ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©ÊµÑéÊÒÐèÒª0.10 mol/L NaOHÈÜÒº475mLºÍ0.40 mol/L¡£ÁòËáÈÜÒº500 mL¡£¸ù¾ÝÕâÁ½ÖÖÈÜÒºµÄÅäÖÆÇé¿ö»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈçͼËùʾµÄÒÇÆ÷ÖÐÅäÖÆÈÜÒº¿Ï¶¨²»ÐèÒªµÄÊÇ      £¨ÌîÐòºÅ£©£¬ÅäÖÆÉÏÊöÈÜÒº»¹ÐèÓõ½µÄ²£Á§ÒÇÆ÷ÊÇ                      £¨ÌîÒÇÆ÷Ãû³Æ£©¡£
£¨2£©ÈËÃdz£½«ÅäÖƹý³Ì¼òÊöΪÒÔϸ÷²½Ö裺

A£®ÀäÈ´B£®³ÆÁ¿C£®Ï´µÓD£®¶¨ÈÝ E£®Èܽâ F£®Ò¡ÔÈ¡£ G£®ÒÆÒº
ÕýÈ·µÄ²Ù×÷˳ÐòÓ¦ÊÇ                  £¨Ìî¸÷²½ÖèÐòºÅ£©¡£
£¨3£©¼ÆËã¸ÃʵÑéÓÃÍÐÅÌÌìƽ³ÆÈ¡NaOHµÄÖÊÁ¿Îª      g¡£ÔÚʵÑéÖÐÆäËû²Ù×÷¾ùÕýÈ·£¬Èô¶¨ÈÝʱ¸©ÊÓÊӿ̶ÈÏߣ¬¡¢ÔòËùµÃÈÜҺŨ¶È       0.lmol/L£¨Ìî¡°´óÏ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£¬ÏÂͬ£©¡£ÈôÒÆҺʱ£¬ÈÝÁ¿Æ¿ÄÚÒÑÓÐÉÙÐíÕôÁóË®£¬ÔòËùµÃÈÜҺŨ¶È   0.lmol£¯L¡£  
£¨4£©¸ù¾Ý¼ÆËãµÃÖª£¬ËùÐèÖÊÁ¿·ÖÊýA 98%¡¢ÃܶÈΪ1184g/cm3µÄŨÁòËáµÄÌå»ýΪ____mL£¨±£ÁôһλСÊý£©¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø