ÌâÄ¿ÄÚÈÝ

ѧÉúÀûÓÃÏÂͼËùÁÐ×°ÖýøÐС°ÌúÓëË®ÕôÆø·´Ó¦¡±µÄʵÑ飬²¢ÀûÓòúÎï½øÒ»²½ÖÆÈ¡FeCl3¡¤6H2O¾§Ìå¡££¨Í¼Öмгּ°Î²Æø´¦Àí×°ÖþùÒÑÂÔÈ¥£©

(1) »Ø´ðÏÂÁÐÎÊÌ⣺ËùÓÃÌú·ÛÖÐÈôÓÐÔÓÖÊ£¬Óû³ýÈ¥²»´¿Ìú·ÛÖлìÓеÄÂÁ·Û¿ÉÒÔÑ¡ÓõÄÊÔ¼ÁΪ__       __£¨ÌîÐòºÅ£©¡£

A£®Ï¡ÑÎËá       B£®ÇâÑõ»¯ÄÆÈÜÒº     C£®Å¨ÁòËá       D. FeCl3ÈÜÒº

¾­³ýÔÓºóµÄÌú·Û½øÒ»²½¸ÉÔïºó×°Èë·´Ó¦ÈÝÆ÷¡£

£¨2£©·´Ó¦·¢Éúºó×°ÖÃBÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________   ____¡£

D×°ÖõÄ×÷Óãº_______________________.

£¨3£©¸ÃС×éѧÉú°ÑBÖз´Ó¦ºóµÄ²úÎï¼ÓÈë×ãÁ¿µÄÑÎËᣬ¹ýÂË£¬ÓÃÉÏÊöÂËÒºÖÆÈ¡FeCl3¡¤6H2O¾§Ì壬Éè¼ÆÁ÷³ÌÈçÏ£º

¢Ù²½ÖèIÖÐͨÈëCl2µÄ×÷Óà                     

£¨ÌÑõ»¯¼Á£¬»¹Ô­¼Á£¬Ñõ»¯²úÎ»¹Ô­²úÎ

¢ÚΪÁ˼ìÑéijδ֪ÈÜÒºÊÇ·ñÊÇFeCl2ÈÜÒº£¬Í¬Ñ§ÃÇÉè¼ÆÁËÒÔÏÂʵÑé·½°¸¼ÓÒÔÖ¤Ã÷¡£

ÏòÒ»Ö§×°ÓиÃδ֪ÈÜÒºµÄÊÔ¹ÜÖÐÏÈͨÈëÂÈÆø£¬ÔٵμÓKSCNÈÜÒº£¬ÈÜÒº³ÊÏÖºìÉ«£¬Ö¤Ã÷¸Ãδ֪ÈÜÒºÊÇFeCl2ÈÜÒº¡£ÄãÈÏΪ´Ë·½°¸ÊÇ·ñºÏÀí        (ÌºÏÀí¡±»ò¡±²»ºÏÀí¡±)¡£

 

(1)  B

(2)  3Fe + 4H2O Fe3O4+ 4H2   .   ³ýÈ¥H2ÖеÄË®ÕôÆû

£¨3£©¢Ù  Ñõ»¯¼Á       ¢Ú¡¡²»ºÏÀí

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ѧÉúÀûÓÃÏÂͼËùÁÐ×°ÖýøÐС°ÌúÓëË®ÕôÆø·´Ó¦¡±µÄʵÑ飬²¢ÀûÓòúÎï½øÒ»²½ÖÆÈ¡FeCl3?6H2O¾§Ì壮£¨Í¼Öмгּ°Î²Æø´¦Àí×°ÖþùÒÑÂÔÈ¥£©

£¨1£©»Ø´ðÏÂÁÐÎÊÌ⣺ËùÓÃÌú·ÛÖÐÈôÓÐÔÓÖÊ£¬Óû³ýÈ¥²»´¿Ìú·ÛÖлìÓеÄÂÁ·Û¿ÉÒÔÑ¡ÓõÄÊÔ¼ÁΪ
B
B
£¨ÌîÐòºÅ£©£®
A£®Ï¡ÑÎËá   B£®ÇâÑõ»¯ÄÆÈÜÒº     C£®Å¨ÁòËá   D£®FeCl3ÈÜÒº
´Ë²½Éæ¼°·´Ó¦µÄÀë×Ó·½³ÌʽΪ
2Al+2OH-+2H2O=2AlO2-+3H2¡ü
2Al+2OH-+2H2O=2AlO2-+3H2¡ü
£®¾­³ýÔÓºóµÄÌú·Û½øÒ»²½¸ÉÔïºó×°Èë·´Ó¦ÈÝÆ÷£®
£¨2£©·´Ó¦·¢Éúºó×°ÖÃBÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
3Fe+4H2O
 ¸ßΠ
.
 
Fe3O4+4H2
3Fe+4H2O
 ¸ßΠ
.
 
Fe3O4+4H2
£®D×°ÖõÄ×÷Óãº
³ýÈ¥H2ÖеÄË®ÕôÆø
³ýÈ¥H2ÖеÄË®ÕôÆø
£®
£¨3£©¸ÃС×éѧÉú°ÑBÖз´Ó¦ºóµÄ²úÎï¼ÓÈë×ãÁ¿µÄÑÎËᣬ¹ýÂË£¬ÓÃÉÏÊöÂËÒºÖÆÈ¡FeCl3?6H2O¾§Ì壬Éè¼ÆÁ÷³ÌÈçÏ£º
ÂËÒº
Cl2
I
FeCl3
II
FeCl3?6H2O¾§Ìå
¢ÙÓÃÀë×Ó·½³Ìʽ±íʾ²½ÖèIÖÐͨÈëCl2µÄ×÷ÓÃ
 £¨Óõ¥ÏßÇűíʾµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£©
¢ÚΪÁ˼ìÑéijδ֪ÈÜÒºÊÇ·ñÊÇFeCl2ÈÜÒº£¬Í¬Ñ§ÃÇÉè¼ÆÁËÒÔÏÂʵÑé·½°¸¼ÓÒÔÖ¤Ã÷£®
ÏòÒ»Ö§×°ÓиÃδ֪ÈÜÒºµÄÊÔ¹ÜÖÐÏÈͨÈëÂÈÆø£¬ÔٵμÓKSCNÈÜÒº£¬ÈÜÒº³ÊÏÖºìÉ«£¬Ö¤Ã÷¸Ãδ֪ÈÜÒºÊÇFeCl2ÈÜÒº£®ÄãÈÏΪ´Ë·½°¸ÊÇ·ñºÏÀí
²»ºÏÀí
²»ºÏÀí
£¨ÌºÏÀí¡±»ò¡±²»ºÏÀí¡±£©£®

ѧÉúÀûÓÃÏÂͼËùÁÐ×°ÖýøÐС°ÌúÓëË®ÕôÆø·´Ó¦¡±µÄʵÑ飬²¢ÀûÓòúÎï½øÒ»²½ÖÆÈ¡FeCl3¡¤6H2O¾§Ìå¡££¨Í¼Öмгּ°Î²Æø´¦Àí×°ÖþùÒÑÂÔÈ¥£©

(1) »Ø´ðÏÂÁÐÎÊÌ⣺ËùÓÃÌú·ÛÖÐÈôÓÐÔÓÖÊ£¬Óû³ýÈ¥²»´¿Ìú·ÛÖлìÓеÄÂÁ·Û¿ÉÒÔÑ¡ÓõÄÊÔ¼ÁΪ__       __£¨ÌîÐòºÅ£©¡£

A£®Ï¡ÑÎËá   B£®ÇâÑõ»¯ÄÆÈÜÒº    C£®Å¨ÁòËá   D. FeCl3ÈÜÒº

 ´Ë²½Éæ¼°·´Ó¦µÄÀë×Ó·½³ÌʽΪ                       ¡£¾­³ýÔÓºóµÄÌú·Û½øÒ»²½¸ÉÔïºó×°Èë·´Ó¦ÈÝÆ÷¡£

£¨2£©·´Ó¦·¢Éúºó×°ÖÃBÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________   ____¡£

D×°ÖõÄ×÷Óãº________________.

£¨3£©¸ÃС×éѧÉú°ÑBÖз´Ó¦ºóµÄ²úÎï¼ÓÈë×ãÁ¿µÄÑÎËᣬ¹ýÂË£¬ÓÃÉÏÊöÂËÒºÖÆÈ¡FeCl3¡¤6H2O¾§Ì壬Éè¼ÆÁ÷³ÌÈçÏ£º

¢ÙÓÃÀë×Ó·½³Ìʽ±íʾ²½ÖèIÖÐͨÈëCl2µÄ×÷Óà                     (2·Ö)

£¨Óõ¥ÏßÇűíʾµç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿£©

¢ÚΪÁ˼ìÑéijδ֪ÈÜÒºÊÇ·ñÊÇFeCl2ÈÜÒº£¬Í¬Ñ§ÃÇÉè¼ÆÁËÒÔÏÂʵÑé·½°¸¼ÓÒÔÖ¤Ã÷¡£

ÏòÒ»Ö§×°ÓиÃδ֪ÈÜÒºµÄÊÔ¹ÜÖÐÏÈͨÈëÂÈÆø£¬ÔٵμÓKSCNÈÜÒº£¬ÈÜÒº³ÊÏÖºìÉ«£¬Ö¤Ã÷¸Ãδ֪ÈÜÒºÊÇFeCl2ÈÜÒº¡£ÄãÈÏΪ´Ë·½°¸ÊÇ·ñºÏÀí        (ÌºÏÀí¡±»ò¡±²»ºÏÀí¡±)¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø