ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿20¡æʱÏò10mL0.1mol¡¤L-1´×ËáÈÜÒºÖв»¶ÏµÎÈë0.1mol¡¤L-1NaOHÈÜÒº£¬ÈÜÒºpH±ä»¯ÈçͼËùʾ¡£´Ë¹ý³ÌÀïÈÜÒºÖÐÀë×ÓŨ¶ÈµÄ¹Øϵ´íÎóµÄÊÇ
A. aµã£ºc(Na+)>c(CH3COO-)>c(OH-)>c(H+)
B. bµã£º c(H+)= c(CH3COOH)+c(OH-)
C. cµã£ºc(Na+)= c(CH3COO-)>c(H+)=c(OH-)
D. dµã£ºc(CH3COO-)>c(Na+)>c(H+)>c(OH-)
¡¾´ð°¸¡¿B
¡¾½âÎö¡¿A£®aµãΪNaOHºÍCH3COONaµÄ»ìºÏÎÇÒ2c£¨NaOH£©=c£¨CH3COONa£©£¬ÈÜÒº³Ê¼îÐÔ£¬´×Ëá¸ùÀë×ÓË®½âµ«Ë®½â³Ì¶È½ÏС£¬ËùÒÔÈÜÒºÖÐÀë×ÓŨ¶È´óС˳ÐòÊÇc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©£¬¹ÊAÕýÈ·£»B£®bµãʱ£¬ÈÜÒº³Ê¼îÐÔ£¬Ó¦ÓÐc£¨H+£©£¼c£¨OH-£©£¬¹ÊB´íÎó£»C£®¸ù¾ÝÈÜÒºµçºÉÊغã¿ÉÖªÈÜÒºÖÐÓ¦´æÔÚc£¨Na+£©+c£¨H+£©=c£¨CH3COO-£©+c£¨OH-£©£¬ÈÜÒº³ÊÖÐÐÔ£¬Ó¦ÓÐc£¨H+£©=c£¨OH-£©£¬Ôòc£¨Na+£©=c£¨CH3COO-£©£¬ËùÒÔÈÜÒºÖÐÀë×ÓŨ¶È¹Øϵ£ºc£¨Na+£©=c£¨CH3COO-£©£¾c£¨H+£©=c£¨OH-£©£¬¹ÊCÕýÈ·£»D£®dµãʱ´×Ëá¹ýÁ¿£¬ÈÜҺΪCH3COOHºÍCH3COONaµÄ»ìºÏÎÈÜÒº³ÊËáÐÔ£¬ËùÒÔc£¨H+£©£¾c£¨OH-£©£¬ÈÜÒº³ÊµçÖÐÐÔ£¬c£¨Na+£©+c£¨H+£©=c£¨CH3COO-£©+c£¨OH-£©£¬ËùÒÔc£¨Na+£©£¼c£¨CH3COO-£©£¬Ôòc£¨CH3COO-£©£¾c£¨Na+£©£¾c£¨H+£©£¾c£¨OH-£©£¬¹ÊDÕýÈ·£»¹ÊÑ¡B¡£
![](http://thumb2018.1010pic.com/images/loading.gif)