ÌâÄ¿ÄÚÈÝ

¼×ÈÜÒº¿ÉÄܺ¬ÓС¢¡¢¡¢¡¢¡¢¡¢¡¢°ËÖÖÀë×ÓÖеÄÈô¸ÉÖÖ¡£ÎªÈ·¶¨¼×ÈÜÒºµÄ×é³É£¬½«Æä·Ö³ÉÁ½µÈ·Ý£¬½øÐÐÈçÏÂʵÑ飺
¢ÙÏòÒ»·ÝÈÜÒºÖмÓÈë×ãÁ¿µÄŨÈÜÒº²¢¼ÓÈÈ£¬²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öÏÂÌå»ýΪ4.48L¡£
¢ÚÏòÁíÒ»·ÝÈÜÒºÖмÓÈë0.6mol/LµÄÈÜÒº500mL£¬Ç¡ºÃ¿ÉÒÔÓëÈÜÒºÖеÄÀë×ÓÍêÈ«·´Ó¦£¬¹ýÂ˵Ã66.3g³Áµí¼°ÂËÒº¡£
¢ÛÏòÉÏÊö³ÁµíÖмÓÈë¹ýÁ¿µÄÑÎËᣬ²úÉúµÄÆøÌåͨÈë×ãÁ¿³ÎÇåµÄʯ»ÒË®ÖУ¬µÃµ½Ò»¶¨Á¿µÄ³ÁµíX¡£
¢ÜÏòÉÏÊöÂËÒºÖмÓÈë1mol/LÈÜÒº650mL£¬Ç¡ºÃ¿ÉÍêÈ«·´Ó¦¡£¾Ý´Ë£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣨ÓÃÏàÓ¦µÄÀë×Ó·ûºÅ±íʾ£©£º
£¨1£©ÉÏÊöʵÑé¢ÛÖеõ½³ÁµíXµÄÖÊÁ¿Îª__________________£»Éú³É³ÁµíXµÄÀë×Ó·½³ÌʽΪ_____________________________________¡£
£¨2£©¼×ÈÜÒºÖÐÒ»¶¨²»´æÔÚµÄÀë×ÓÊÇ______________£»¿ÉÄÜ´æÔÚµÄÀë×ÓÊÇ____________¡£
£¨3£©¼×ÈÜÒºÒ»¶¨´æÔÚµÄÀë×ÓÖУ¬ÎïÖʵÄÁ¿×î´óµÄÀë×ÓÊÇ___________£»ÎïÖʵÄÁ¿×îСµÄÀë×ÓÊÇ_____________£¬´ËÎïÖʵÄÁ¿×îСµÄÀë×ÓÆäÎïÖʵÄÁ¿Îª____________¡£
£¨1£©10g£»
£¨2£©¡¢ £¨3£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ijÎÞÉ«ÈÜÒº£¬ÓÉNa+¡¢Ag+¡¢Ba2+¡¢Al3+¡¢AlO2-¡¢MnO4-¡¢CO32-¡¢SO42-¡¢SiO32-ÖеÄ
Èô¸ÉÖÖ×é³É£¨²»¿¼ÂÇË®µÄµçÀ룩¡£È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ñ.È¡ÊÊÁ¿ÈÜÒº£¬¼ÓÈë¹ýÁ¿µÄÑÎËᣬÓÐÆøÌåÉú³É£¬²¢µÃµ½ÎÞÉ«ÈÜÒº£»
¢ò.ÔÚ¢ñËùµÃÈÜÒºÖмÓÈë¹ýÁ¿µÄNH4HCO3ÈÜÒº£¬ÓÐÆøÌåÉú³É£¬Í¬Ê±Îö³ö°×É«³Áµí¼×£»
¢ó. ÔÚ¢òËùµÃÈÜÒºÖмÓÈë¹ýÁ¿µÄBa(OH)2ÈÜÒº,¼ÓÈÈ,Ò²ÓÐÆøÌåÉú³É£¬Í¬Ê±Îö³ö°×É«³ÁµíÒÒ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÉʵÑé¢ñ¿ÉÖªÔ­ÈÜÒºÖÐÒ»¶¨²»º¬ÓеÄÀë×ÓÊÇ                    £»
Ò»¶¨º¬ÓеÄÀë×ÓÊÇ                        ¡£
£¨2£©ÓÉʵÑé¢ò¿ÉÖªÔ­ÈÜÒºÈÜÒºÖл¹Ò»¶¨º¬ÓеÄÀë×ÓÊÇ                  £»Éú³É¼×µÄÀë×Ó·½³ÌʽΪ                                                     ¡£
£¨3£©ÊµÑé¢óÖÐÉú³É°×É«³ÁµíÒÒµÄÀë×Ó·½³ÌʽΪ                                        
                                       ¡£
Ô­ÈÜÒºÖл¹¿ÉÄÜ´æÔÚµÄÀë×ÓÊÇ      £»¼ìÑé¸ÃÀë×ӵķ½·¨ÊÇ         ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø