ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÑÇÏõËáÂÈ(C1NO)ÊÇÓлúºÏ³ÉÖеÄÖØÒªÊÔ¼Á¡£¿ÉÓÉNOÓëCl2ÔÚͨ³£Ìõ¼þÏ·´Ó¦µÃµ½£¬»¯Ñ§·½³ÌʽΪ2NO(g)+C12(g)2C1NO(g)£¬
£¨1£©µªÑõ»¯ÎïÓëÐü¸¡ÔÚ´óÆøÖеĺ£ÑÎÁ£×ÓÏ໥×÷ÓÃʱ»áÉú³ÉÑÇÏõËáÂÈ£¬Éæ¼°ÈçÏ·´Ó¦£º
¢Ù 2NO2(g)+NaC1(s)NaNO3(s)+ClNO(g) K1
¢Ú 4NO2(g)+2NaC1(s)2NaNO3(s)+2NO(g)+Cl2(g) K2
¢Û 2NO(g)+C12(g)2C1NO(g) K3
ÔòK1£¬K2£¬K3Ö®¼äµÄ¹ØϵΪK3=______________¡£
£¨2£©ÒÑÖª¼¸ÖÖ»¯Ñ§¼üµÄ¼üÄÜÊý¾ÝÈçϱí(ÑÇÏõËáÂȵĽṹΪCl-N=O):
Ôò2NO(g)+C12(g)2C1NO(g)·´Ó¦µÄ¡÷HºÍaµÄ¹ØϵΪ¡÷H=________kJ/mol¡£
£¨3£©ÔÚ1LµÄºãÈÝÃܱÕÈÝÆ÷ÖгäÈë2molNO(g)ºÍ1molC12(g)£¬ÔÚ²»Í¬Î¶ÈϲâµÃc(C1NO)Óëʱ¼äµÄ¹ØϵÈçͼA:
¢Ù ÓÉͼA¿ÉÅжÏT1 ________T2£¬¸Ã·´Ó¦µÄ¡÷H________0 (Ìî¡°>¡±¡°<¡±»ò¡°=¡±)¡£
¢Ú ·´Ó¦¿ªÊ¼µ½10minʱNOµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=____________mol/(L¡¤min)¡£
¢Û T2ʱ¸Ã·´Ó¦µÄƽºâ³£ÊýK=____________¡£
£¨4£© Ò»¶¨Ìõ¼þÏÂÔÚºãκãÈݵÄÃܱÕÈÝÆ÷Öа´Ò»¶¨±ÈÀý³äÈëNO(g)ºÍCl2(g)£¬Æ½ºâʱClNOµÄÌå»ý·ÖÊýËæn(NO)/n(C12)µÄ±ä»¯Í¼ÏóÈçͼB£¬ÔòA¡¢B¡¢CÈý״̬ÖУ¬NOµÄת»¯ÂÊ×î´óµÄÊÇ________µã¡£
¡¾´ð°¸¡¿ K12/K2 289-2a < < 0.1 2 A
¡¾½âÎö¡¿ÊÔÌâ·ÖÎö£º£¨1£©ÒÑÖª£º¢Ù2NO2(g)+NaCl(s)NaNO3(s)+ClNO(g)
¢Ú 4NO2(g)+2NaCl(s)2NaNO3(s)+2NO(g)+Cl2(g)
¸ù¾Ý¸Ç˹¶¨ÂÉ¿ÉÖª½«¢Ù¡Á2-¢Ú¿ÉµÃ£º2NO(g)+Cl2(g)2ClNO(g)£¬Òò´Ë¸Ã·´Ó¦µÄƽºâ³£ÊýK3£½K12/K2¡£
£¨2£©2NO(g)+C12(g)2C1NO(g)·´Ó¦µÄ¡÷H=·´Ó¦ÎïµÄ¼üÄÜÖ®ºÍ-Éú³ÉÎïµÄ¼üÄÜÖ®ºÍ=(2¡Á630+243) kJ/mol-(2a+2¡Á607) kJ/mol£½(289-2a)kJ/mol¡£
£¨3£©¢Ù ¸ù¾ÝͼÏñ¿ÉÖªT2£¾T1£¬½µµÍζÈc(C1NO)Ôö´ó£¬ËµÃ÷ƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬ËµÃ÷Õý·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬¡÷H£¼0¡£
¢Ú ·´Ó¦¿ªÊ¼µ½10minʱ£¬c(C1NO)=1mol/L£¬Ôòv(C1NO)= 1mol/L¡Â10min=0.1mol/(L¡¤min)£¬ÔòNOµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=v(C1NO)=0.1mol/(L¡¤min)
¢Û 2NO(g)+Cl2(g)2ClNO(g)
Æðʼ(mol/L) 2 1 0
·´Ó¦(mol/L) 1 0.5 1
ƽºâ(mol/L) 1 0.5 1
ËùÒÔT2ʱ¸Ã·´Ó¦µÄƽºâ³£ÊýK==12/12¡Á0.5=2¡£
£¨4£©n(NO)/n(C12)µÄ±ÈֵԽС£¬ËµÃ÷Èôn(NO)²»±ä£¬n(C12) Ô½´ó£¬ËùÒÔNOµÄת»¯ÂÊÔ½´ó£¬NOµÄת»¯ÂÊ×î´óµÄÊÇAµã¡£
¡¾ÌâÄ¿¡¿¿ØÖƱäÁ¿ÊÇ¿ÆѧÑо¿µÄÖØÒª·½·¨¡£ÏàͬÖÊÁ¿µÄÂÁÓë×ãÁ¿1 mol¡¤L-1ÑÎËá·Ö±ðÔÚÏÂÁÐÌõ¼þÏ·¢Éú·´Ó¦£¬¿ªÊ¼½×¶Î»¯Ñ§·´Ó¦ËÙÂÊ×î´óµÄÊÇ(¡¡¡¡)
Ñ¡Ïî | ÂÁµÄ״̬ | ʵÑéζÈ/¡æ |
A | Ƭ״ | 20 |
B | Ƭ״ | 30 |
C | ·ÛÄ© | 20 |
D | ·ÛÄ© | 30 |
A.AB.BC.CD.D