ÌâÄ¿ÄÚÈÝ

ÓÉÁ×ËáÐγɵÄÁ×Ö¬¼°Æä»¯ºÏÎï(Èçø)ÊÇϸ°ûµÄÖØÒª×é³É²¿·Ö£¬¶Ôµ÷½ÚÉúÃü»î¶¯Æð»ý¼«µÄ×÷Óã¬Á×ËáßÁÈ©ËØ(½á¹¹ÈçÏÂ)ÄÜÓÐЧµØ´Ù½øÖ²Îï¶ÔµªµÄÎüÊÕ¡£

ÊÔÍê³ÉÏÂÁÐÎÊÌ⣺

(1)Á×ËáßÁÈ©ËØ·Ö×ÓʽΪ____________¡£

(2)Á×ËáßÁÈ©ËØ¾ßÓеÄÐÔÖÊÊÇ____________¡£

A.ÄÜÓë½ðÊôÄÆ·´Ó¦                            B.ÄÜ·¢ÉúÒø¾µ·´Ó¦

C.ÄÜÓëFeCl3ÈÜÒº·´Ó¦                         D.ÄÜ·¢Éú¼Ó³É·´Ó¦

E.ÄÜÓëÒÒËá·¢Éúõ¥»¯·´Ó¦                       F.ÄÜ·¢ÉúË®½â·´Ó¦

(3)1 molÁ×ËáßÁÈ©ËØÄÜÓë____________mol NaOH·´Ó¦£¬ÊÔд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡£

(1)C8H10O6NP  (2)ABDEF

  +4NaOHNa3PO4+


½âÎö:

Á×ËáßÁÈ©ËØ·Ö×ÓÖоßÓÐÈ©»ù¡¢´¼ôÇ»ù¡¢õ¥»ù¡¢ÎÞ»úËáµÈ½á¹¹£¬¸ù¾Ý½á¹¹¾ö¶¨ÐÔÖÊ£¬¿ÉÈ·¶¨¸ÃÎïÖʾßÓеÄÐÔÖÊΪA¡¢B¡¢D¡¢E¡¢F¡£1 mol Á×ËáßÁÈ©ËØË®½âÄÜÉú³É1 mol H3PO4ºÍ1 molº¬Ò»¸ö·ÓôÇ»ùµÄÓлúÎ¹ÊÄÜÓë4 mol NaOH·´Ó¦¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø