ÌâÄ¿ÄÚÈÝ
£¨12·Ö£©ÓÒͼÊÇijѧУʵÑéÊÒ´Ó»¯Ñ§ÊÔ¼ÁÉ̵êÂò»ØµÄÁòËáÊÔ¼Á±êÇ©ÉϵIJ¿·ÖÄÚÈÝ¡£
ÏÖÓøÃŨÁòËáÅäÖÆ100 mL¡¡1 mol/LµÄÏ¡ÁòËá¡£¿É¹©Ñ¡ÓõÄÒÇÆ÷ÓУº
¢Ù½ºÍ·µÎ¹Ü£»¢ÚÉÕÆ¿£»¢ÛÉÕ±£»¢Ü Ò©³×£»¢ÝÁ¿Í²£»¢ÞÍÐÅÌÌìƽ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÅäÖÆÏ¡ÁòËáʱ£¬ÉÏÊöÒÇÆ÷Öв»ÐèҪʹÓõÄÓÐ £¨Ñ¡ÌîÐòºÅ£©£¬»¹È±ÉÙµÄÒÇÆ÷ÓÐ
¡¡¡¡ £¨Ð´ÒÇÆ÷Ãû³Æ£©£»
(2)¾¼ÆË㣬¸ÃÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ mol/L¡£ÅäÖÆ100mL1mol/LµÄÏ¡ÁòËáÐèÒªÓÃÁ¿Í²Á¿È¡ÉÏÊöŨÁòËáµÄÌå»ýΪ ¡¡ mL£¨±£ÁôһλСÊý£©£¬Á¿È¡Å¨ÁòËáʱӦѡÓà £¨Ñ¡Ìî¢Ù10mL¡¢¢Ú50mL ¡¢¢Û100mL£©¹æ¸ñµÄÁ¿Í²£»
£¨3£©ÓýºÍ·µÎ¹ÜÍùÈÝÁ¿Æ¿ÖмÓˮʱ£¬²»Ð¡ÐÄÒºÃ泬¹ýÁ˿̶ȣ¬´¦ÀíµÄ·½·¨ÊÇ________£¨ÌîÐòºÅ£©¡£
A.Îü³ö¶àÓàÒºÌ壬ʹ°¼ÒºÃæÓë¿Ì¶ÈÏßÏàÇÐ
B.СÐļÓÈÈÈÝÁ¿Æ¿£¬¾Õô·¢ºó£¬Ê¹°¼ÒºÃæÓë¿Ì¶ÈÏßÏàÇÐ
C.¾¼ÆËã¼ÓÈëÒ»¶¨Á¿µÄŨÑÎËá
D.ÖØÐÂÅäÖÆ
(ÿ¿Õ2·Ö)(1) ¢Ú ¢Ü ¢Þ £» 100mLÈÝÁ¿Æ¿ ²£Á§°ô
(2) 18.4 mol/L 5.4 ¢Ù £¨3£©D
¡¾½âÎö¡¿£¨1£©ÓÉÓÚÁòËáÊÇÈÜÒº£¬Òò´Ë ¢Ú ¢Ü ¢ÞÊDz»ÐèÒªµÄ¡£¸ù¾ÝÅäÖÆÔÀí¿ÉÖª£¬»¹È±ÉÙ100mLÈÝÁ¿Æ¿¡¢²£Á§°ô¡£
£¨2£©¸ù¾Ý¿ÉÖª¡£ÁòËáµÄŨ¶ÈÊÇ¡£ÒòΪϡÊ͹ý³ÌÖУ¬ÈÜÖÊÊDz»±äµÄ£¬ËùÒÔÐèÒªÁòËáµÄÌå»ýÊÇ¡£¸ù¾Ý¹æ¸ñÏà½üµÄÔÔò¿ÉÖª£¬Ó¦¸ÃÑ¡Ôñ¢Ù¡£
£¨3£©ÓýºÍ·µÎ¹ÜÍùÈÝÁ¿Æ¿ÖмÓˮʱ£¬²»Ð¡ÐÄÒºÃ泬¹ýÁ˿̶ȣ¬Õâ˵Ã÷ʵÑéÒÑ֪ʧ°Ü£¬Ö»ÄÜÖØ×ö£¬´ð°¸Ñ¡D¡£
ÓÒͼÊÇijѧУʵÑéÊÒ´Ó»¯Ñ§ÊÔ¼ÁÉ̵êÂò»ØµÄÁòËáÊÔ¼Á±êÇ©ÉϵIJ¿·ÖÄÚÈÝ¡£¾Ý´ËÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®¸ÃÊÔ¼ÁµÄÎïÖʵÄÁ¿Å¨¶ÈΪ9.2 mol/L |
B£®¸ÃÁòËá50mLÓë×ãÁ¿µÄÍ·´Ó¦Éú³É±ê×¼×´¿öÏÂ10.3 L SO2 |
C£®ÅäÖÆ250mL¡¢4.6 mol/LµÄÏ¡ÁòËáÐè¸ÃÁòËá62.5 mL |
D£®¸ÃÁòËáÓëµÈÌå»ýµÄË®»ìºÏºóËùµÃÈÜÒºµÄÖÊÁ¿·ÖÊýСÓÚ49% |