ÌâÄ¿ÄÚÈÝ

Ò½Éúͨ³£ÓÃÆÏÌÑÌÇ×¢ÉäҺά³Ö²¡ÈËѪҺÖеÄѪÌǺ¬Á¿£®ÏÂͼÊÇÒ½Ôº¸ø²¡ÈËÊäҺʱʹÓõÄһƿÖÊÁ¿·ÖÊýΪ5%µÄÆÏÌÑÌÇ£¨C6H12O6£©×¢ÉäÒºµÄ±êÇ©£®
ÆÏÌÑÌÇ×¢ÉäÒº
¹æ¸ñ£º250mL
Ãܶȣº1.08g?mL-1
Éú²úÅúºÅ£º10032032
ÓÐЧÆÚ£ºÖÁ2013Äê3ÔÂ
ÖÊÁ¿·ÖÊý£º5%
ijѧÉúÓûÔÚʵÑéÊÒÖÐÅäÖÆ500mL¸ÃÆÏÌÑÌÇ×¢ÉäÒº£®ÊµÑéÓÃÆ·£ºÆÏÌÑÌǾ§Ì壨Ħ¶ûÖÊÁ¿Îª180g?mol-1£©¡¢ÕôÁóË®¡¢ÉÕ±­¡¢Ììƽ¡¢Ò©³×¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²£®
£¨1£©ÊµÑ黹ȱÉÙµÄÒÇÆ÷ÓÐ______£®
£¨2£©ÏÂÁжÔÈÝÁ¿Æ¿¼°ÆäʹÓ÷½·¨µÄÃèÊöÖÐÕýÈ·µÄÊÇ______£®
A£®Ê¹ÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓñê×¼ÆÏÌÑÌÇ×¢ÉäÒºÈóÏ´
C£®ÅäÖÆÈÜҺʱ£¬½«³ÆºÃµÄÆÏÌÑÌǾ§ÌåСÐĵ¹ÈëÈÝÁ¿Æ¿ÖУ¬¼ÓÕôÁóË®ÖÁ¾à¿Ì¶ÈÏß1¡«2cmʱ£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏß
D£®ÈÝÁ¿Æ¿ÉϱêÃ÷ÈÝ»ý¡¢Î¶ȺÍŨ¶È
£¨3£©ÊµÑéÖÐÐèÈ¡ÓÃ______ g¾§Ì壬ÅäÖƺóµÄÈÜÒºÖÐÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ______£®
£¨4£©ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÆÏÌÑÌÇÈÜҺʱ£¬ÏÂÁвÙ×÷ʹʵÑé½á¹ûÆ«µÍµÄÊÇ______£®
A£®ÈÝÁ¿Æ¿ÖÐÔ­ÓÐÉÙÁ¿ÕôÁóË®¡¡¡¡¡¡¡¡¡¡B£®Ï´µÓÉÕ±­ºÍ²£Á§°ôµÄÈÜҺδתÈëÈÝÁ¿Æ¿ÖУ»
C£®¶¨ÈÝʱ¹Û²ìÒºÃ温ÊÓ¡¡¡¡¡¡¡¡¡¡¡¡¡¡D£®¶¨ÈÝʱ¹Û²ìÒºÃæÑöÊÓ
E£®¶¨Èݺ󣬼Ӹǵ¹×ªÒ¡ÔȺ󣬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÓֵμÓÕôÁóË®ÖÁ¿Ì¶È£¬ËùÅäµÃÈÜÒºµÄŨ¶È£®

½â£º£¨1£©ÒòÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈNaOHÈÜÒº²½ÖèÓгÆÁ¿¡¢Èܽ⡢ÒÆÒº¡¢Ï´µÓ¡¢¶¨ÈÝ¡¢Ò¡ÔȵȲÙ×÷£¬Ò»°ãÓÃÍÐÅÌÌìƽ³ÆÁ¿£¬ÓÃÒ©³×È¡Ò©Æ·£¬·ÅÔÚСÉÕ±­ÖгÆÁ¿£¬È»ºóÔÚÉÕ±­ÖÐÈܽ⣨¿ÉÓÃÁ¿Í²Á¿È¡Ë®£©£¬ÀäÈ´ºóתÒƵ½500mlÈÝÁ¿Æ¿ÖУ¬²¢Óò£Á§°ôÒýÁ÷£¬µ±¼ÓË®ÖÁÒºÃæ¾àÀë¿Ì¶ÈÏß1¡«2cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼Ó£¬ËùÒÔÐèÒªµÄÒÇÆ÷Ϊ£ºÍÐÅÌÌìƽ¡¢ÉÕ±­¡¢Ò©³×¡¢²£Á§°ô¡¢ÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹Ü£¬¹Ê´ð°¸Îª£º500mlÈÝÁ¿Æ¿£»
£¨2£©A£®Ê¹ÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£¬¹ÊAÕýÈ·£»
B£®ÈÝÁ¿Æ¿ÊÇÓÃÀ´ÅäÖÆÈÜÒºµÄ£¬²»ÐèÒª±ê×¼ÆÏÌÑÌÇ×¢ÉäÒºÈóÏ´£¬¹ÊB´íÎó£»
C£®ÒòÈÝÁ¿Æ¿²»ÄÜÖ±½ÓÓÃÀ´Èܽâ¹ÌÌ壬¹ÊC´íÎó£»
D£®ÈÝÁ¿Æ¿ÉϱêÃ÷ÈÝ»ý¡¢Î¶Ⱥ͹æ¸ñ£¬¹ÊD´íÎó£»
¹ÊÑ¡£ºA£®
£¨3£©ÆÏÌÑÌÇ£¨C6H12O6£©×¢ÉäÒºµÄÃܶÈΪ1.08g?mL-1£¬500mLÈÜÒº£¬ÆÏÌÑÌǵÄÖÊÁ¿·ÖÊý5%£¬Ôòº¬ÆÏÌÑÌǵÄÖÊÁ¿Îª£º500mL¡Á1.08g/cm3¡Á5%=27.0g£¬ÆÏÌÑÌǵÄÎïÖʵÄÁ¿Îª=0.15mol£¬ÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶ÈΪ=0.3mol/L£¬¹Ê´ð°¸Îª£º27.0£»0.3mol/L£»
£¨4£©A£®ÈÝÁ¿Æ¿ÖÐÔ­ÓÐÉÙÁ¿ÕôÁóË®£¬¶ÔÌå»ýºÍÎïÖʵÄÁ¿¾ùÎÞÓ°Ï죬¶ÔËùÅäÈÜҺŨ¶ÈÎÞÓ°Ï죬¹ÊA´íÎó£»
B£®Ï´µÓÉÕ±­ºÍ²£Á§°ôµÄÈÜҺδתÈëÈÝÁ¿Æ¿ÖУ¬ÒÆÈëÈÝÁ¿Æ¿ÄÚÈÜÖʵÄÎïÖʵÄÁ¿¼õС£¬ËùÅäÈÜÒºµÄŨ¶ÈÆ«µÍ£¬¹ÊBÕýÈ·£»
C£®¶¨ÈÝʱ¹Û²ìÒºÃ温ÊÓ£¬µ¼ÖÂËùÅäÈÜÒºµÄÌå»ýƫС£¬ËùÅäÈÜÒºµÄŨ¶ÈÆ«´ó£¬¹ÊC´íÎó£»
D£®¶¨ÈÝʱ¹Û²ìÒºÃæÑöÊÓ£¬µ¼ÖÂËùÅäÈÜÒºµÄÌå»ýÆ«´ó£¬ËùÅäÈÜÒºµÄŨ¶ÈƫС£¬¹ÊDÕýÈ·£»
E£®¶¨Èݺ󣬼Ӹǵ¹×ªÒ¡ÔȺ󣬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÓֵμÓÕôÁóË®ÖÁ¿Ì¶È£¬µ¼ÖÂËùÅäÈÜÒºµÄÌå»ýÆ«´ó£¬ËùÅäÈÜÒºµÄŨ¶ÈƫС£¬¹ÊEÕýÈ·£»
¹ÊÑ¡£ºBDE£®
·ÖÎö£º£¨1£©¸ù¾ÝʵÑé²Ù×÷µÄ²½ÖèÒÔ¼°Ã¿²½²Ù×÷ÐèÒªÒÇÆ÷È·¶¨·´Ó¦ËùÐèÒÇÆ÷£»
£¨2£©A£®Ê¹ÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£»
B£®ÈÝÁ¿Æ¿ÊÇÓÃÀ´ÅäÖÆÈÜÒºµÄ£¬²»ÐèÒª±ê×¼ÆÏÌÑÌÇ×¢ÉäÒºÈóÏ´£»
C£®¸ù¾ÝÈÝÁ¿Æ¿²»ÄÜÖ±½ÓÓÃÀ´Èܽâ¹ÌÌ壻
D£®ÈÝÁ¿Æ¿ÉϱêÃ÷ÈÝ»ý¡¢Î¶Ⱥ͹æ¸ñ£»
£¨3£©¸ù¾ÝÌå»ý¡¢ÃܶȿɼÆËãÈÜÒºµÄÖÊÁ¿£¬ÔÙÀûÓÃÆÏÌÑÌǵÄÖÊÁ¿·ÖÊýÀ´¼ÆËãÆÏÌÑÌǵÄÖÊÁ¿£»¸ù¾Ýc=À´¼ÆË㣻
£¨4£©·ÖÎö²Ù×÷¶ÔÈÜÖʵÄÎïÖʵÄÁ¿¡¢ÈÜÒºÌå»ýµÄÓ°Ï죬¸ù¾Ýc=·ÖÎö²Ù×÷¶ÔËùÅäÈÜҺŨ¶ÈµÄÓ°Ï죻
µãÆÀ£º±¾Ì⿼²éÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒºµÄÅäÖƼ°Îó²î·ÖÎö£¬ÄѶÈÖеȣ¬×¢Òâ¸ù¾Ýc=Àí½âÈÜÒºÅäÖÆÓëÎó²î·ÖÎö£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø