ÌâÄ¿ÄÚÈÝ

ÏÖÓг£ÎÂϵÄÁù·ÝÈÜÒº£º¢Ù0.01mol/LCH3COOHÈÜÒº£»¢Ú0.01mol/LHClÈÜÒº£»¢ÛpH=12µÄ°±Ë®£»¢ÜpH=12µÄNaOHÈÜÒº£»¢Ý0.01mol/LCH3COOHÈÜÒºÓëpH=12µÄ°±Ë®µÈÌå»ý»ìºÏºóËùµÃÈÜÒº£»¢Þ0.01mol/LHClÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒº¡£

£¨1£©ÆäÖÐË®µÄµçÀë³Ì¶È×î´óµÄÊÇ           £¨Ñ¡ÌîÐòºÅ£¬ÏÂͬ£©£¬Ë®µÄµçÀë³Ì¶ÈÏàͬµÄÊÇ            £»

£¨2£©Èô½«¢Ú¡¢¢Û»ìºÏºóËùµÃÈÜÒº pH=7£¬ÔòÏûºÄÈÜÒºµÄÌå»ý£º¢Ú       ¢Û£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©£»Èô½«¢Ú¡¢¢ÛÈÜÒºµÈÌå»ý»ìºÏºó£¬ËùµÃÈÜÒº pH        7£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©¡£

£¨3£©Èô½«¢Ù¡¢¢ÜÈÜÒº°´Ìå»ý±ÈΪ2£º1»ìºÏºó£¬ËùµÃÈÜÒº pH        7£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©´ËʱÈÜÒºÖгýË®·Ö×ÓÍâµÄ¸÷΢Á£µÄŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                                                      £»

½«¢Ù¡¢¢Ü»ìºÏ£¬ÈôÓÐc(CH3COO£­)£¾c(H£«)£¬Ôò»ìºÏÒº¿ÉÄܳʠ             £¨ÌîÐòºÅ£©¡£

A£®ËáÐÔ                  B£®¼îÐÔ                       C£®ÖÐÐÔ  

£¨1£©¢Þ(1·Ö)       ¢Ú¢Û¢Ü   2·Ö)                    £¨2£©£¾(1·Ö)       £¾(1·Ö)

£¨3£©£¼(1·Ö)    c(CH3COO£­£¾c(Na+)£¾c(CH3COOH) £¾c(H+) £¾c(OH£­)    (2·Ö)             ABC (2·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨¢ñ£©³£ÎÂϽ«Ìå»ýΪv1¡¢Å¨¶ÈΪc1µÄÒ»ÔªËáHAÓëÌå»ýΪv2¡¢Å¨¶ÈΪc2µÄÒ»Ôª¼îMOH»ìºÏ£®£¨1£©Èôv1?c1=v2?c2£¬»ìºÏºóµÄÈÜÒºpH£¾7£¬ÔòÒ»ÔªÈõËáµÄµçÀë³Ì¶È
£¼
£¼
£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©Ò»ÔªÈõ¼îµÄµçÀë³Ì¶È£»
£¨2£©Èôv1=v2£¬Ò»ÔªÈõ¼îµÄµçÀë³Ì¶È´óÓÚÒ»ÔªÈõËáµÄµçÀë³Ì¶È£¬ÇÒ»ìºÏºóÈÜÒºpH£¼7£¬Ôòc1
£¾
£¾
c2
£¨¢ò£©ÏÖÓг£ÎÂϵÄÁù·ÝÈÜÒº£º¢Ù0.01mol/LCH3COOHÈÜÒº£»¢Ú0.01mol/LHClÈÜÒº£»¢ÛpH=12µÄ°±Ë®£»¢ÜpH=12µÄNaOHÈÜÒº£»¢Ý0.01mol/LCH3COOHÈÜÒºÓë0.01mol/LµÄ°±Ë®µÈÌå»ý»ìºÏºóËùµÃÈÜÒº£»¢Þ0.01mol/LHClÈÜÒºÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏËùµÃÈÜÒº£®
£¨1£©ÆäÖÐË®µÄµçÀë³Ì¶È×î´óµÄÊÇ
¢Ý
¢Ý
£¨Ñ¡ÌîÐòºÅ£¬ÏÂͬ£©£¬Ë®µÄµçÀë³Ì¶ÈÏàͬµÄÊÇ
¢Ú¢Û¢Ü
¢Ú¢Û¢Ü
£»
£¨2£©Èô½«¢Ú¡¢¢Û»ìºÏºóËùµÃÈÜÒºpH=7£¬ÔòÏûºÄÈÜÒºµÄÌå»ý£º¢Ú
£¾
£¾
¢Û£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£»
£¨3£©½«Áù·ÝÈÜҺϡÊÍÏàͬ±¶Êýºó£¨²»¿¼ÂǼ«¶ÈÏ¡ÊÍ£©£¬ÈÜÒºµÄpH£º¢Ù
£¾
£¾
¢Ú£¬¢Û
£¾
£¾
¢Ü£¬¢Ý
=
=
¢Þ£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£»
£¨4£©½«¢Ù¡¢¢Ü»ìºÏ£¬ÈôÓÐc£¨CH3COO-£©£¾c£¨H+£©£¬Ôò»ìºÏÒº¿ÉÄܳÊ
ABC
ABC
£®
A£®ËáÐÔ   B£®¼îÐÔ  C£®ÖÐÐÔ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø