ÌâÄ¿ÄÚÈÝ
±ê¿öϳäÂúHClµÄÉÕÆ¿×öÍêÅçȪʵÑéºóµÃµ½Ï¡ÑÎËᣬÓñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËá²â¶¨ËüµÄ׼ȷŨ¶È£¬ÇëÄã»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Óñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËáʱ£¬Ì¼ËáÄÆÈÜҺӦװÔÚ______ʽµÎ¶¨¹ÜÖУ¬ÈôÓü׻ù³È×÷ָʾ¼Á£¬´ïµ½µÎ¶¨ÖÕµãʱ£¬ÈÜÒº´Ó______É«±ä³É______É«£®
£¨2£©ÏÖÅäÖÆÈýÖÖŨ¶ÈµÄ±ê׼̼ËáÄÆÈÜÒº£¬ÄãÈÏΪ×îºÏÊʵÄÊÇÏÂÁеÚ______ÖÖ£®
¢Ù2.500mol/L ¢Ú0.25mol/L ¢Û0.025mol/L
£¨3£©Èô²ÉÓÃÉÏÊöºÏÊʵıê׼̼ËáÄÆÈÜÒºµÎ¶¨£¬ÓÃc£¨Na2CO3£©±íʾ£¬µÎ¶¨Ê±ÊµÑéÊý¾ÝÁбíÈçÏ£º
ÇóÕâÖÖ´ý²âÏ¡ÑÎËáµÄÎïÖʵÄÁ¿Å¨¶È£¨ÓÃÌâÖÐËù¸øÊý¾ÝÁгö¼ÆËãʽ¼´¿É£©£®c£¨HCl£©=______£®
£¨4£©ÈôÊ¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬Ôò×îºóËù²âÑÎËáŨ¶È______£¬ÈôµÎ¶¨Íê±Ïºó¶ÁÊýʱ¸©ÊÓ£¬ÔòʵÑéÎó²îΪ______£¨ÒÔÉÏÁ½¿ÕÌî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©
£¨1£©Óñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËáʱ£¬Ì¼ËáÄÆÈÜҺӦװÔÚ______ʽµÎ¶¨¹ÜÖУ¬ÈôÓü׻ù³È×÷ָʾ¼Á£¬´ïµ½µÎ¶¨ÖÕµãʱ£¬ÈÜÒº´Ó______É«±ä³É______É«£®
£¨2£©ÏÖÅäÖÆÈýÖÖŨ¶ÈµÄ±ê׼̼ËáÄÆÈÜÒº£¬ÄãÈÏΪ×îºÏÊʵÄÊÇÏÂÁеÚ______ÖÖ£®
¢Ù2.500mol/L ¢Ú0.25mol/L ¢Û0.025mol/L
£¨3£©Èô²ÉÓÃÉÏÊöºÏÊʵıê׼̼ËáÄÆÈÜÒºµÎ¶¨£¬ÓÃc£¨Na2CO3£©±íʾ£¬µÎ¶¨Ê±ÊµÑéÊý¾ÝÁбíÈçÏ£º
ʵÑé´ÎÊý±àºÅ | ´ý²âÑÎËáÌå»ý£¨mL£© | µÎÈë̼ËáÄÆÈÜÒºÌå»ý£¨mL£© |
1 | 20.00 | 18.80 |
2 | 20.00 | 16.95 |
3 | 20.00 | 17.05 |
£¨4£©ÈôÊ¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬Ôò×îºóËù²âÑÎËáŨ¶È______£¬ÈôµÎ¶¨Íê±Ïºó¶ÁÊýʱ¸©ÊÓ£¬ÔòʵÑéÎó²îΪ______£¨ÒÔÉÏÁ½¿ÕÌî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©
£¨1£©Ì¼ËáÄÆÈÜÒº³Ê¼îÐÔ£¬ÓüîʽµÎ¶¨¹Üʢװ̼ËáÄÆÈÜÒº£»µÎ¶¨ÖÕµãʱ£¬ÈÜÒºÑÕÉ«ÓɺìÉ«±äΪ³ÈÉ«ÇÒ°ë·ÖÖÓÄÚ²»±äÉ«£»¹Ê´ð°¸Îª£º¼îʽ£»ºìÉ«£»³ÈÉ«£»
£¨2£©HClµÄ´óÖÂŨ¶ÈΪ
mol/L=0.045mol/L£¬±ê׼̼ËáÄÆÈÜҺӦѡ0.025mol/L£¬¹ÊÑ¡£º¢Û£»
£¨3£©£¨3£©ÉáÈ¥µÚÒ»×éÊý¾Ý£¬Ì¼ËáÄÆÈÜÒºµÄƽ¾ùÌå»ýΪ
£¬
2HCl¡«Na2CO3
2 1
C£¨HCl£©¡Á20.00mL 0.025mol/L¡Á
C(HCl)=
¡Á
mol¡ÁL-1
¹Ê´ð°¸Îª£ºC(HCl)=
¡Á
mol¡ÁL-1£»
£¨4£©Ê¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬±ê×¼ÒºµÄŨ¶È½µµÍ£¬Ôì³ÉV£¨±ê×¼Òº£©Æ«´ó£¬¸ù¾Ýc£¨´ý²â£©=
¿ÉÖªc£¨´ý²â£©Æ«¸ß£»µÎ¶¨Íê±Ïºó¶ÁÊýʱ¸©ÊÓ£¬Ôì³ÉV£¨±ê×¼Òº£©Æ«Ð¡£¬¸ù¾Ýc£¨´ý²â£©=
¿ÉÖªc£¨´ý²â£©Æ«Ð¡£¬¹Ê´ð°¸Îª£ºÆ«¸ß£»Æ«µÍ£®
£¨2£©HClµÄ´óÖÂŨ¶ÈΪ
1 |
22.4 |
£¨3£©£¨3£©ÉáÈ¥µÚÒ»×éÊý¾Ý£¬Ì¼ËáÄÆÈÜÒºµÄƽ¾ùÌå»ýΪ
16.95+17.05 |
2 |
2HCl¡«Na2CO3
2 1
C£¨HCl£©¡Á20.00mL 0.025mol/L¡Á
16.95+17.05 |
2 |
C(HCl)=
2¡ÁC(Na2CO3) |
20.00 |
(16.95+17.05) |
2 |
¹Ê´ð°¸Îª£ºC(HCl)=
2¡ÁC(Na2CO3) |
20.00 |
(16.95+17.05) |
2 |
£¨4£©Ê¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬±ê×¼ÒºµÄŨ¶È½µµÍ£¬Ôì³ÉV£¨±ê×¼Òº£©Æ«´ó£¬¸ù¾Ýc£¨´ý²â£©=
c(±ê×¼)¡ÁV(±ê×¼) |
V(´ý²â) |
c(±ê×¼)¡ÁV(±ê×¼) |
V(´ý²â) |
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
±ê¿öϳäÂúHClµÄÉÕÆ¿×öÍêÅçȪʵÑéºóµÃµ½Ï¡ÑÎËᣬÓñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËá²â¶¨ËüµÄ׼ȷŨ¶È£¬ÇëÄã»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Óñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËáʱ£¬Ì¼ËáÄÆÈÜҺӦװÔÚ______ʽµÎ¶¨¹ÜÖУ¬ÈôÓü׻ù³È×÷ָʾ¼Á£¬´ïµ½µÎ¶¨ÖÕµãʱ£¬ÈÜÒº´Ó______É«±ä³É______É«£®
£¨2£©ÏÖÅäÖÆÈýÖÖŨ¶ÈµÄ±ê׼̼ËáÄÆÈÜÒº£¬ÄãÈÏΪ×îºÏÊʵÄÊÇÏÂÁеÚ______ÖÖ£®
¢Ù2.500mol/L ¢Ú0.25mol/L ¢Û0.025mol/L
£¨3£©Èô²ÉÓÃÉÏÊöºÏÊʵıê׼̼ËáÄÆÈÜÒºµÎ¶¨£¬ÓÃc£¨Na2CO3£©±íʾ£¬µÎ¶¨Ê±ÊµÑéÊý¾ÝÁбíÈçÏ£º
ÇóÕâÖÖ´ý²âÏ¡ÑÎËáµÄÎïÖʵÄÁ¿Å¨¶È£¨ÓÃÌâÖÐËù¸øÊý¾ÝÁгö¼ÆËãʽ¼´¿É£©£®c£¨HCl£©=______£®
£¨4£©ÈôÊ¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬Ôò×îºóËù²âÑÎËáŨ¶È______£¬ÈôµÎ¶¨Íê±Ïºó¶ÁÊýʱ¸©ÊÓ£¬ÔòʵÑéÎó²îΪ______£¨ÒÔÉÏÁ½¿ÕÌî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©
£¨1£©Óñê׼̼ËáÄÆÈÜÒºµÎ¶¨ÕâÖÖÑÎËáʱ£¬Ì¼ËáÄÆÈÜҺӦװÔÚ______ʽµÎ¶¨¹ÜÖУ¬ÈôÓü׻ù³È×÷ָʾ¼Á£¬´ïµ½µÎ¶¨ÖÕµãʱ£¬ÈÜÒº´Ó______É«±ä³É______É«£®
£¨2£©ÏÖÅäÖÆÈýÖÖŨ¶ÈµÄ±ê׼̼ËáÄÆÈÜÒº£¬ÄãÈÏΪ×îºÏÊʵÄÊÇÏÂÁеÚ______ÖÖ£®
¢Ù2.500mol/L ¢Ú0.25mol/L ¢Û0.025mol/L
£¨3£©Èô²ÉÓÃÉÏÊöºÏÊʵıê׼̼ËáÄÆÈÜÒºµÎ¶¨£¬ÓÃc£¨Na2CO3£©±íʾ£¬µÎ¶¨Ê±ÊµÑéÊý¾ÝÁбíÈçÏ£º
ʵÑé´ÎÊý±àºÅ | ´ý²âÑÎËáÌå»ý£¨mL£© | µÎÈë̼ËáÄÆÈÜÒºÌå»ý£¨mL£© |
1 | 20.00 | 18.80 |
2 | 20.00 | 16.95 |
3 | 20.00 | 17.05 |
£¨4£©ÈôÊ¢×°Na2CO3ÈÜÒºµÄµÎ¶¨¹ÜÔڵζ¨Ç°Î´Óñê×¼ÒºÈóÏ´£¬Ôò×îºóËù²âÑÎËáŨ¶È______£¬ÈôµÎ¶¨Íê±Ïºó¶ÁÊýʱ¸©ÊÓ£¬ÔòʵÑéÎó²îΪ______£¨ÒÔÉÏÁ½¿ÕÌî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©