Question

£¨1£©£¨7·Ö£©ÔÚFe£¨OH£©₃½ºÌåÖÐÖðµÎ¼ÓÈëHIÏ¡ÈÜÒº£¬»á³öÏÖһϵÁб仯£º
¢ÙÏȳöÏÖºìºÖÉ«³Áµí£¬Ô­ÒòÊÇ£º                          £»
¢ÚËæºó³ÁµíÈܽ⣬ÈÜÒº³Ê»ÆÉ«£¬Ð´³ö´Ë¹ý³Ì·´Ó¦µÄÀë×Ó·½³Ìʽ£º           £»
¢Û×îºóÈÜÒºÑÕÉ«¼ÓÉԭÒòÊÇ£º               £¬´Ë¹ý³ÌµÄÀë×Ó·½³ÌʽÊÇ£º     £»¢ÜÈçÓÃÏ¡ÑÎËá´úÌæHIÏ¡ÈÜÒº£¬ÄܳöÏÖÉÏÊöÄÄЩÏàͬµÄʵÑéÏÖÏ󣺠      £¨Ð´ÐòºÅ£©¡£
£¨2£©£¨3·Ö£©2.00gC₂H₂ÆøÌåÍêȫȼÉÕÉú³ÉҺ̬ˮºÍCO₂ÆøÌ壬·Å³ö99.6kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦È¼ÉÕµÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ                                     £»

Answer 1

£¨1£©¢Ù¼ÓÈëµç½âÖÊ£¬Ê¹½ºÌåÄý¾Û£¨1·Ö_w.*£©
¢ÚFe£¨OH£©₃+3H⁺=Fe²⁺+3H₂O£¨2·Ö£©
¢ÛÓÐI₂Éú³É£»£¨1·Ö£©2Fe³⁺+2I^-=2Fe²⁺+I₂£¨2·Ö£©
¢Ü£¨1£©£¨2£©£¨1·Ö£©
£¨2£©C₂H₂£¨g£©+O₂£¨g£©¡ú2CO₂£¨g£©+H₂O£¨l£©£»¡÷H=¡ª1294.8kJ/mol£¨3·Ö£©£¨ÆäËüºÏÀí´ð°¸Ò²µÃ·Ö£©

ÂÔ