ÌâÄ¿ÄÚÈÝ
ʵÑéÊÒÏÖÓÐ3ÖÖËá¼îָʾ¼Á£¬ÆäpHµÄ±äÉ«·¶Î§ÈçÏ£º
¼×»ù³È£º3.1¡«4.4 ʯÈ50¡«8.0 ·Ó̪£º8.2¡«10.0
ÓÃ0.1000mol¡¤L£1NaOHÈÜÒºµÎ¶¨Î´ÖªÅ¨¶ÈµÄCH3COOHÈÜÒº£¬·´Ó¦Ç¡ºÃÍêȫʱ£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ( )
A£®ÈÜÒº³ÊÖÐÐÔ£¬¿ÉÑ¡Óü׻ù³È»ò·Ó̪×÷ָʾ¼Á
B£®ÈÜÒº³ÊÖÐÐÔ£¬Ö»ÄÜÑ¡ÓÃʯÈï×÷ָʾ¼Á
C£®ÈÜÒº³Ê¼îÐÔ£¬¿ÉÑ¡Óü׻ù³È»ò·Ó̪×÷ָʾ¼Á
D£®ÈÜÒº³Ê¼îÐÔ£¬Ö»ÄÜÑ¡Ó÷Ó̪×÷ָʾ¼Á
D¡£
½âÎö:
NaOHÓëCH3COOHÇ¡ºÃÍêÈ«·´Ó¦Éú³ÉCH3COONa£¬CH3COONaΪǿËáÈõ¼îÑΣ¬Ë®½âºóÈÜÒº³Ê¼îÐÔ£¬ÎªÁ˼õÉٵζ¨Îó²î£¬Ó¦Ñ¡Ôñָʾ¼ÁµÄpH·¶Î§ÓëCH3COONaÈÜÒºpH½Ó½ø£¬ËùÒÔָʾ¼ÁÑ¡Ôñ·Ó̪¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ʵÑéÊÒÏÖÓÐ3ÖÖËá¼îָʾ¼Á£¬ÆäpH±äÉ«·¶Î§ÈçÏ£º¼×»ù³È£º3.1¡«4.4ʯÈ5.0¡«8.0·Ó̪£º8.2¡«10.0¡£ÓÃ0.1000mol/LNaOHÈÜÒºµÎ¶¨Î´ÖªÅ¨¶ÈµÄCH3COOHÈÜÒº£¬·´Ó¦Ç¡ºÃÍêȫʱ£¬ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ
A£®ÈÜÒº³ÊÖÐÐÔ£¬¿ÉÑ¡Óü׻ù³È»ò·Ó̪×÷ָʾ¼Á |
B£®ÈÜÒº³ÊÖÐÐÔ£¬Ö»ÄÜÑ¡ÓÃʯÈï×÷ָʾ¼Á |
C£®ÈÜÒº³Ê¼îÐÔ£¬¿ÉÑ¡Óü׻ù³È»ò·Ó̪×÷ָʾ¼Á |
D£®ÈÜÒº³Ê¼îÐÔ£¬Ö»ÄÜÑ¡Ó÷Ó̪×÷ָʾ¼Á |