ÌâÄ¿ÄÚÈÝ

(6·Ö)ÎÒ¹úÕþ¸®ÎªÁËÏû³ýµâȱ·¦²¡£¬¹æ¶¨ÔÚʳÑÎÖбØÐë¼ÓÈËÊÊÁ¿µÄµâËá¼Ø¡£¼ìÑéʳÑÎÖÐÊÇ·ñ¼Óµâ£¬¿ÉÀûÓÃÈçÏ·´Ó¦£ºKIO3+5KI+3H2SO4====3K2SO4+3I2+3H2O

(1)Óá°Ë«ÏßÇÅ¡±±íʾ³öÉÏÊö·´Ó¦Öеç×Ó×ªÒÆµÄ·½ÏòºÍÊýÄ¿

________________________________________¡£

    (2)Èç¹û·´Ó¦ÖÐ×ªÒÆ0£®2molµç×Ó£¬ÔòÉú³ÉI2µÄÎïÖʵÄÁ¿Îª_________________¡£

    (3)ÀûÓÃÉÏÊö·´Ó¦¼ìÑéʳÑÎÖÐÊÇ·ñ¼Óµâ£¬ËùÐèÊÔ¼ÁÊÇ______________(ÌîÏÂÁÐÑ¡ÏîµÄÐòºÅ)

       ¢ÙµâË®    ¢ÚKIÈÜÒº    ¢Ûµí·ÛÈÜÒº    ¢ÜÏ¡ÁòËá      ¢ÝAgNO3ÈÜÒº  

 

 

£¨1£©KIO3+5KI+3H2SO4====3K2SO4+3I2+3H2O

 

 

 

£¨2£©0.12mol     £¨3£©¢Ú¢Û¢Ü

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø