ÌâÄ¿ÄÚÈÝ


½ðÊôÂÁÖÊÇáÇÒÓÐÁ¼ºÃµÄ·À¸¯Ê´ÐÔ£¬ÔÚ¹ú·À¹¤ÒµÖÐÓзdz£ÖØÒªµÄ×÷Óá£ÇëÍê³ÉÏÂÁпհףº

 (1)ÔÚ19ÊÀ¼Íʱ£¬ÂÁÊÇÒ»ÖÖÕä¹óµÄ½ðÊô¡£ÈËÃÇ×î³õµÃµ½µÄÂÁÁ£ÈçͬÕ䱦£¬ËüµÄ¼Û¸ñͬ»Æ½ðÏ൱¡£1827Ä꣬µÂ¹ú»¯Ñ§¼ÒάÀÕÓýðÊô¼ØÓëÎÞË®ÂÈ»¯ÂÁ·´Ó¦¶øÖƵÃÁ˽ðÊôÂÁ¡£ÓüØÓëÎÞË®ÂÈ»¯ÂÁ·´Ó¦ÖÆÂÁ¶ø²»ÓÃÂÈ»¯ÂÁÈÜÒºµÄÀíÓÉÊÇ_________¡£ ÏÖ´ú¹¤ÒµÁ¶ÂÁµÄÔ­ÁÏÊÇÓÉÂÁÍÁ¿óÌáÈ¡¶øµÃ£¬ÔÚÌáÈ¡¹ý³ÌÖÐͨÈëµÄÆøÌåΪ____¡£

(2)»ð¼ýºÍµ¼µ¯±íÃæµÄ±¡²ãÊÇÄ͸ßÎÂÎïÖÊ¡£½«Ê¯Ä«¡¢ÂÁ·ÛºÍ¶þÑõ»¯îÑ°´Ò»¶¨±ÈÀý»ìºÏÔÚ¸ßÎÂÏÂìÑÉÕ£¬ËùµÃÎïÖÊ¿É×÷Ä͸ßβÄÁÏ£¬4Al(s)+3TiO2£¨s£©+3C(s) 2Al2O3(s)+3TiC(s)

-1176 kJ¡¤mol-1£¬·´Ó¦¹ý³ÌÖУ¬Ã¿×ªÒÆ1 molµç×ӷųöµÄÈÈÁ¿Îª________¡£

(3)¹èÓëÂÁͬÖÜÆÚ£¬µØ¿ÇÀï¹èÂÁµÄº¬Á¿Êǹè________ÂÁ£¨Ìî>£¬<»ò=£©£» Na2CaSi6O14ÊǹèËáÑβ£Á§µÄÖ÷Òª³É·Ö£¬Na2CaSi6O14Ò²¿Éд³ÉNa2O¡¤CaO¡¤6SiO2¡£Ê¢·ÅNaOHÈÜÒºµÄÊÔ¼ÁÆ¿ÈôÓò£Á§Æ¿ÈûÈÝÒ×ÐγÉÕ³ÐԵĹèËáÑζøÎÞ·¨´ò¿ª£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ ________¡£³¤Ê¯ÊÇÂÁ¹èÑÎËᣬ²»Í¬À೤ʯÆäÑõÔ­×ÓµÄÎïÖʵÄÁ¿·ÖÊýÏàͬ¡£ÓÉÄƳ¤Ê¯»¯Ñ§Ê½NaAlSi3O8¿ÉÍÆÖª¸Æ³¤Ê¯µÄ»¯Ñ§Ê½Îª________¡£

¸ßÎÂ

 
(4)ÓÃÂÁºÍ½ðÊôÑõ»¯Îï·´Ó¦ÖƱ¸½ðÊôµ¥ÖÊÊǹ¤ÒµÉϽϳ£Óõķ½·¨¡£È磺2Al+4BaO3Ba¡ü+BaO¡¤Al2O3, Óû¯Ñ§Æ½ºâÒƶ¯Ô­Àí½âÊÍÉÏÊö·½·¨¿ÉÖÆÈ¡½ðÊôBaµÄÔ­ÒòÊÇ_______________________________.     


£¨1£©¼ØÏÈÓëË®·´Ó¦Éú³ÉKOH£¬KOHÔÙÓëÂÈ»¯ÂÁ·´Ó¦Éú³ÉÇâÑõ»¯ÂÁ£¬ÎÞ·¨µÃµ½µ¥ÖÊÂÁ£¨2·Ö£©£»  CO2£¨2·Ö£©

£¨2£©98 kJ£¨2·Ö£©

£¨3£©£¾£¨2·Ö£©£»  SiO2£«2NaOH£½Na2SiO3£«H2O£¨2·Ö£©£» CaAl2Si2O8 £¨2·Ö£©

£¨4£©ÀûÓÃBaµÄ·Ðµã±ÈAlµÄµÍ£¬BaÒÔÆøÌåÒݳö£¬Ê¹Æ½ºâÓÒÒÆ¡££¨2·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø