ÌâÄ¿ÄÚÈÝ
£¨8·Ö£©ÈçͼËùʾ£¬¼×¡¢ÒÒ¡¢±ûÊÇÈýÖÖ³£¼ûµ¥ÖÊ£¬X¡¢Y¡¢ZÊdz£¼û»¯ºÏÎËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹Øϵ£º
¢ÅÈô¼×ÊǶÌÖÜÆÚ½ðÊôµ¥ÖÊ£¬ÒÒ¡¢±ûÊǶÌÖÜÆڷǽðÊôµ¥ÖÊ£¬X¡¢Y¡¢ZÖÐÖ»ÓÐÒ»ÖÖÊÇÀë×Ó¾§Ì壬
ÊÔÍƶϣº
¢ÙXµÄµç×ÓʽÊÇ______________________________¡£
¢ÚXÓë¼×·´Ó¦µÄ»¯Ñ§·½³Ìʽ____________________________________¡£
¢ÆÈô¼×ÊÇÆøÌåµ¥ÖÊ£¬±ûͨ³£ÊÇÒºÌ壬YºÍZ¾ßÓÐÏàͬµÄÑôÀë×Ó£¬XÓëZº¬ÓÐÏàͬµÄÒõÀë×Ó£¬ÊÔÍƶϣº
¢Ùд³öZµÄ»¯Ñ§Ê½_______________________¡£
¢Úд³öXÓë×ãÁ¿µÄ¼×ÔÚÈÜÒºÖÐÍêÈ«·´Ó¦µÄÀë×Ó·½³Ìʽ£º________________________ _ ¡£
¢Å¢Ù£¨2·Ö£© ¢Ú2Mg+CO2==2MgO+C£¨2·Ö£©
¢Æ¢ÙFeBr3£¨2·Ö£© ¢Ú3Cl2+2Fe2++4Br-==2Fe3++2Br2+6Cl-£¨2·Ö£©
½âÎö:ÓÉ¿òͼ¿ÉÖª·´Ó¦¼×£«X¡ú±û£«YÊôÓÚÖû»·´Ó¦¡£
£¨1£©Èô¼×Ϊ¶ÌÖÜÆÚ½ðÊô£¬ÒÒ¡¢±ûÊǷǽðÊô£¬ÔÚ³£¼û½ðÊôÄÜÖû»·Ç½ðÊôµÄ·´Ó¦ÖÐÖ»ÓÐþºÍ¶þÑõ»¯Ì¼·ûºÏ£¬¹Ê¼×ÊÇþ£¬XÊǶþÑõ»¯Ì¼£¬±ûÊÇ̼¡¢YÊÇMgO¡£Ì¼ºÍ¶þÑõ»¯Ì¼·´Ó¦Éú³ÉCO£¬ZÊÇCO¡£Ì¼²»ÍêȫȼÉÕÉú³ÉCO£¬ÒÒÊÇÑõÆø¡£
£¨2£©ÔÚ³£¼ûµÄµ¥ÖÊÒºÌåÖÐÖ»Óе¥ÖÊä壨½ðÊô¹¯²»³£¼û£¬ºÜÉÙÉæ¼°µ½£©£¬¼´±ûÊǵ¥ÖÊäå¡£YºÍZ¾ßÓÐÏàͬµÄÑôÀë×Ó£¬¸ù¾Ýת»¯¹Øϵ¿ÉÖªXÖÐÒ²º¬ÓиÃÔªËØ£¬¹Ê¸ÃÔªËØÊDZä¼ÛµÄ½ðÊôÔªËØ£¬³£¼ûµÄ±ä¼Û½ðÊôÊÇÌú£¬ÒÒÊǵ¥ÖÊÌú£¬Òò´ËZÊÇFeBr3£¬ÔòXÊÇFeBr2¡£ÄÜ°ÑFeBr2Ñõ»¯Éú³ÉFeBr3ºÍµ¥ÖÊäåµÄµ¥ÖÊÆøÌåÓ¦ÂÈÆø£¬¼´¼×ÊÇÂÈÆø¡£
¢ÙC ¢ÚH2O2 ¢ÛNa ¢ÜFe ¢ÝHNO3£®
A¡¢½ö¢Ù¢Û¢Ü | B¡¢½ö¢Ù¢Ú¢Ý | C¡¢½ö¢Ù¢Ú¢Û¢Ý | D¡¢¢Ù¢Ú¢Û¢Ü¢Ý |
A¡¢¢Ù¢Ú¢Û | B¡¢¢Ú¢Û¢Ü | C¡¢¢Ù¢Ú¢Ü | D¡¢¢Ù¢Ú¢Û¢Ü |
¼×£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©£»¡÷H=-92.4kJ/mol
ÒÒ£º2NO2£¨g£©?N2O4
±û£ºH2£¨g£©+I2£¨g£©?2HI£¨g£©
ÔòÏÂÁÐÓйØ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢Èô¼×µÄÌå»ýΪ2L£¬¾¹ý10Ãëºó·´Ó¦´ïµ½Æ½ºâ״̬£¬·Å³öÈÈÁ¿Îª55.44U£¬ÔòH2µÄ·´Ó¦ËÙÂÊÊÇ0.09mol/£¨L?s£© | B¡¢Èô¼×¡¢ÒÒÖз´Ó¦´ïµ½Æ½ºâʱµÄÌå»ýÏàͬ£¬ÔòÁ½ÈÝÆ÷ÖÐËùº¬ÎïÖʵÄÁ¿¿ÉÄÜÏàͬ | C¡¢ÈôÒÒ¡¢±ûÖз´Ó¦´ïµ½Æ½ºâʱµÄÌå»ý¡¢Ñ¹Ç¿¾ùÏàͬ£¬ÔòÒÒÖÐNO2µÄת»¯ÂÊΪ50% | D¡¢Èô¼×¡¢ÒÒ¡¢±ûÖз´Ó¦¾ù´ïµ½Æ½ºâ״̬ʱ£¬Ôò¼×ÖÐÎïÖʵÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»±ä£¬ÒÒÖÐÎïÖʵÄÑÕÉ«²»±ä£¬±ûÖеÄζȲ»±ä |