ÌâÄ¿ÄÚÈÝ
(15·Ö)ij¹¤Òµ·ÏË®Öнöº¬Ï±íÀë×ÓÖеÄ5ÖÖ£¨²»¿¼ÂÇË®µÄµçÀë¼°Àë×ÓµÄË®½â£©£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1mol/L¡£
ÑôÀë×Ó | K+ Cu2+ Fe3+ Al3+ Fe2+ |
ÒõÀë×Ó | Cl- CO32- NO3- SO42- SiO32- |
¢ñ£®Óò¬Ë¿ÕºÈ¡ÉÙÁ¿ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬ÎÞ×ÏÉ«»ðÑ棨͸¹ýÀ¶É«îܲ£Á§¹Û²ì£©¡£
¢ò£®È¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëKSCNÈÜÒºÎÞÃ÷ÏԱ仯¡£
¢ó£®ÁíÈ¡ÈÜÒº¼ÓÈëÉÙÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«£¬´ËʱÈÜÒºÒÀÈ»³ÎÇ壬ÇÒÈÜÒºÖÐÒõÀë×ÓÖÖÀ಻±ä¡£
¢ô£®Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÇëÍƶϣº
£¨1£©ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ £¨Ð´Àë×Ó·ûºÅ£©¡£
£¨2£©¢óÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄµÄÀë×Ó·½³ÌʽÊÇ_________________________¡£
£¨3£©½«¢óÖÐËùµÃºì×ØÉ«ÆøÌåͨÈëË®ÖУ¬ÆøÌå±äÎÞÉ«£¬Ëù·¢ÉúµÄ»¯Ñ§·½³ÌʽΪ
_______________________________________________________________
£¨4£©¼×ͬѧ×îÖÕÈ·¶¨ÔÈÜÒºÖÐËùº¬ÑôÀë×ÓÊÇ £¬ÒõÀë×ÓÊÇ ¡££¨Ð´Àë×Ó·ûºÅ£©
£¨5£©ÁíÈ¡100mLÔÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª g¡£
£¨6£©¹¤Òµ·ÏË®Öг£º¬Óв»Í¬ÀàÐ͵ÄÎÛȾÎ¿É²ÉÓò»Í¬µÄ·½·¨´¦Àí¡£ÒÔÏÂÊÇÒÒͬѧÕë¶Ôº¬²»Í¬ÎÛȾÎïµÄ·ÏË®Ìá³öµÄ´¦Àí´ëÊ©ºÍ·½·¨£¬ÆäÖÐÕýÈ·µÄÊÇ
Ñ¡Ïî | ÎÛȾÎï | ´¦Àí´ëÊ© | ·½·¨Àà±ð |
A | ·ÏËá | ¼ÓÉúʯ»ÒÖÐºÍ | ÎïÀí·¨ |
B | Cu2+µÈÖؽðÊôÀë×Ó | ¼ÓÁòËáÑγÁ½µ | »¯Ñ§·¨ |
C | º¬¸´ÔÓÓлúÎïµÄ·ÏË® | ͨ¹ý΢ÉúÎï´úл | ÎïÀí·¨ |
D | ¼îÐԵķÏË® | ÓÃCO2À´ÖÐºÍ | »¯Ñ§·¨ |
£¨1£©K+ Fe3+ £¨2·Ö£©£¨2£©3Fe2+ + NO3- + 4H+ 3Fe3+ + NO + 2H2O£¨2·Ö£©
£¨3£©3NO2+H2O2HNO3+NO £¨2·Ö£©
(4) Fe2+ Cu2+ £¨2·Ö£© Cl- NO3- SO42-£¨3·Ö£©
£¨5£©1.6g £¨2·Ö£© £¨6£©D£¨2·Ö£©
½âÎö
(15·Ö)ij¹¤Òµ·ÏË®Öнöº¬Ï±íÀë×ÓÖеÄ5ÖÖ£¨²»¿¼ÂÇË®µÄµçÀë¼°Àë×ÓµÄË®½â£©£¬ÇÒ¸÷ÖÖÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈÏàµÈ£¬¾ùΪ0.1mol/L¡£
ÑôÀë×Ó |
K+ Cu2+ Fe3+ Al3+ Fe2+ |
ÒõÀë×Ó |
Cl- CO32- NO3- SO42- SiO32- |
¼×ͬѧÓû̽¾¿·ÏË®µÄ×é³É£¬½øÐÐÁËÈçÏÂʵÑ飺
¢ñ£®Óò¬Ë¿ÕºÈ¡ÉÙÁ¿ÈÜÒº£¬ÔÚ»ðÑæÉÏ×ÆÉÕ£¬ÎÞ×ÏÉ«»ðÑ棨͸¹ýÀ¶É«îܲ£Á§¹Û²ì£©¡£
¢ò£®È¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëKSCNÈÜÒºÎÞÃ÷ÏԱ仯¡£
¢ó£®ÁíÈ¡ÈÜÒº¼ÓÈëÉÙÁ¿ÑÎËᣬÓÐÎÞÉ«ÆøÌåÉú³É£¬¸ÃÎÞÉ«ÆøÌåÓö¿ÕÆø±ä³Éºì×ØÉ«£¬´ËʱÈÜÒºÒÀÈ»³ÎÇ壬ÇÒÈÜÒºÖÐÒõÀë×ÓÖÖÀ಻±ä¡£
¢ô£® Ïò¢óÖÐËùµÃµÄÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÇëÍƶϣº
£¨1£©ÓÉ¢ñ¡¢¢òÅжϣ¬ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ £¨Ð´Àë×Ó·ûºÅ£©¡£
£¨2£©¢óÖмÓÈëÉÙÁ¿ÑÎËáÉú³ÉÎÞÉ«ÆøÌåµÄµÄÀë×Ó·½³ÌʽÊÇ_________________________¡£
£¨3£©½«¢óÖÐËùµÃºì×ØÉ«ÆøÌåͨÈëË®ÖУ¬ÆøÌå±äÎÞÉ«£¬Ëù·¢ÉúµÄ»¯Ñ§·½³ÌʽΪ
_______________________________________________________________
£¨4£©¼×ͬѧ×îÖÕÈ·¶¨ÔÈÜÒºÖÐËùº¬ÑôÀë×ÓÊÇ £¬ÒõÀë×ÓÊÇ ¡££¨Ð´Àë×Ó·ûºÅ£©
£¨5£©ÁíÈ¡100mLÔÈÜÒº£¬¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬³ä·Ö·´Ó¦ºó¹ýÂË£¬Ï´µÓ£¬×ÆÉÕÖÁºãÖØ£¬µÃµ½µÄ¹ÌÌåÖÊÁ¿Îª g¡£
£¨6£©¹¤Òµ·ÏË®Öг£º¬Óв»Í¬ÀàÐ͵ÄÎÛȾÎ¿É²ÉÓò»Í¬µÄ·½·¨´¦Àí¡£ÒÔÏÂÊÇÒÒͬѧÕë¶Ôº¬²»Í¬ÎÛȾÎïµÄ·ÏË®Ìá³öµÄ´¦Àí´ëÊ©ºÍ·½·¨£¬ÆäÖÐÕýÈ·µÄÊÇ
Ñ¡Ïî |
ÎÛȾÎï |
´¦Àí´ëÊ© |
·½·¨Àà±ð |
A |
·ÏËá |
¼ÓÉúʯ»ÒÖÐºÍ |
ÎïÀí·¨ |
B |
Cu2+µÈÖؽðÊôÀë×Ó |
¼ÓÁòËáÑγÁ½µ |
»¯Ñ§·¨ |
C |
º¬¸´ÔÓÓлúÎïµÄ·ÏË® |
ͨ¹ý΢ÉúÎï´úл |
ÎïÀí·¨ |
D |
¼îÐԵķÏË® |
ÓÃCO2À´ÖÐºÍ |
»¯Ñ§·¨ |