ÌâÄ¿ÄÚÈÝ

ÏÖÓÐÒÔÏÂËÄÖÖÎïÖÊ£º

A£®ÐÂÖƵÄÇâÑõ»¯Í­[Cu(OH)2]Ðü×ÇÒºB£®Ì¼ï§(NH4HCO3)
C£®Ã÷·¯[ KAI(SO4)2¡¤12H2O]D£®Êìʯ»Ò[Ca(OH)2]
ÇëÄã¸ù¾ÝÌâÒ⣬ѡÔñÇ¡µ±µÄÑ¡ÏîÓÃ×Öĸ´úºÅÌî¿Õ¡£
(1)¼ìÑéÄòÒºÖÐÊÇ·ñº¬ÓÐÆÏÌÑÌÇ£¬¿ÉʹÓà           £»
(2)Ҫʹº¬ÄàɳµÄºÓË®±ä³ÎÇ壬¿ÉʹÓà            £»
(3)ÒªÖк͸ÖÌú³§¡¢µç¶Æ³§²úÉúµÄËáÐÔ·ÏË®£¬¿ÉʹÓà          £»
(4)¸øÅ©×÷ÎïÊ©Óõª·Ê£¬¿ÉʹÓà             ¡£

£¨1£©A£»£¨2£©C£»£¨3£©D£»£¨4£©B

½âÎöÊÔÌâ·ÖÎö£º£¨1£©ÆÏÌÑÌÇÖк¬ÓÐÈ©»ù£¬Äܱ»ÐÂÖƵÄÇâÑõ»¯Í­[Cu(OH)2]Ðü×ÇÒºÑõ»¯£¬´ð°¸Ñ¡A¡£
£¨2£©Ã÷·¯Êdz£Óõľ»Ë®¼Á£¬ËùÒÔҪʹº¬ÄàɳµÄºÓË®±ä³ÎÇ壬¿ÉʹÓÃÃ÷·¯£¬´ð°¸Ñ¡C¡£
£¨3£©Êìʯ»ÒÏÔ¼îÐÔ£¬Òò´ËÒªÖк͸ÖÌú³§¡¢µç¶Æ³§²úÉúµÄËáÐÔ·ÏË®£¬¿ÉʹÓÃÊìʯ»Ò£¬´ð°¸Ñ¡D¡£
£¨4£©Ì¼ï§ÊÇÒ»ÖÖ³£Óû¯·Ê£¬Òò´Ë¸øÅ©×÷ÎïÊ©Óõª·Ê£¬¿ÉʹÓÃ̼泥¬´ð°¸Ñ¡B¡£
¿¼µã£º¿¼²é³£¼ûÎïÖʵĽṹ¡¢ÐÔÖʺÍÓÃ;
µãÆÀ£º¸ÃÌâÊÇ»ù´¡ÐÔÊÔÌâµÄ¿¼²é£¬ÄѶȲ»´ó£¬¸ù¾ÝÊÇÒªÊìÁ·¼Çס³£¼ûÎïÖʵÄÐÔÖʺÍÓÃ;£¬È»ºóÁé»îÔËÓü´¿É¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø