó¦£¬Ôò·´Ó¦ N2(g)+3H20(1)=2NH3(g)+3£¯2O2(g)µÄ=           KJ¡¤mol-1¡£

¢ÇijÑо¿Ð¡×éÔÚ673 K¡¢30 MPaÏ£¬ÔÚÌå»ýΪµÄÃܱÕÈÝÆ÷ÖнøÐз´Ó¦£ºN2(g)+3H2(g) 2NH3(g)£¬Æä(H2)ºÍ (NH3)Ëæʱ¼ä±ä»¯µÄ¹ØϵÈçͼËùʾ¡£

¢ÙÏÂÁÐÐðÊöÕýÈ·µÄÊÇ           ¡£(Ìî×Öĸ)

  A£®µãaµÄÕý·´Ó¦ËÙÂʱȵãbµÄ´ó

B£®µãc´¦·´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬

C£®Èôt3ʱÓÉ673KÉýÖÁ773 K£¬Ôò (H2)½«Ôö´ó

¢Ú´Ó¿ªÊ¼µ½Æ½ºâʱ·´Ó¦µÄƽ¾ùËÙÂÊ(ÒÔH2µÄŨ¶È±ä»¯±íʾ) (H2)=              ¡£

¢ÛÈô¿ªÊ¼Ê± (N2)= (H2)£¬Ôò·´Ó¦µÄƽºâ³£Êý=            (ÓôúÊýʽ±íʾ)¡£

 

14·ÖI£®£¨1£©2CO2+4e-+2H2O=2CO+4OH-   £¨2£©²»ÄÜ£¬ÕâÊǸöìÊÔöìؼõµÄ±ä»¯

¢ò.£¨1£©bc £¨2£©+765.0 kJ¡¤mol-1 £¨3£©¢Ù AC ¢Ú 3n2/(2Vt2) mol/(L¡¤s)

¢Û n22V2/[(n3-n2/2)¡Á(n3-3n2/2)3]

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨14·Ö£©

I£®ÎÒ¹ú¼´½«½¨³É×Ô¼ºµÄÔØÈË¿Õ¼äÕ¾¡£ÔØÈ˺½ÌìÆ÷µÄÉú̬ϵͳÖУ¬²»½öÒªÇó·ÖÀëÈ¥³ýCO2£¬»¹ÒªÇóÌṩ³ä×ãµÄO2¡£
¢ÅijÖֵ绯ѧװÖÿÉʵÏÖÈçÏÂת»¯£º2CO2=2CO+O2£¬CO¿ÉÓÃ×÷ȼÁÏ¡£ÒÑÖª¸Ã·´Ó¦µÄij¼«·´Ó¦Îª£º4OH-£­4e-=O2¡ü+2H2O£¬ÔòÁíÒ»¼«·´Ó¦Îª£º           ¡£
¢ÆÓÐÈËÌá³ö£¬¿ÉÒÔÉè¼ÆijζÈϵķ´Ó¦£º2CO=2C+O2£¨¡÷H>O¡¢¡÷S<O£©À´Ïû³ýCOµÄÎÛȾ¡£ÇëÄãÅжϸÃζÈÏÂÉÏÊö·´Ó¦ÊÇ·ñÄÜ·¢Éú²¢ËµÃ÷ÀíÓÉÊÇ                ¡£
¢ò.´óÆø¹ÌµªÊôÓÚ×ÔÈ»¹Ìµª£¬ºÏ³É°±ÊÇÄ¿Ç°È˹¤¹ÌµªµÄÖ÷Òª·½·¨¡£¿Æѧ¼ÒÒ»Ö±ÖÂÁ¦¡°È˹¤¹Ìµª¡±Ð·½·¨µÄÑо¿¡£
¢ÅÓйشóÆø¹Ìµª(ÒÔN2+O  2NOΪÀý)¡¢È˹¤¹Ìµª(ÒÔN2+3H2 2NH3ΪÀý)·´Ó¦µÄƽºâ³£ÊýµÄÖµÈçÏÂ±í¡£

·´Ó¦
N2+02 2NO        
N2+3H22NH3
ζÈ/¡æ
 27
2000
100
400
K
 3.84¡Á10-31
 0.1
3.4¡Á109
2.0x104
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ           ¡£(Ìî×Öĸ)
a£®´óÆø¹ÌµªÓëÈ˹¤¹Ìµª¶¼ÊÇ·ÅÈÈ·´Ó¦
b£®ÈËÀàÄ£Äâ´óÆø¹ÌµªÎÞÏÖʵÒâÒå
c£®Ñ°ÕÒÔÚ³£ÎÂϺϳɰ±µÄ¸ßЧ´ß»¯¼ÁÊÇÄ¿Ç°È˹¤¹ÌµªµÄз½Ïò
d£®ÔÚ³£ÎÂÏ£¬È˹¤¹Ìµª·Ç³£ÈÝÒ×½øÐÐ
¢ÆÒÑÖª£ºN2(g)+3H2(g)  2NH3(g)    =-92.4kJ¡¤mol-1
2H2(g)+02(g)="2H20(1)        " ="-571.6" kJ¡¤mol-1
¾Ý±¨µÀ£¬ÔÚ³£Î¡¢³£Ñ¹¡¢¹âÕÕ¡¢´ß»¯¼ÁµÄÌõ¼þÏ£¬N2¿ÉÒÔÓëË®·´Ó¦£¬Ôò·´Ó¦ N2(g)+3H20(1)=2NH3(g)+3£¯2O2(g)µÄ=          KJ¡¤mol-1¡£
¢ÇijÑо¿Ð¡×éÔÚ673 K¡¢30 MPaÏ£¬ÔÚÌå»ýΪµÄÃܱÕÈÝÆ÷ÖнøÐз´Ó¦£ºN2(g)+3H2(g) 2NH3(g)£¬Æä(H2)ºÍ(NH3)Ëæʱ¼ä±ä»¯µÄ¹ØϵÈçͼËùʾ¡£

¢ÙÏÂÁÐÐðÊöÕýÈ·µÄÊÇ           ¡£(Ìî×Öĸ)
A£®µãaµÄÕý·´Ó¦ËÙÂʱȵãbµÄ´ó
B£®µãc´¦·´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬
C£®Èôt3ʱÓÉ673 KÉýÖÁ773 K£¬Ôò(H2)½«Ôö´ó
¢Ú´Ó¿ªÊ¼µ½Æ½ºâʱ·´Ó¦µÄƽ¾ùËÙÂÊ(ÒÔH2µÄŨ¶È±ä»¯±íʾ)(H2)=              ¡£
¢ÛÈô¿ªÊ¼Ê±(N2)=(H2)£¬Ôò·´Ó¦µÄƽºâ³£Êý=            (ÓôúÊýʽ±íʾ)¡£

£¨14·Ö£©

I£®ÎÒ¹ú¼´½«½¨³É×Ô¼ºµÄÔØÈË¿Õ¼äÕ¾¡£ÔØÈ˺½ÌìÆ÷µÄÉú̬ϵͳÖУ¬²»½öÒªÇó·ÖÀëÈ¥³ýCO2£¬»¹ÒªÇóÌṩ³ä×ãµÄO2¡£

¢ÅijÖֵ绯ѧװÖÿÉʵÏÖÈçÏÂת»¯£º2CO2=2CO+O2£¬CO¿ÉÓÃ×÷ȼÁÏ¡£ÒÑÖª¸Ã·´Ó¦µÄij¼«·´Ó¦Îª£º4OH-£­4e-=O2¡ü+2H2O£¬ÔòÁíÒ»¼«·´Ó¦Îª£º            ¡£

¢ÆÓÐÈËÌá³ö£¬¿ÉÒÔÉè¼ÆijζÈϵķ´Ó¦£º2CO=2C+O2£¨¡÷H>O¡¢¡÷S<O£©À´Ïû³ýCOµÄÎÛȾ¡£ÇëÄãÅжϸÃζÈÏÂÉÏÊö·´Ó¦ÊÇ·ñÄÜ·¢Éú²¢ËµÃ÷ÀíÓÉÊÇ                 ¡£

¢ò.´óÆø¹ÌµªÊôÓÚ×ÔÈ»¹Ìµª£¬ºÏ³É°±ÊÇÄ¿Ç°È˹¤¹ÌµªµÄÖ÷Òª·½·¨¡£¿Æѧ¼ÒÒ»Ö±ÖÂÁ¦¡°È˹¤¹Ìµª¡±Ð·½·¨µÄÑо¿¡£

¢ÅÓйشóÆø¹Ìµª(ÒÔN2+O  2NOΪÀý)¡¢È˹¤¹Ìµª(ÒÔN2+3H2  2NH3ΪÀý)·´Ó¦µÄƽºâ³£ÊýµÄÖµÈçÏÂ±í¡£

·´Ó¦

N2+02 2NO        

N2+3H22NH3

ζÈ/¡æ

 27

2000

100

400

K

 3.84¡Á10-31

 0.1

3.4¡Á109

2.0x104

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ            ¡£(Ìî×Öĸ)

a£®´óÆø¹ÌµªÓëÈ˹¤¹Ìµª¶¼ÊÇ·ÅÈÈ·´Ó¦

b£®ÈËÀàÄ£Äâ´óÆø¹ÌµªÎÞÏÖʵÒâÒå

c£®Ñ°ÕÒÔÚ³£ÎÂϺϳɰ±µÄ¸ßЧ´ß»¯¼ÁÊÇÄ¿Ç°È˹¤¹ÌµªµÄз½Ïò

d£®ÔÚ³£ÎÂÏ£¬È˹¤¹Ìµª·Ç³£ÈÝÒ×½øÐÐ

¢ÆÒÑÖª£ºN2(g)+3H2(g)  2NH3(g)     =-92.4kJ¡¤mol-1

2H2(g)+02(g)=2H20(1)         =-571.6 kJ¡¤mol-1

¾Ý±¨µÀ£¬ÔÚ³£Î¡¢³£Ñ¹¡¢¹âÕÕ¡¢´ß»¯¼ÁµÄÌõ¼þÏ£¬N2¿ÉÒÔÓëË®·´Ó¦£¬Ôò·´Ó¦ N2(g)+3H20(1)=2NH3(g)+3£¯2O2(g)µÄ=           KJ¡¤mol-1¡£

¢ÇijÑо¿Ð¡×éÔÚ673 K¡¢30 MPaÏ£¬ÔÚÌå»ýΪµÄÃܱÕÈÝÆ÷ÖнøÐз´Ó¦£ºN2(g)+3H2(g) 2NH3(g)£¬Æä (H2)ºÍ (NH3)Ëæʱ¼ä±ä»¯µÄ¹ØϵÈçͼËùʾ¡£

¢ÙÏÂÁÐÐðÊöÕýÈ·µÄÊÇ            ¡£(Ìî×Öĸ)

  A£®µãaµÄÕý·´Ó¦ËÙÂʱȵãbµÄ´ó

B£®µãc´¦·´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬

C£®Èôt3ʱÓÉ673 KÉýÖÁ773 K£¬Ôò (H2)½«Ôö´ó

¢Ú´Ó¿ªÊ¼µ½Æ½ºâʱ·´Ó¦µÄƽ¾ùËÙÂÊ(ÒÔH2µÄŨ¶È±ä»¯±íʾ) (H2)=               ¡£

¢ÛÈô¿ªÊ¼Ê± (N2)= (H2)£¬Ôò·´Ó¦µÄƽºâ³£Êý=             (ÓôúÊýʽ±íʾ)¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø