ÌâÄ¿ÄÚÈÝ
ijͬѧΪÁ˲ⶨÈý¾ÛÇè°·µÄ·Ö×ÓʽºÍ½á¹¹¼òʽ£¬Éè¼ÆÁËÈçÏÂʵÑé
²éÔÄ×ÊÁÏ£ºÈý¾ÛÇè°·µÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª126£¬Èý¾ÛÇè°·ÔÚ³£ÎÂϳʾ§Ì壬ÔÚ¼ÓÈÈÌõ¼þÏÂÄÜÓëÑõÆø·¢Éú·´Ó¦Éú³É¶þÑõ»¯Ì¼¡¢µªÆøºÍË®¡£È¡12.6 gµÄÈý¾ÛÇè°·¾§Ìå°´ÈçͼװÖýøÐÐʵÑ飨¼ÙÉèÈý¾ÛÇè°·ÍêÈ«·´Ó¦×ª»¯³É²úÎ¡£
£¨1£©Ð´³öA×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________¡££¨Ò»¸ö¼´¿É£©¡£
£¨2£©µ±C×°ÖÃÖз´Ó¦ÍêÈ«·¢Éúºó£¬¶ÁÈ¡HÖÐË®µÄÌå»ýµÄʵÑé²Ù×÷˳ÐòΪ___________¡££¨ÌîÐòºÅ£©
¢Ù¶ÁÊý ¢ÚÀäÈ´ÖÁÊÒΠ¢Ûµ÷ƽG¡¢H×°ÖÃÖеÄÒºÃæ
£¨3£©²â¶¨Êý¾ÝÈçÏ£º
£¨1£©Ð´³öA×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________¡££¨Ò»¸ö¼´¿É£©¡£
£¨2£©µ±C×°ÖÃÖз´Ó¦ÍêÈ«·¢Éúºó£¬¶ÁÈ¡HÖÐË®µÄÌå»ýµÄʵÑé²Ù×÷˳ÐòΪ___________¡££¨ÌîÐòºÅ£©
¢Ù¶ÁÊý ¢ÚÀäÈ´ÖÁÊÒΠ¢Ûµ÷ƽG¡¢H×°ÖÃÖеÄÒºÃæ
£¨3£©²â¶¨Êý¾ÝÈçÏ£º
¾²â¶¨£¬GÖÐÊÕ¼¯µÄÆøÌåÕۺϱê×¼×´¿öϵÄÌå»ýΪ6.72 L¡£
¢ÙÀûÓÃÉÏÊöʵÑéÊý¾Ý£¬¼ÆËãÈý¾ÛÇè°·µÄʵÑéʽΪ______________¡£
¢ÚÈý¾ÛÇè°·µÄ·Ö×ÓʽΪ______________¡£
¢ÛÈôD×°ÖÃÑ¡ÓÃÏÂÁвÄÁÏ´úÌæÍÍø£¬¿ÉÑ¡ÓÃ___________£¨ÌîÐòºÅ£©
A. CuO B. Mg C. Ag D. C
£¨4£©ÒÑÖªÇâÇèËᣨHCN£©µÄ½á¹¹¼òʽΪH£C¡ÔN£¬Èý¾ÛÇè°··Ö×ÓÀàËÆÓÚ±½·Ö×ӽṹ£¬Ã¿¸öÔ×Ó×îÍâ²ãµç×ÓÊý¾ù´ïµ½8µç×Ó»ò2µç×ӽṹ£¬ÊÔд³öÆä½á¹¹¼òʽ£º______________¡£
£¨5£©Èý¾ÛÇè°··Ö×ÓÖÐËùÓÐÔ×Ó_______£¨ÌîÊÇ¡¢·ñ£©¹²Æ½Ãæ¡£
¢ÙÀûÓÃÉÏÊöʵÑéÊý¾Ý£¬¼ÆËãÈý¾ÛÇè°·µÄʵÑéʽΪ______________¡£
¢ÚÈý¾ÛÇè°·µÄ·Ö×ÓʽΪ______________¡£
¢ÛÈôD×°ÖÃÑ¡ÓÃÏÂÁвÄÁÏ´úÌæÍÍø£¬¿ÉÑ¡ÓÃ___________£¨ÌîÐòºÅ£©
A. CuO B. Mg C. Ag D. C
£¨4£©ÒÑÖªÇâÇèËᣨHCN£©µÄ½á¹¹¼òʽΪH£C¡ÔN£¬Èý¾ÛÇè°··Ö×ÓÀàËÆÓÚ±½·Ö×ӽṹ£¬Ã¿¸öÔ×Ó×îÍâ²ãµç×ÓÊý¾ù´ïµ½8µç×Ó»ò2µç×ӽṹ£¬ÊÔд³öÆä½á¹¹¼òʽ£º______________¡£
£¨5£©Èý¾ÛÇè°··Ö×ÓÖÐËùÓÐÔ×Ó_______£¨ÌîÊÇ¡¢·ñ£©¹²Æ½Ãæ¡£
£¨1£©2Na2O2+2H2O=4NaOH+O2¡ü»ò2H2O2
2H2O+O2¡ü
£¨2£©¢Ú¢Û¢Ù
£¨3£©¢ÙCN2H2£»¢ÚC3N6H6£»¢ÛC
£¨4£©
£¨5£©·ñ
£¨2£©¢Ú¢Û¢Ù
£¨3£©¢ÙCN2H2£»¢ÚC3N6H6£»¢ÛC
£¨4£©
£¨5£©·ñ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿