ÌâÄ¿ÄÚÈÝ

Ò»¶¨Ìõ¼þϽ«2.3 mol SO2ÆøÌåºÍ1.2 mol O2ÆøÌå³äÈëÒ»ÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖУ¬¿É»¬¶¯»îÈûµÄλÖÃÈçͼ1Ëùʾ£¬ÔÚºãκãѹÏ·¢ÉúÈçÏ·´Ó¦£º2SO2£¨g£©+ O2£¨g£©    2SO3£¨g£©£¬ÆäÖС÷H < 0 £¬µ±·´Ó¦´ïµ½Æ½ºâʱ£¬»îÈûλÖÃÈçͼ2Ëùʾ£º

£¨1£©Æ½ºâʱSO2ת»¯ÂÊΪ      £¨¼ÆËã½á¹û¾«È·ÖÁ1%£©£»
£¨2£©¸ÃÌõ¼þÏ·´Ó¦µÄƽºâ³£ÊýΪ    £¨±£ÁôÈýλÓÐЧÊý×Ö£©£»
£¨3£©ÌÖÂÛζȶԸ÷´Ó¦ÖÐSO2ת»¯ÂʵÄÓ°Ïì             ¡£

£¨1£©87% £»£¨2£© 1.11¡Á103£»£¨3£©Éý¸ßζȣ¬SO2ת»¯ÂʽµµÍ(ÆäËüºÏÀí´ð°¸Ò²¿É)

ÊÔÌâ·ÖÎö£ººãκãѹʱ£¬ÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬Æ½ºâʱÆøÌåÌå»ýΪ5L£¬ÎïÖʵÄÁ¿Îª2.5 mol,¸ù¾ÝƽºâÈý¶Îʽ£º2SO2£¨g£©+  O2£¨g£© 2SO3£¨g£©
Æðʼ 2.3         1.2          0
±ä»¯ 2X         X           2X
ƽºâ 2.3-2X     1.2- X        2X
2.3-2X + 1.2- X + 2X=2.5  X=1
ËùÒÔƽºâʱSO2ת»¯ÂÊ=2/2.3=0.87£¬Æ½ºâ³£Êý£½1.11¡Á103£»Éý¸ßζÈ,ƽºâÏò×óÒƶ¯,¶þÑõ»¯ÁòµÄת»¯ÂʼõС.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
»¯Ñ§·´Ó¦Ô­ÀíÔÚ¿ÆÑкÍÉú²úÖÐÓй㷺ӦÓá£
£¨1£©ÀûÓá°»¯Ñ§ÕôÆøתÒÆ·¨¡±ÖƱ¸TaS2¾§Ì壬·¢ÉúÈçÏ·´Ó¦£º
TaS2£¨s£©£«2I2£¨g£©TaI4£¨g£©£«S2£¨g£©¡¡¦¤H>0£¨I£©
·´Ó¦£¨¢ñ£©µÄƽºâ³£Êý±í´ïʽK£½________£¬ÈôK£½1£¬ÏòijºãÈÝÈÝÆ÷ÖмÓÈë1 mol I2£¨g£©ºÍ×ãÁ¿TaS2£¨s£©£¬I2£¨g£©µÄƽºâת»¯ÂÊΪ________¡£
£¨2£©ÈçͼËùʾ£¬·´Ó¦£¨¢ñ£©ÔÚʯӢÕæ¿Õ¹ÜÖнøÐУ¬ÏÈÔÚζÈΪT2µÄÒ»¶Ë·ÅÈëδÌá´¿µÄTaS2·ÛÄ©ºÍÉÙÁ¿I2£¨g£©£¬Ò»¶Îʱ¼äºó£¬ÔÚζÈΪT1µÄÒ»¶ËµÃµ½ÁË´¿¾»TaS2¾§Ì壬ÔòζÈT1________T2£¨Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£©¡£ÉÏÊö·´Ó¦ÌåϵÖÐÑ­»·Ê¹ÓõÄÎïÖÊÊÇ________¡£

£¨3£©ÀûÓÃI2µÄÑõ»¯ÐԿɲⶨ¸ÖÌúÖÐÁòµÄº¬Á¿¡£×ö·¨Êǽ«¸ÖÑùÖеÄÁòת»¯³ÉH2SO3£¬È»ºóÓÃÒ»¶¨Å¨¶ÈµÄI2ÈÜÒº½øÐе樣¬ËùÓÃָʾ¼ÁΪ________£¬µÎ¶¨·´Ó¦µÄÀë×Ó·½³ÌʽΪ______________________¡£
£¨4£©25¡æʱ£¬H2SO3HSO3-£«H£«µÄµçÀë³£ÊýKa£½1¡Á10£­2mol¡¤L£­1£¬Ôò¸ÃζÈÏÂNaHSO3Ë®½â·´Ó¦µÄƽºâ³£ÊýKh£½________mol¡¤L£­1£¬ÈôÏòNaHSO3ÈÜÒºÖмÓÈëÉÙÁ¿µÄI2£¬ÔòÈÜÒºÖн«________£¨Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø