ÌâÄ¿ÄÚÈÝ

ÉèË®µÄµçÀëƽºâÇúÏßÈçͼËùʾ
£¨1£©ÈôÒÔAµã±íʾ25¡ãCʱˮÔÚµçÀëƽºâʱµÄÀë×ÓŨ¶È£¬µ±Î¶ÈÉÏÉýµ½100¡ãCʱ£¬Ë®µÄµçÀëƽºâ״̬ΪBµã£¬Ôò´ËʱˮµÄÀë×Ó»ý´Ó_______Ôö¼Óµ½________¡£
£¨2£©½«pH=8µÄBa(OH)2ÈÜÒºÓëpH=5µÄÏ¡ÑÎËá»ìºÏ£¬²¢±£³Ö100¡ãCºãΣ¬Óûʹ»ìºÏÈÜÒºpH=7 £¬ÔòBa(OH)2ÓëÑÎËáµÄÌå»ý±ÈΪ____________¡£
£¨3£©ÒÑÖª20¡ãCʱ±¥ºÍH2SÈÜÒºÖÐc(H2S) = 0.1mol¡¤ L-1£¬H2SÒ»¼¶µçÀë³£ÊýԼΪ1¡Á10-7£¬ ¶þ¼¶µçÀë³£ÊýԼΪ7 ¡Á10-15£¬Ôò´ËʱÈÜÒºÖÐc(H+)=________¡£
£¨1£©10-14 £»10-12 
£¨2£©2£º9
£¨3£©1¡Á10-4mol¡¤L-1
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø