ÌâÄ¿ÄÚÈÝ

ÒÑÖªÒÒ¶þËá(HOOC¡ªCOOH)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬Ò×Éý»ª£¬ÊÜÈÈÒ׷ֽ⡣ÆäÑβÝËá¸ÆºÍ²ÝËáÇâ¸Æ¾ùΪ°×É«ÄÑÈÜÎï¡£

ij¿ÎÍâ»î¶¯Ð¡×éΪÁË̽Ë÷ÒÒ¶þËáµÄËáÐÔÇ¿Èõ¼°ÒÒ¶þËáÊÜÈÈ·Ö½â²úÎÉè¼ÆÁËÈçÏÂʵÑé¡£

(1)ÓÃpHÊÔÖ½²â¶¨µÈÎïÖʵÄÁ¿Å¨¶ÈµÄÁòËá¡¢ÒÒ¶þËá¡¢´×ËáÈÜÒºµÄpH£¬²âµÃÈÜÒºµÄpH·Ö±ðΪa¡¢b¡¢c£¬ÇÒa£¼b£¼c¡£

¢Ù²â¶¨ÉÏÊöÈÜÒºpHµÄ·½·¨ÊÇ________________________________________________¡£

¢ÚÉÏÊöÈýÖÖËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ__________________________________________¡£

(2)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼװÖýøÐÐʵÑé¡£

³ä·Ö¼ÓÈÈÒ»¶Îʱ¼äºó£¬·¢ÏÖÒÒ×°ÖÃÖÐUÐιÜÀï³öÏÖÉÙÁ¿ÒºÌ壬±û×°ÖÃÖгÎÇåʯ»ÒË®±ä»ë×Ç¡£´ý·´Ó¦Íê³Éºó£¬ÏòÒÒ×°ÖÃÖÐUÐιÜÀï¼ÓÈëÉÙÁ¿ÎÞË®ÁòËáÍ­£¬ÎÞË®ÁòËáÍ­±äÀ¶¡£

¢Ù¸ù¾ÝÉÏÊöʵÑéÊÂʵ£¬ÍƲâÒÒ¶þËá·Ö½â²úÎïÖÐÒ»¶¨ÓÐ__________________________________¡£

¢ÚÒÒ×°ÖõÄ×÷ÓÃÊÇ________________________________________________________¡£

(3)¸ù¾Ý¶¡×°ÖÃÍƲ⣬ÒÒ¶þËá·Ö½âµÄ²úÎïÖл¹¿ÉÄÜÓÐ___________________________________¡£

(1)¢ÙÓýྻµÄ²£Á§°ôպȡÉÙÁ¿´ý²âÊÔµÎÓÚÒ»ÌõpHÊÔÖ½ÉÏ£¬°ÑÊÔÖ½ÏÔʾµÄÑÕÉ«Óë±ê×¼±ÈÉ«¿¨±È½Ï£¬ÒÔÈ·¶¨ÆäpH

¢ÚÁòË᣾ÒÒ¶þË᣾´×Ëá(»òH2SO4£¾£¾CH3COOH)

(2)¢Ù¶þÑõ»¯Ì¼ºÍË®(»òCO2ºÍH2O)

¢ÚÀäÄýÒÒ¶þËá·Ö½âµÄÆø̬²úÎïºÍÉý»ªµÄÒÒ¶þËᣬÅųýÉý»ªµÄÒÒ¶þËá¶ÔÆä·Ö½â²úÎï¶þÑõ»¯Ì¼È·¶¨µÄ¸ÉÈÅ

(3)Ò»Ñõ»¯Ì¼(»òCO)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÒÑÖªÒÒ¶þËá(HOOC¨DCOOH£¬¿É¼òдΪH2C2O4)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬ÊôÓÚ¶þÔªÖÐÇ¿Ëá(ΪÈõµç½âÖÊ)£¬ÇÒËáÐÔÇ¿ÓÚ̼ËᣬÆäÈÛµãΪ101.5¡æ£¬ÔÚ157¡æÉý»ª¡£Ä³Ð£Ñо¿ÐÔѧϰС×éΪ̽¾¿²ÝËáµÄ²¿·Ö»¯Ñ§ÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑ飺

(1)ÏòÊ¢ÓÐ1 mL±¥ºÍNaHCO3ÈÜÒºµÄÊÔ¹ÜÖмÓÈë×ãÁ¿ÒÒ¶þËáÈÜÒº£¬¹Û²ìµ½ÓÐÎÞÉ«ÆøÅݲúÉú¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________¡£

(2)ÏòÊ¢ÓÐÉÙÁ¿ÒÒ¶þËá±¥ºÍÈÜÒºµÄÊÔ¹ÜÖеÎÈëÓÃÁòËáËữµÄKMnO4ÈÜÒº£¬Õñµ´£¬·¢ÏÖÆäÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥£¬ËµÃ÷ÒÒ¶þËá¾ßÓÐ_________________(Ìî¡°Ñõ»¯ÐÔ¡±¡¢¡°»¹Ô­ÐÔ¡±»ò¡°ËáÐÔ¡±)£¬ÇëÅäƽ¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º

____ MnO4¨C + ____ H2C2O4 + _____ H+ = _____ Mn2+ + _____ CO2¡ü + _____ H2O

(3)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃδ±ê³ö)£º

ʵÑé·¢ÏÖ£¬×°ÖÃC¡¢GÖгÎÇåʯ»ÒË®±ä»ë×Ç£¬BÖÐCuSO4·ÛÄ©±äÀ¶£¬FÖÐCuO·ÛÄ©±äºì£¬

¾Ý´Ë£¬ÒÒ¶þËá·Ö½âµÄ²úÎïΪ___________________________¡£ÉÏÊö×°ÖÃÖУ¬DµÄ×÷ÓÃÊÇ_____

__________________________________________¡£×°ÖÃFÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

___________________________________________________________¡£

(4)¸ÃС×éͬѧ½«2.52 g²ÝËᾧÌå(H2C2O4??2H2O)¼ÓÈëµ½100 mL 0.2 mol/LµÄNaOHÈÜÒºÖгä·Ö·´Ó¦£¬²âµÃ·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÆäÔ­ÒòÊÇ______________________

________________________________________________________________¡£

ÒÑÖªÒÒ¶þËá(HOOC¨DCOOH£¬¿É¼òдΪH2C2O4)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬ÊôÓÚ¶þÔªÖÐÇ¿Ëá(ΪÈõµç½âÖÊ)£¬ÇÒËáÐÔÇ¿ÓÚ̼ËᣬÆäÈÛµãΪ101.5¡æ£¬ÔÚ157¡æÉý»ª¡£Ä³Ð£Ñо¿ÐÔѧϰС×éΪ̽¾¿²ÝËáµÄ²¿·Ö»¯Ñ§ÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑ飺

(1)ÏòÊ¢ÓÐ1 mL±¥ºÍNaHCO3ÈÜÒºµÄÊÔ¹ÜÖмÓÈë×ãÁ¿ÒÒ¶þËáÈÜÒº£¬¹Û²ìµ½ÓÐÎÞÉ«ÆøÅݲúÉú¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________________¡£

(2)ÏòÊ¢ÓÐÉÙÁ¿ÒÒ¶þËá±¥ºÍÈÜÒºµÄÊÔ¹ÜÖеÎÈëÓÃÁòËáËữµÄKMnO4ÈÜÒº£¬Õñµ´£¬·¢ÏÖÆäÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥£¬ËµÃ÷ÒÒ¶þËá¾ßÓÐ_________________(Ìî¡°Ñõ»¯ÐÔ¡±¡¢¡°»¹Ô­ÐÔ¡±»ò¡°ËáÐÔ¡±)£¬ÇëÅäƽ¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º

____ MnO4¨C + ____ H2C2O4 + _____ H+ = _____ Mn2+ + _____ CO2¡ü + _____ H2O

(3)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃδ±ê³ö)£º

ʵÑé·¢ÏÖ£¬×°ÖÃC¡¢GÖгÎÇåʯ»ÒË®±ä»ë×Ç£¬BÖÐCuSO4·ÛÄ©±äÀ¶£¬FÖÐCuO·ÛÄ©±äºì£¬

¾Ý´Ë£¬ÒÒ¶þËá·Ö½âµÄ²úÎïΪ______________________¡£ÉÏÊö×°ÖÃÖУ¬DµÄ×÷ÓÃÊÇ______¡£×°ÖÃFÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º _________________________________________¡£

(4)¸ÃС×éͬѧ½«2.52g²ÝËᾧÌå(H2C2O4??2H2O)¼ÓÈëµ½100 mL 0.2 mol/LµÄNaOHÈÜÒºÖгä·Ö·´Ó¦£¬²âµÃ·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÆäÔ­ÒòÊÇ_________________________________¡£

ÒÑÖªÒÒ¶þËá(HOOC¨DCOOH£¬¿É¼òдΪH2C2O4)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬ÊôÓÚ¶þÔªÖÐÇ¿Ëá(ΪÈõµç½âÖÊ)£¬ÇÒËáÐÔÇ¿ÓÚ̼ËᣬÆäÈÛµãΪ101.5¡æ£¬ÔÚ157¡æÉý»ª¡£Ä³Ð£Ñо¿ÐÔѧϰС×éΪ̽¾¿²ÝËáµÄ²¿·Ö»¯Ñ§ÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑ飺

(1)ÏòÊ¢ÓÐ1 mL±¥ºÍNaHCO3ÈÜÒºµÄÊÔ¹ÜÖмÓÈë×ãÁ¿ÒÒ¶þËáÈÜÒº£¬¹Û²ìµ½ÓÐÎÞÉ«ÆøÅݲúÉú¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________¡£

(2)ÏòÊ¢ÓÐÉÙÁ¿ÒÒ¶þËá±¥ºÍÈÜÒºµÄÊÔ¹ÜÖеÎÈëÓÃÁòËáËữµÄKMnO4ÈÜÒº£¬Õñµ´£¬·¢ÏÖÆäÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥£¬ËµÃ÷ÒÒ¶þËá¾ßÓÐ_________________(Ìî¡°Ñõ»¯ÐÔ¡±¡¢¡°»¹Ô­ÐÔ¡±»ò¡°ËáÐÔ¡±)£¬ÇëÅäƽ¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º

____ MnO4¨C + ____ H2C2O4 + _____ H+ = _____ Mn2+ + _____ CO2¡ü + _____ H2O

(3)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃδ±ê³ö)£º

ʵÑé·¢ÏÖ£¬×°ÖÃC¡¢GÖгÎÇåʯ»ÒË®±ä»ë×Ç£¬BÖÐCuSO4·ÛÄ©±äÀ¶£¬FÖÐCuO·ÛÄ©±äºì£¬

¾Ý´Ë£¬ÒÒ¶þËá·Ö½âµÄ²úÎïΪ___________________________¡£ÉÏÊö×°ÖÃÖУ¬DµÄ×÷ÓÃÊÇ_____

__________________________________________¡£×°ÖÃFÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

___________________________________________________________¡£

(4)¸ÃС×éͬѧ½«2.52 g²ÝËᾧÌå(H2C2O4•2H2O)¼ÓÈëµ½100 mL 0.2 mol/LµÄNaOHÈÜÒºÖгä·Ö·´Ó¦£¬²âµÃ·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÆäÔ­ÒòÊÇ______________________

________________________________________________________________¡£

 

ÒÑÖªÒÒ¶þËá(HOOC¨DCOOH£¬¿É¼òдΪH2C2O4)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬ÊôÓÚ¶þÔªÖÐÇ¿Ëá(ΪÈõµç½âÖÊ)£¬ÇÒËáÐÔÇ¿ÓÚ̼ËᣬÆäÈÛµãΪ101.5¡æ£¬ÔÚ157¡æÉý»ª¡£Ä³Ð£Ñо¿ÐÔѧϰС×éΪ̽¾¿²ÝËáµÄ²¿·Ö»¯Ñ§ÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑ飺
(1)ÏòÊ¢ÓÐ1 mL±¥ºÍNaHCO3ÈÜÒºµÄÊÔ¹ÜÖмÓÈë×ãÁ¿ÒÒ¶þËáÈÜÒº£¬¹Û²ìµ½ÓÐÎÞÉ«ÆøÅݲúÉú¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________¡£
(2)ÏòÊ¢ÓÐÉÙÁ¿ÒÒ¶þËá±¥ºÍÈÜÒºµÄÊÔ¹ÜÖеÎÈëÓÃÁòËáËữµÄKMnO4ÈÜÒº£¬Õñµ´£¬·¢ÏÖÆäÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥£¬ËµÃ÷ÒÒ¶þËá¾ßÓÐ_________________(Ìî¡°Ñõ»¯ÐÔ¡±¡¢¡°»¹Ô­ÐÔ¡±»ò¡°ËáÐÔ¡±)£¬ÇëÅäƽ¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º
____ MnO4¨C + ____ H2C2O4 + _____ H+ =" _____" Mn2+ + _____ CO2¡ü + _____ H2O
(3)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃδ±ê³ö)£º
ʵÑé·¢ÏÖ£¬×°ÖÃC¡¢GÖгÎÇåʯ»ÒË®±ä»ë×Ç£¬BÖÐCuSO4·ÛÄ©±äÀ¶£¬FÖÐCuO·ÛÄ©±äºì£¬

¾Ý´Ë£¬ÒÒ¶þËá·Ö½âµÄ²úÎïΪ___________________________¡£ÉÏÊö×°ÖÃÖУ¬DµÄ×÷ÓÃÊÇ_____
__________________________________________¡£×°ÖÃFÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
___________________________________________________________¡£
(4)¸ÃС×éͬѧ½«2.52 g²ÝËᾧÌå(H2C2O4?2H2O)¼ÓÈëµ½100 mL 0.2 mol/LµÄNaOHÈÜÒºÖгä·Ö·´Ó¦£¬²âµÃ·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÆäÔ­ÒòÊÇ______________________
________________________________________________________________¡£

ÒÑÖªÒÒ¶þËá(HOOC¨DCOOH£¬¿É¼òдΪH2C2O4)Ë׳ƲÝËᣬÒ×ÈÜÓÚË®£¬ÊôÓÚ¶þÔªÖÐÇ¿Ëá(ΪÈõµç½âÖÊ)£¬ÇÒËáÐÔÇ¿ÓÚ̼ËᣬÆäÈÛµãΪ101.5¡æ£¬ÔÚ157¡æÉý»ª¡£Ä³Ð£Ñо¿ÐÔѧϰС×éΪ̽¾¿²ÝËáµÄ²¿·Ö»¯Ñ§ÐÔÖÊ£¬½øÐÐÁËÈçÏÂʵÑ飺

(1)ÏòÊ¢ÓÐ1 mL±¥ºÍNaHCO3ÈÜÒºµÄÊÔ¹ÜÖмÓÈë×ãÁ¿ÒÒ¶þËáÈÜÒº£¬¹Û²ìµ½ÓÐÎÞÉ«ÆøÅݲúÉú¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________¡£

(2)ÏòÊ¢ÓÐÉÙÁ¿ÒÒ¶þËá±¥ºÍÈÜÒºµÄÊÔ¹ÜÖеÎÈëÓÃÁòËáËữµÄKMnO4ÈÜÒº£¬Õñµ´£¬·¢ÏÖÆäÈÜÒºµÄ×ϺìÉ«ÍÊÈ¥£¬ËµÃ÷ÒÒ¶þËá¾ßÓÐ_________________(Ìî¡°Ñõ»¯ÐÔ¡±¡¢¡°»¹Ô­ÐÔ¡±»ò¡°ËáÐÔ¡±)£¬ÇëÅäƽ¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º

____ MnO4¨C + ____ H2C2O4 + _____ H+ = _____ Mn2+ + _____ CO2¡ü + _____ H2O

(3)½«Ò»¶¨Á¿µÄÒÒ¶þËá·ÅÓÚÊÔ¹ÜÖУ¬°´ÏÂͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃδ±ê³ö)£º

ʵÑé·¢ÏÖ£¬×°ÖÃC¡¢GÖгÎÇåʯ»ÒË®±ä»ë×Ç£¬BÖÐCuSO4·ÛÄ©±äÀ¶£¬FÖÐCuO·ÛÄ©±äºì£¬

¾Ý´Ë£¬ÒÒ¶þËá·Ö½âµÄ²úÎïΪ___________________________¡£ÉÏÊö×°ÖÃÖУ¬DµÄ×÷ÓÃÊÇ_____

__________________________________________¡£×°ÖÃFÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

___________________________________________________________¡£

(4)¸ÃС×éͬѧ½«2.52 g²ÝËᾧÌå(H2C2O4•2H2O)¼ÓÈëµ½100 mL 0.2 mol/LµÄNaOHÈÜÒºÖгä·Ö·´Ó¦£¬²âµÃ·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÆäÔ­ÒòÊÇ______________________

________________________________________________________________¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø