ÌâÄ¿ÄÚÈÝ

(10·Ö)ʵÑéÊÒÏÖÐèÅäÖÆÎïÖʵÄÁ¿Å¨¶ÈΪ1 mol¡¤L£­1µÄNaOHÈÜÒº480 mL¡£

(1)ʵÑé¹ý³ÌÖÐÓõ½µÄ²£Á§ÒÇÆ÷ÓУºÉÕ±­¡¢Á¿Í²¡¢½ºÍ·µÎ¹Ü¡¢________¡¢________¡£

(2)ÒªÅäÖÆ´ËÈÜÒº£¬ÐèÒª³ÆÁ¿NaOH¹ÌÌåµÄÖÊÁ¿Îª________¡£

(3)ÅäÖƺõÄNaOHÈÜÒº²»ÄÜÓôøÄ¥¿Ú²£Á§ÈûµÄÊÔ¼ÁÆ¿´æ·Å£¬Çë½âÊÍÔ­Òò(Óû¯Ñ§·½³Ìʽ±íʾ)________________________________¡£

(4)Èô½«´ËÈÜÒº³¤ÆÚ±©Â¶ÔÚ¿ÕÆøÖУ¬×îÖÕת»¯Îª________£¬È¡Ò»¶¨Á¿µÄ¸ÃÎïÖÊÈÜÓÚË®ÅäÖƳɱ¥ºÍÈÜÒº£¬Í¨ÈëCO2ÆøÌåºó·¢ÏÖÈÜÒº±ä»ë×Ç£¬Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ

____________________________________¡£

 

¡¾´ð°¸¡¿

(1)500 mLÈÝÁ¿Æ¿¡¡²£Á§°ô

(2)20 g

(3)SiO2£«2NaOH===Na2SiO3£«H2O

(4)Na2CO3¡¡Na2CO3£«CO2£«H2O===2NaHCO3¡ý?

¡¾½âÎö¡¿ÊµÑéÊÒÈÝÁ¿Æ¿µÄÈÝÁ¿ÓÐ50 mL¡¢100 mL¡¢150 mL¡¢200 mL¡¢250 mL¡¢500 mL¡¢1 000 mLµÈ£¬ÁíÍâÐèҪעÒ⣬ËùÅäÈÜÒºÌå»ý´óÓÚËùÐèÈÜÒºÌå»ý£»NaOHÈÜÒºÄܸ¯Ê´²£Á§£¬¿ÉÓò£Á§Æ¿±£´æ£¬µ«²»ÄÜÓÃÄ¥¿Ú²£Á§Èû£»NaOHÈÜÒºÔÚ¿ÕÆøÖÐÎüÊÕCO2¶ø±ä³ÉNa2CO3£¬Na2CO3±¥ºÍÈÜÒºÖÐͨÈëCO2ÆøÌåºó£¬Éú³ÉÈܽâ¶È½ÏСµÄNaHCO3¾§Ì壬¶øʹÈÜÒº±ä»ë×Ç¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨10·Ö£¬Ã¿¿Õ2·Ö£©ÓÒͼΪʵÑéÊÒijŨÑÎËáÊÔ¼ÁÆ¿ÉϵıêÇ©£¬ÊÔ¸ù¾ÝÓйØÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ä³Ñ§ÉúÓûÓÃÉÏÊöŨÑÎËáºÍÕôÁóË®ÅäÖÆ500 mLÎïÖʵÄÁ¿Å¨¶ÈΪ0.30 mol/LÏ¡ÑÎËá¡£

¢Ù¸ÃѧÉúÐèÒªÁ¿È¡       mLÉÏÊöŨÑÎËá½øÐÐÅäÖÆ¡£

¢ÚÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ(ÓÃ×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î)                           ¡£

A.ÓÃ30mLˮϴµÓÉÕ±­2¡«3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿

B.ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèŨÑÎËáµÄÌå»ý£¬ÂýÂýÑر­±Ú×¢ÈëÊ¢ÓÐÉÙÁ¿Ë®£¨Ô¼30 mL£©µÄÉÕ±­ÖУ¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä»ìºÏ¾ùÔÈ

C.½«ÒÑÀäÈ´µÄÑÎËáÑز£Á§°ô×¢Èë500mLµÄÈÝÁ¿Æ¿ÖÐ

D.½«ÈÝÁ¿Æ¿µÄ²£Á§Èû¸Ç½ô£¬µßµ¹Ò¡ÔÈ

E.¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐ

F.¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦

¢ÛÔÚÅäÖƹý³ÌÖУ¬ÏÂÁвÙ×÷»áʹËùÅäÖƵÄÏ¡ÑÎËáÎïÖʵÄÁ¿Å¨¶ÈÆ«¸ßµÄÊÇ               ¡£

A.ÓÃÁ¿Í²Á¿È¡Å¨ÑÎËáʱ¸©Êӹ۲찼ҺÃæ

B.Ò¡ÔȺó£¬ÒºÃæϽµ£¬²¹³äË®

C.¶¨ÈÝʱÑöÊӿ̶ÈÏß

D.ÔÚÅäÖÆÇ°ÓÃÏàͬŨ¶ÈµÄÏ¡ÑÎËáÈóÏ´ÈÝÁ¿Æ¿

£¨2£©ÏÖ½«200mL0.30mol/LµÄÑÎËáÓë50mL0.80mol/LCaCl2ÈÜÒº»ìºÏ(»ìºÏºóÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¬ËùµÃÈÜÒºÖÐCl£­µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ          mol/L¡£

£¨3£©ÔÚ±ê×¼×´¿öÏ£¬½«_____________L HClÆøÌåÈÜÓÚ1000 mLË®ÖÐ(Ë®µÄÃܶÈΪ1 g/cm3)£¬ËùµÃÈÜÖÊÖÊÁ¿·ÖÊýΪ36.5%µÄÑÎËá¡£(±£ÁôСÊýµãºóһλ)

 

£¨10·Ö£¬Ã¿¿Õ2·Ö£©ÓÒͼΪʵÑéÊÒijŨÑÎËáÊÔ¼ÁÆ¿ÉϵıêÇ©£¬ÊÔ¸ù¾ÝÓйØÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ä³Ñ§ÉúÓûÓÃÉÏÊöŨÑÎËáºÍÕôÁóË®ÅäÖÆ500 mLÎïÖʵÄÁ¿Å¨¶ÈΪ0.30 mol/LÏ¡ÑÎËá¡£

¢Ù¸ÃѧÉúÐèÒªÁ¿È¡        mLÉÏÊöŨÑÎËá½øÐÐÅäÖÆ¡£

¢ÚÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ(ÓÃ×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î)                           ¡£

A.ÓÃ30mLˮϴµÓÉÕ±­2¡«3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿

B.ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèŨÑÎËáµÄÌå»ý£¬ÂýÂýÑر­±Ú×¢ÈëÊ¢ÓÐÉÙÁ¿Ë®£¨Ô¼30 mL£©µÄÉÕ±­ÖУ¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä»ìºÏ¾ùÔÈ

C.½«ÒÑÀäÈ´µÄÑÎËáÑز£Á§°ô×¢Èë500mLµÄÈÝÁ¿Æ¿ÖÐ

D.½«ÈÝÁ¿Æ¿µÄ²£Á§Èû¸Ç½ô£¬µßµ¹Ò¡ÔÈ

E.¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐ

F.¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦

¢ÛÔÚÅäÖƹý³ÌÖУ¬ÏÂÁвÙ×÷»áʹËùÅäÖƵÄÏ¡ÑÎËáÎïÖʵÄÁ¿Å¨¶ÈÆ«¸ßµÄÊÇ               ¡£

A.ÓÃÁ¿Í²Á¿È¡Å¨ÑÎËáʱ¸©Êӹ۲찼ҺÃæ

B.Ò¡ÔȺó£¬ÒºÃæϽµ£¬²¹³äË®

C.¶¨ÈÝʱÑöÊӿ̶ÈÏß

D.ÔÚÅäÖÆÇ°ÓÃÏàͬŨ¶ÈµÄÏ¡ÑÎËáÈóÏ´ÈÝÁ¿Æ¿

£¨2£©ÏÖ½«200mL0.30mol/LµÄÑÎËáÓë50mL0.80mol/LCaCl2ÈÜÒº»ìºÏ(»ìºÏºóÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¬ËùµÃÈÜÒºÖÐCl£­µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ          mol/L¡£

£¨3£©ÔÚ±ê×¼×´¿öÏ£¬½«_____________L HClÆøÌåÈÜÓÚ1000 mLË®ÖÐ(Ë®µÄÃܶÈΪ1 g/cm3)£¬ËùµÃÈÜÖÊÖÊÁ¿·ÖÊýΪ36.5%µÄÑÎËá¡£(±£ÁôСÊýµãºóһλ)

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø