ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©ÈýÖÖ¶ÌÖÜÆÚÔªËØ£ø¡¢y¡¢£ú¶ÔÓ¦µÄµ¥ÖÊ X¡¢Y¡¢Z£¬³£Î³£Ñ¹Ï¾ùΪÎÞÉ«ÆøÌ壬ÔÚÊʵ±Ìõ¼þϵ¥ÖÊX¡¢Y¡¢ZÖ®¼ä¿ÉÒÔ·¢ÉúÈçÓÒͼËùʾµÄ±ä»¯¡£ÒÑÖªB·Ö×Ó×é³ÉÖУúÔ­×Ó¸öÊý±ÈC·Ö×ÓÖÐÉÙÒ»¸ö¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÔªËØ£øµÄÔ­×ӽṹʾÒâͼ          £»ÔªËØyÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ             £»

£¨2£©ÒÑÖªCµÄŨÈÜÒºÓëŨÑÎËáÏàÓö¿É²úÉú°×ÑÌ£¬Ð´³ö°×Ñ̳ɷֵĵç×Óʽ£º                     ¡£

£¨3£©CÓëXÔÚÒ»¶¨Ìõ¼þÏÂÉú³É»¯ºÏÎïAµÄ»¯Ñ§·½³Ìʽ£º                         ¡£

£¨4£©Ò»¶¨Ìõ¼þÏ£¬AÓëC·´Ó¦¿ÉÉú³ÉYºÍB£¬Çëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£»²¢Óõ¥ÏßÇÅ·¨±ê³öµç×Ó×ªÒÆµÄ·½ÏòÓëÊýÄ¿¡£

                                               ¡£

£¨5£©Óõç×Óʽ±íʾBµÄÐγɹý³Ì                                           ¡£

 

¡¾´ð°¸¡¿

  £» µÚ¶þÖÜÆÚ  µÚVA×å         £¨2£© 

£¨3£©4NH3+5O24NO+6H2O     

£¨4£©4NH3+6NO£½5N2+6H2O      £¨·½³Ìʽ2·Ö£¬µ¥ÏßÇÅ·ÖÎö2·Ö£©

£¨5£©

¡¾½âÎö¡¿³£Î³£Ñ¹Ï¾ùΪÎÞÉ«ÆøÌåµÄ¶ÌÖÜÆÚÔªËØ×é³ÉµÄµ¥Öʳ£¼ûµÄÊÇÇâÆø¡¢ÑõÆø¡¢µªÆø¡£ËüÃÇÖ®¼ä»¯ºÏ·´Ó¦µÄÉú³ÉÎïΪH2O¡¢NO¡¢NH3¡£B·Ö×Ó×é³ÉÖУúÔ­×Ó¸öÊý±ÈC·Ö×ÓÖÐÉÙÒ»¸ö£¬ËùÒÔBÊÇË®£¬CÊǰ±Æø¡£ÔòZÊÇÇâÆø£¬YÊǵªÆø£¬XÊÇÑõÆø¡£°±ÆøºÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯ï§£¬ÊôÓÚÀë×Ó»¯ºÏÎº¬ÓÐÀë×Ó¼üºÍ¼«ÐÔ¼ü¡£ÔÚ´ß»¯¼ÁµÄ×÷ÓÃϰ±Æø¿ÉÒÔ·¢Éú´ß»¯Ñõ»¯Éú³ÉNOºÍË®¡£NO¾ßÓÐÑõ»¯ÐÔÄÜÑõ»¯°±ÆøÉú³ÉµªÆøºÍË®¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø