ÌâÄ¿ÄÚÈÝ

ΪÁË·ÀÖλ·¾³ÎÛȾ²¢¶ÔÎ²Æø½øÐÐ×ÛºÏÀûÓã¬Ä³ÁòËá³§Óð±Ë®ÎüÊÕÎ²ÆøÖеÄSO2£¬ÔÙÏòÎüÊÕÒºÖмÓÈëŨÁòËᣬÒÔÖÆÈ¡¸ßŨ¶ÈµÄSO2¼°£¨NH4£©2SO4ºÍNH4HSO4¹ÌÌå¡£

Ϊ²â¶¨ÉÏÊö£¨NH4£©2SO4ºÍNH4HSO4¹ÌÌå»ìºÏÎïµÄ×é³É£¬ÏÖ³ÆÈ¡¸ÃÑùÆ·ËÄ·Ý£¬·Ö±ð¼ÓÈëÏàͬŨ¶ÈµÄNaOHÈÜÒº¸÷40.00 mL£¬¼ÓÈÈÖÁ120 ¡æ ×óÓÒ£¬Ê¹°±ÆøÈ«²¿Òݳö£Û(NH4)2SO4ºÍNH4HSO4µÄ·Ö½âζȾù¸ßÓÚ200 ¡æ£Ý£¬²âµÃÓйØÊµÑéÊý¾ÝÈçÏ£¨±ê×¼×´¿ö£©£º

ʵÑéÐòºÅ

ÑùÆ·µÄÖÊÁ¿/g

NaOHÈÜÒºµÄÌå»ý/Ml

°±ÆøµÄÌå»ý/L

¢ñ

7.4

40.00

1.68

¢ò

14.8

40.00

3.36

¢ó

22.2

40.00

1.12

¢ô

37.0

40.00

0.00

£¨1£©ÊµÑé¹ý³ÌÖÐÓйط´Ó¦µÄÀë×Ó·½³ÌʽΪ

_____________________________________________________________________¡£

£¨2£©ÓÉ¢ñ×éÊý¾ÝÖ±½ÓÍÆ²â£º±ê×¼×´¿öÏÂ3.7 gÑùÆ·½øÐÐͬÑùʵÑéʱ£¬Éú³É°±ÆøµÄÌå»ýΪ_____________L¡£

£¨3£©ÊÔ¼ÆËã¸Ã»ìºÏÎïÖУ¨NH4£©2SO4ºÍNH4HSO4µÄÎïÖʵÄÁ¿Ö®±È¡£

£¨4£©Óû¼ÆËã¸ÃNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈӦѡÔñµÚ____________×éÊý¾Ý£¬ÓÉ´ËÇóµÃNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ____________¡£

£¨1£©H++OH-====H2O£¬+OH-NH3¡ü+H2O

£¨2£©0.84

£¨3£©É裺7.4 gÑùÆ·ÖУ¨NH4£©2SO4µÄÎïÖʵÄÁ¿Îªx£¬NH4HSO4µÄÎïÖʵÄÁ¿Îªy£¬Ôò132 g¡¤mol-1¡¤x+115 g¡¤mol-1¡¤y=7.4 g

2x+y=1.68 L/22.4 L¡¤mol-1½âµÃ:x=0.012 5 mol

y=0.05 mol   n£Û(NH4)2SO4£Ý¡Ãn(NH4HSO4)=0.012 5 mol¡Ã0.05 mol=1¡Ã4

(4)¢ó  5.0 mol¡¤L-1

½âÎö£ºÓÉÊý¾Ý¢ñºÍ¢ò  7.4 g /1.68 L=14.8 g/3.36 L¿ÉÖª£ºµ±ÑùÆ·ÖÊÁ¿¡Ü14.8 gʱ£¬NaOH×ãÁ¿£¬¼´ÑùÆ·ÖÊÁ¿Óë°±ÆøÌå»ýÖ®±ÈΪ¶¨Öµ£¬Ôò£ºV£¨NH3£©=3.7 g¡Á1.68 L/7.4 g=0.84 L¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø