ÌâÄ¿ÄÚÈÝ

£¨9·Ö£©ÏÖÓÐ10ÖÖÔªËصÄÐÔÖÊ¡¢Êý¾ÝÈçϱíËùÁУ¬ËüÃǾùΪ¶ÌÖÜÆÚÔªËØ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

 
A
B
C
D
E
F
G
H
I
J
Ô­×Ӱ뾶(10£­9m)
0.074
0.160
0.152
0.110
0.099
0.186
0.075
0.082
0.102
0.037
×î¸ß»ò×îµÍ
»¯ºÏ¼Û
 
£«2
£«1
£«5
£«7
£«1
£«5
£«3
+6[
+1
£­2
 
 
£­3
£­1
 
£­3
 
-2
 
£¨1£©HµÄÔªËØ·ûºÅÊÇ          ; BÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ£¨ÖÜÆÚ¡¢×壩            
£¨2£©ÔÚÒÔÉÏÔªËØÐγɵÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄ»¯ºÏÎïµÄ·Ö×ÓʽÊÇ       ¡£
£¨3£©»¯ºÏÎïF2A2µÄµç×ÓʽÊÇ£º         £¬¹¹³É¸ÃÎïÖʵĻ¯Ñ§¼üÀàÐÍΪ________________£¨Ìî¡°Àë×Ó¼ü¡¢¼«ÐÔ¼ü»ò·Ç¼«ÐÔ¼ü¡±£©
µ±F2A2ÓëJ2AµÄ·´Ó¦ÖÐÓÐ3.01¡Á1023¸öµç×ÓתÒÆʱ£¬²Î¼Ó·´Ó¦µÄF2A2µÄÖÊÁ¿ÊÇ         g¡£
£¨4£©Óõç×Óʽ±íʾJ2AµÄÐγɹý³Ì£º                                               £»

(1) B; µÚÈýÖÜÆÚµÚIIA×壻 £¨2£©HClO4;
(3)     Àë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü£»39g
£¨4£©
(µÚ£¨4£©Ìâ2·Ö£¬Èç¹ûµç×Ó·Ö±ðÓõãºÍ²æ±íʾÁË£¬ÔòÇ°ºóµã²æ±ØÐë¶ÔÓ¦£¬·ñÔòû·Ö)
µÚ(3)ÌâµÚ¶þ¸ö¿Õ¡°Àë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü¡±2·Ö£¬Ìî¶ÔÒ»¸ö¸øÒ»·Ö£¬ÆäÓàÿÌâÿ¿Õ1·Ö

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÖÓÐ10ÖÖÔªËصÄÐÔÖÊ¡¢Êý¾ÝÈçϱíËùÁУ¬ËüÃǾùΪ¶ÌÖÜÆÚÔªËØ£®
A B C D E F G H I J
Ô­×Ӱ뾶£¨10-10m£© 0.74 1.60 1.52 1.10 0.99 1.86 0.75 0.82 0.102 0.037
×î¸ß»ò×îµÍ
»¯ºÏ¼Û
+2 +1 +5 +7 +1 +5 +3 +6 +1
-2 -3 -1 -3 -2
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©DµÄÔªËØÃû³ÆÊÇ
Á×
Á×
£¬HµÄÔªËØ·ûºÅÊÇ
B
B
£®
BÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ£¨ÖÜÆÚ¡¢×壩
µÚÈýÖÜÆÚµÚ¢òA×å
µÚÈýÖÜÆÚµÚ¢òA×å

£¨2£©ÔÚÒÔÉÏÔªËØÐγɵÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄ»¯ºÏÎïµÄ·Ö×ÓʽÊÇ
HClO4
HClO4
£®
»¯ºÏÎïF2A2µÄµç×ÓʽÊÇ£º
£¬¹¹³É¸ÃÎïÖʵĻ¯Ñ§¼üÀàÐÍΪ
Àë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü
Àë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü

£¨3£©Óõç×Óʽ±íʾAµÄ¼òµ¥Ç⻯ÎïµÄÐγɹý³ÌÈçÏ£º
£»GµÄÇ⻯ÎïµÄ½á¹¹Ê½Îª
£®
£¨4£©Ò»¶¨Ìõ¼þÏ£¬IA2ÆøÌåÓë×ãÁ¿µÄAµ¥Öʳä·Ö·´Ó¦Éú³É20gÆø̬»¯ºÏÎ·Å³ö24.6kJÈÈÁ¿£¬Ð´³öÆäÈÈ»¯Ñ§·½³Ìʽ
2SO2£¨g£©+O2£¨g£©2SO3£¨g£©£»¡÷H=-196.8kJ/mol
2SO2£¨g£©+O2£¨g£©2SO3£¨g£©£»¡÷H=-196.8kJ/mol
£®
£¨5£©ÓÃJÔªËصĵ¥ÖÊÓëAÔªËصĵ¥ÖÊ¿ÉÒÔÖƳɵç³Ø£¬µç³ØÖÐ×°ÓÐKOHŨÈÜÒº£¬Óöà¿×µÄ¶èÐԵ缫¼×ºÍÒÒ½þÈëKOHÈÜÒº£¬ÔÚ¼×¼«Í¨ÈëJµÄµ¥ÖÊ£¬ÒÒ¼«Í¨ÈëAµÄµ¥ÖÊ£¬Ôò¼×¼«µÄµç¼«·´Ó¦Ê½Îª£º
H2-2e-+2OH-¨T2H2O
H2-2e-+2OH-¨T2H2O
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø