ÌâÄ¿ÄÚÈÝ
I¡¢Ä³Í¬Ñ§Éè¼ÆʵÑ齫Fe3O4ºÍCuO×é³ÉµÄ»ìºÏÎïX½øÐÐÈçͼËùʾµÄת»¯£¨Ã¿Ò»²½¾ù·´Ó¦ÍêÈ«£©
£¨1£©Éú³ÉÆøÌåBµÄ»¯Ñ§·½³ÌʽÊÇ____________________________¡£
£¨2£©½«¹ÌÌåDͶÈë¹ýÁ¿Ï¡ÁòËá²¢³ä·Ö·´Ó¦ºó£¬¹ýÂË£¬ÔÙÏòÂËÒº¼ÓÈëË«ÑõË®£¬µÃ»ÆÉ«ÈÜÒº¡£ д³öµ±¼ÓÈëË«ÑõˮʱÈÜÒºÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º________________________ ¡£
£¨3£©ÈôÒÑÖª¹ÌÌåXµÄÖÊÁ¿Îª7£®2g·´Ó¦ÖÐAl·ÛµÄÖÊÁ¿ÊÇ2£®7g£¬ÆøÌåBÔÚ±ê×¼×´¿öϵÄÌå»ýΪ672mL£¬Ôò¹ÌÌåDµÄÖÊÁ¿ÊÇ____________ g£®
II¡¢»ìºÏÎïAÓÉ̼ËáÄƺÍ̼ËáÇâÄÆ×é³É¡£ÏÖÓÐÁ½°üÖÊÁ¿ÏàµÈµÄ»ìºÏÎïA£º
£¨4£©ÈôÏòÆäÖÐÒ»°ü¼ÓÈë100mL 3mol/LµÄBa(OH)2ÈÜÒº£¨¹ýÁ¿£©£¬Ê¹HCO3-¡¢CO32-È«²¿±äΪ³Áµí£¬¹ýÂ˺ó£¬ÔÙÏòÂËÒºÖмÓÈë200mL 2mol/LµÄÏ¡ÑÎËᣬÈÜҺǡºÃ³ÊÖÐÐÔ¡£
¢Ùд³öÏÂÁз´Ó¦µÄÀë×Ó·½³Ìʽ
̼ËáÇâÄÆÓë¹ýÁ¿ÇâÑõ»¯±µµÄ·´Ó¦£º____________________________£»
¢Ú»ìºÏÎïAÖÐNaHCO3µÄÖÊÁ¿Îª____________________g¡£
£¨5£©ÈôÏòÁíÒ»°üÖÐÏȼÓ50mL8mol/LµÄHClÈÜÒº£¬Ê¹HCO3-¡¢CO32-È«²¿±äΪCO2ºó£¬ÔÙ¼Ó50mL2mol/LµÄ
Ba(OH)2ÈÜÒº£¬»ìºÏºóµÄÈÜÒºpH=14£¨»ìºÏºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ¡¢ÔÚ³£ÎÂÏ£©¡£»ìºÏÎïAÖÐNa2CO3µÄÖÊÁ¿Îª_______________g¡£
£¨2£©½«¹ÌÌåDͶÈë¹ýÁ¿Ï¡ÁòËá²¢³ä·Ö·´Ó¦ºó£¬¹ýÂË£¬ÔÙÏòÂËÒº¼ÓÈëË«ÑõË®£¬µÃ»ÆÉ«ÈÜÒº¡£ д³öµ±¼ÓÈëË«ÑõˮʱÈÜÒºÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º________________________ ¡£
£¨3£©ÈôÒÑÖª¹ÌÌåXµÄÖÊÁ¿Îª7£®2g·´Ó¦ÖÐAl·ÛµÄÖÊÁ¿ÊÇ2£®7g£¬ÆøÌåBÔÚ±ê×¼×´¿öϵÄÌå»ýΪ672mL£¬Ôò¹ÌÌåDµÄÖÊÁ¿ÊÇ____________ g£®
II¡¢»ìºÏÎïAÓÉ̼ËáÄƺÍ̼ËáÇâÄÆ×é³É¡£ÏÖÓÐÁ½°üÖÊÁ¿ÏàµÈµÄ»ìºÏÎïA£º
£¨4£©ÈôÏòÆäÖÐÒ»°ü¼ÓÈë100mL 3mol/LµÄBa(OH)2ÈÜÒº£¨¹ýÁ¿£©£¬Ê¹HCO3-¡¢CO32-È«²¿±äΪ³Áµí£¬¹ýÂ˺ó£¬ÔÙÏòÂËÒºÖмÓÈë200mL 2mol/LµÄÏ¡ÑÎËᣬÈÜҺǡºÃ³ÊÖÐÐÔ¡£
¢Ùд³öÏÂÁз´Ó¦µÄÀë×Ó·½³Ìʽ
̼ËáÇâÄÆÓë¹ýÁ¿ÇâÑõ»¯±µµÄ·´Ó¦£º____________________________£»
¢Ú»ìºÏÎïAÖÐNaHCO3µÄÖÊÁ¿Îª____________________g¡£
£¨5£©ÈôÏòÁíÒ»°üÖÐÏȼÓ50mL8mol/LµÄHClÈÜÒº£¬Ê¹HCO3-¡¢CO32-È«²¿±äΪCO2ºó£¬ÔÙ¼Ó50mL2mol/LµÄ
Ba(OH)2ÈÜÒº£¬»ìºÏºóµÄÈÜÒºpH=14£¨»ìºÏºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ¡¢ÔÚ³£ÎÂÏ£©¡£»ìºÏÎïAÖÐNa2CO3µÄÖÊÁ¿Îª_______________g¡£
£¨1£©2Al+2NaOH+2H2O==2NaAlO2+3H2¡ü
£¨2£©2Fe2++H2O2+2H+==2Fe2++2H2O
£¨3£©5.28
£¨4£©¢Ù£»¢Ú16.8g
£¨5£©5.3g
£¨2£©2Fe2++H2O2+2H+==2Fe2++2H2O
£¨3£©5.28
£¨4£©¢Ù£»¢Ú16.8g
£¨5£©5.3g
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿