ÌâÄ¿ÄÚÈÝ
(9·Ö)¢å½ð¸ÕʯºÍʯī¾ùΪ̼µÄͬËØÒìÐÎÌ壬ËüÃÇȼÉÕÑõÆø²»×ãʱÉú³ÉÒ»Ñõ»¯Ì¼£¬³ä·ÖȼÉÕʱÉú³É¶þÑõ»¯Ì¼£¬·´Ó¦ÖзųöµÄÈÈÁ¿ÈçͼËùʾ£º
¢ÅµÈÁ¿½ð¸ÕʯºÍʯīÍêȫȼÉÕ__________£¨Ìî¡°½ð¸Õʯ¡±»ò¡°Ê¯Ä«¡±£©·Å³öÈÈÁ¿¸ü¶à£¬Ð´³ö±íʾʯīȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ ______________________________ £»
¢ÆÔÚͨ³£×´¿öÏ£¬½ð¸ÕʯºÍʯīÏà±È________£¨Ìî¡°½ð¸Õʯ¡±»ò¡°Ê¯Ä«¡±£©¸üÎȶ¨£¬Ð´³öʯīת»¯Îª½ð¸ÕʯµÄÈÈ»¯Ñ§·½³Ìʽ __________________________ £»
¢Ç12gʯīÔÚÒ»¶¨Á¿¿ÕÆøÖÐȼÉÕ£¬Éú³ÉÆøÌå36g£¬¸Ã¹ý³Ì·Å³öµÄÈÈÁ¿ ¡£
¢æ¢Å¼ÒÓÃÒº»¯ÆøÖÐÖ÷Òª³É·ÖÖ®Ò»ÊǶ¡Íé¡£µ±1g¶¡ÍéÍêȫȼÉÕ²¢Éú³ÉCO2ºÍҺ̬ˮʱ£¬·Å³öÈÈÁ¿50KJ¡£ÊÔд³ö¶¡ÍéȼÉÕ·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ £»
¢ÆÒÑÖªº¬KOH 28.0gÏ¡ÈÜÒºÓë×ãÁ¿Ï¡ÁòËá·´Ó¦£¬·Å³ö28.65KJµÄÈÈÁ¿£¬ÊÔд³ö¸Ã·´Ó¦ÖкÍÈȵÄÈÈ»¯Ñ§·½³Ìʽ ¡£
¢ÅµÈÁ¿½ð¸ÕʯºÍʯīÍêȫȼÉÕ__________£¨Ìî¡°½ð¸Õʯ¡±»ò¡°Ê¯Ä«¡±£©·Å³öÈÈÁ¿¸ü¶à£¬Ð´³ö±íʾʯīȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ ______________________________ £»
¢ÆÔÚͨ³£×´¿öÏ£¬½ð¸ÕʯºÍʯīÏà±È________£¨Ìî¡°½ð¸Õʯ¡±»ò¡°Ê¯Ä«¡±£©¸üÎȶ¨£¬Ð´³öʯīת»¯Îª½ð¸ÕʯµÄÈÈ»¯Ñ§·½³Ìʽ __________________________ £»
¢Ç12gʯīÔÚÒ»¶¨Á¿¿ÕÆøÖÐȼÉÕ£¬Éú³ÉÆøÌå36g£¬¸Ã¹ý³Ì·Å³öµÄÈÈÁ¿ ¡£
¢æ¢Å¼ÒÓÃÒº»¯ÆøÖÐÖ÷Òª³É·ÖÖ®Ò»ÊǶ¡Íé¡£µ±1g¶¡ÍéÍêȫȼÉÕ²¢Éú³ÉCO2ºÍҺ̬ˮʱ£¬·Å³öÈÈÁ¿50KJ¡£ÊÔд³ö¶¡ÍéȼÉÕ·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ £»
¢ÆÒÑÖªº¬KOH 28.0gÏ¡ÈÜÒºÓë×ãÁ¿Ï¡ÁòËá·´Ó¦£¬·Å³ö28.65KJµÄÈÈÁ¿£¬ÊÔд³ö¸Ã·´Ó¦ÖкÍÈȵÄÈÈ»¯Ñ§·½³Ìʽ ¡£
£¨Ò»£©£¨1£©½ð¸Õʯ£»C£¨Ê¯Ä«£¬s£©£«O2(g)£½CO2(g) ¡÷H£½£393.5kJ/mol
£¨2£©Ê¯Ä«£»C£¨Ê¯Ä«£¬s£©£½C£¨½ð¸Õʯ£¬s£© ¡÷H£½£«9.1kJ/mol £¨3£©252.0kJ
£¨¶þ£©£¨1£©C4H10(g)£«13/2O2(g)£½4CO2(g)£«5H2O(l) ¦¤H£½£2900kJ/mol
£¨2£©1/2H2SO4(aq)£«KOH(aq)£½1/2K2SO4(aq)£«H2O(l) ¦¤H£½£57.3kJ/mol
£¨2£©Ê¯Ä«£»C£¨Ê¯Ä«£¬s£©£½C£¨½ð¸Õʯ£¬s£© ¡÷H£½£«9.1kJ/mol £¨3£©252.0kJ
£¨¶þ£©£¨1£©C4H10(g)£«13/2O2(g)£½4CO2(g)£«5H2O(l) ¦¤H£½£2900kJ/mol
£¨2£©1/2H2SO4(aq)£«KOH(aq)£½1/2K2SO4(aq)£«H2O(l) ¦¤H£½£57.3kJ/mol
ÊÔÌâ·ÖÎö£º£¨Ò»£©£¨1£©¸ù¾ÝͼÏñ¿ÉÖª£¬½ð¸ÕʯµÄ×ÜÄÜÁ¿¸ßÓÚʯīµÄ×ÜÄÜÁ¿£¬ËùÒÔµÈÁ¿½ð¸ÕʯºÍʯīÍêȫȼÉÕ½ð¸Õʯ·Å³öÈÈÁ¿¸ü¶à¡£¸ù¾ÝͼÏñ¿ÉÖª£¬1molʯīÍêȫȼÉշųöµÄÈÈÁ¿ÊÇ110.5kJ£«283.0kJ£½393.5kJ£¬ËùÒÔʯīȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽÊÇC£¨Ê¯Ä«£¬s£©£«O2(g)£½CO2(g) ¡÷H£½£393.5kJ/mol¡£
£¨2£©½ð¸ÕʯµÄ×ÜÄÜÁ¿¸ßÓÚʯīµÄ×ÜÄÜÁ¿£¬ËùÒÔʯī±È½ð¸ÕʯÎȶ¨¡£¸ù¾ÝͼÏñ¿ÉÖª£¬1mol½ð¸Õʯת»¯ÎªÊ¯Ä«·Å³öµÄÄÜÁ¿ÊÇ395.4kJ£393.5kJ£½9.1kJ£¬ËùÒÔʯīת»¯Îª½ð¸ÕʯµÄÈÈ»¯Ñ§·½³ÌʽÊÇC£¨Ê¯Ä«£¬s£©£½C£¨½ð¸Õʯ£¬s£© ¡÷H£½£«9.1kJ/mol¡£
£¨3£©ÉèÉú³ÉµÄCOºÍCO2ÎïÖʵÄÁ¿·Ö±ðÊǺÍxºÍy£¬Ôòx£«y£½1mol¡¢28x£«44y£½36g£¬½âµÃx£½£½y£½0.5mol£¬ËùÒÔʵ¼Ê·Å³öµÄÈÈÁ¿ÊÇ£¨393.5kJ/mol£«110.5kJ/mol£©¡Á0.5mol£½252.0kJ¡£
£¨¶þ£©£¨1£©µ±1g¶¡ÍéÍêȫȼÉÕ²¢Éú³ÉCO2ºÍҺ̬ˮʱ£¬·Å³öÈÈÁ¿50KJ£¬Ôò1mol¶¡Íé¼´58g¶¡ÍéÍêȫȼÉշųöµÄÈÈÁ¿ÊÇ50KJ¡Á58£½2900kJ£¬ËùÒÔ·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇC4H10(g)£«13/2O2(g)£½4CO2(g)£«5H2O(l) ¦¤H£½£2900kJ/mol¡£
£¨2£©ÖкÍÈÈÊÇÔÚÒ»¶¨Ìõ¼þÏ£¬Ï¡ÈÜÒºÖУ¬Ç¿ËáºÍÇ¿¼î·´Ó¦Éú³É1molˮʱËù·Å³öµÄÈÈÁ¿¡£28gÇâÑõ»¯¼ØµÄÎïÖʵÄÁ¿ÊÇ0.5mol£¬ËùÒԸ÷´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ1/2H2SO4(aq)£«KOH(aq)£½1/2K2SO4(aq)£«H2O(l) ¦¤H£½£57.3kJ/mol¡£
µãÆÀ£º¸ÃÌâÊǸ߿¼Öеij£¼û¿¼µã£¬ÊôÓÚÖеÈÄѶȵÄÊÔÌâ¡£ÊÔÌâ»ù´¡ÐÔÇ¿£¬²àÖضÔѧÉú»ù´¡ÖªÊ¶µÄ¹®¹ÌÓëѵÁ·£¬ÓÐÖúÓÚÅàÑøѧÉúµÄÂß¼ÍÆÀíÄÜÁ¦ºÍÓ¦ÊÔÄÜÁ¦£¬Ìá¸ßѧÉúµÄѧϰЧÂÊ¡£¸ÃÌâµÄ¹Ø¼üÊÇÁ˽ⷴӦÈȵĺ¬Ò壬Ȼºó½áºÏͼÏñÁé»îÔËÓᢷÖÎö¡¢¼ÆËã¼´¿É¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿