ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÏÖʹÓÃËá¼îÖк͵ζ¨·¨²â¶¨ÊÐÊÛ°×´×µÄ×ÜËáÁ¿(g¡¤100mL-1)¡£
¢ñ.ʵÑé²½Öè
(1)ÓÃ__(ÌîÒÇÆ÷Ãû³Æ)Á¿È¡10.00mLʳÓð״ף¬ÔÚÉÕ±ÖÐÓÃˮϡÊͺóתÒƵ½100mL__(ÌîÒÇÆ÷Ãû³Æ)Öж¨ÈÝ£¬Ò¡Ôȼ´µÃ´ý²â°×´×ÈÜÒº¡£
(2)ÓÃËáʽµÎ¶¨¹ÜÈ¡´ý²â°×´×ÈÜÒº20.00mLÓÚ׶ÐÎÆ¿ÖУ¬ÏòÆäÖеμÓ2µÎ__×÷ָʾ¼Á¡£
(3)¶ÁÈ¡Ê¢×°0.1000mol¡¤L-1NaOHÈÜÒºµÄ¼îʽµÎ¶¨¹ÜµÄ³õʼ¶ÁÊý¡£Èç¹ûÒºÃæλÖÃÈçͼËùʾ£¬Ôò´ËʱµÄ¶ÁÊýΪ__mL¡£
(4)µÎ¶¨¡£µ±__ʱ£¬Í£Ö¹µÎ¶¨£¬²¢¼Ç¼NaOHÈÜÒºµÄÖÕ¶ÁÊý¡£Öظ´µÎ¶¨3´Î¡£
¢ò.ʵÑé¼Ç¼
µÎ¶¨´ÎÊýʵÑéÊý¾Ý(mL) | 1 | 2 | 3 | 4 |
V(ÑùÆ·) | 20.00 | 20.00 | 20.00 | 20.00 |
V(NaOH)(ÏûºÄ) | 15.95 | 15.00 | 15.05 | 14.95 |
¢ó.Êý¾Ý´¦ÀíÓëÌÖÂÛ
(5)¼×ͬѧÔÚ´¦ÀíÊý¾Ýʱ¼ÆËãµÃ£ºÆ½¾ùÏûºÄµÄNaOHÈÜÒºµÄÌå»ýV=mL=15.24mL¡£Ö¸³öËûµÄ¼ÆËãµÄ²»ºÏÀíÖ®´¦£º__¡£
°´ÕýÈ·Êý¾Ý´¦Àí£¬¿ÉµÃc(ÊÐÊÛ°×´×)=__mol¡¤L£1£»ÊÐÊÛ°×´××ÜËáÁ¿=__g¡¤100mL-1¡£
(6)ÔÚ±¾ÊµÑéµÄµÎ¶¨¹ý³ÌÖУ¬ÏÂÁвÙ×÷»áʹʵÑé½á¹ûÆ«´óµÄÊÇ__(ÌîдÐòºÅ)¡£
a£®¼îʽµÎ¶¨¹ÜÔڵζ¨Ê±Î´Óñê×¼NaOHÈÜÒºÈóÏ´
b£®¼îʽµÎ¶¨¹ÜµÄ¼â×ìÔڵζ¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ
c£®×¶ÐÎÆ¿ÖмÓÈë´ý²â°×´×ÈÜÒººó£¬ÔÙ¼ÓÉÙÁ¿Ë®
d£®×¶ÐÎÆ¿Ôڵζ¨Ê±¾çÁÒÒ¡¶¯£¬ÓÐÉÙÁ¿ÒºÌ彦³ö
¡¾´ð°¸¡¿ËáʽµÎ¶¨¹Ü(»ò10mLÒÆÒº¹Ü) ÈÝÁ¿Æ¿ ·Ó̪ 0.60 µÎ¼Ó×îºóÒ»µÎNaOHÈÜҺʱ£¬ÈÜÒºÓÉÎÞÉ«Ç¡ºÃ±äΪdzºìÉ«£¬²¢ÔÚ°ë·ÖÖÓÄÚ²»ÍÊÉ« µÚ1´ÎµÎ¶¨Îó²îÃ÷ÏÔ´ó£¬ÊôÒì³£Öµ£¬Ó¦ÉáÈ¥ 0.75 4.50 ab
¡¾½âÎö¡¿
(1)Á¿È¡ÒºÌåʱ£¬Á¿Í²Ö»ÄܶÁµ½Ð¡Êýµãºóһ룬ÒÆÒº¹ÜºÍµÎ¶¨¹Ü¿ÉÒÔ¶Áµ½Ð¡ÊýµãºóÁ½Î»£»ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÈÜҺʱ£¬Í¨³£Ñ¡Ôñ¾ßÓÐÒ»¶¨¹æ¸ñµÄÈÝÁ¿Æ¿¡£
(2)ÖÐѧ³£ÓõÄËá¼îָʾ¼ÁÖ÷ÒªÓзÓ̪ºÍ¼×»ù³È£¬¸ù¾ÝµÎ¶¨ÖÕµãʱµÄpH£¬È·¶¨Ñ¡ÔñºÎÖÖָʾ¼Á¡£
(3)¶ÁÊýʱ£¬ÐèŪÇå´ó¿Ì¶ÈºÍС¿Ì¶È¡£
(4)µÎ¶¨Ê±£¬ÀûÓÃָʾ¼ÁµÄ±äÉ«È·¶¨µÎ¶¨Öյ㡣
(5)ÀûÓÃ4´ÎʵÑé¼ÆËãƽ¾ùֵʱ£¬²»ÊÇÿ´ÎʵÑéÊý¾Ý¶¼¿ÉÓã¬Ó¦Ñ¡ÔñÓÐЧµÄʵÑéÊý¾Ý¼ÆËãƽ¾ùÖµ¡£
´×ËáÓëNaOHµÈÎïÖʵÄÁ¿·¢Éú·´Ó¦£¬Óɴ˼ÆËã¿ÉµÃ½á¹û¡£
(6)·ÖÎö²Ù×÷Îó²îʱ£¬¿ÉÀûÓù«Ê½c(CH3COOH)=½øÐзÖÎö¡£
(1)Á¿È¡ÒºÌåÌå»ýÒªÇó¶Áµ½Ð¡ÊýµãºóÁ½Î»£¬ÔòÁ¿È¡10.00mLʳÓð״×ʱ£¬Ö»ÄÜÓÃËáʽµÎ¶¨¹Ü(»ò10mLÒÆÒº¹Ü)£¬ÔÚÉÕ±ÖÐÓÃˮϡÊͺóתÒƵ½100mLÈÝÁ¿Æ¿Öж¨ÈÝ£¬Ò¡Ôȼ´µÃ´ý²â°×´×ÈÜÒº¡£´ð°¸Îª£ºËáʽµÎ¶¨¹Ü(»ò10mLÒÆÒº¹Ü)£»ÈÝÁ¿Æ¿£»
(2)µÎ¶¨ÖÕµãʱ£¬´×ËáÄÆÈÜÒº³Ê¼îÐÔ£¬ËùÒÔӦʹÓ÷Ó̪×÷ָʾ¼Á¡£´ð°¸Îª£º·Ó̪£»
(3)Èç¹ûÒºÃæλÖÃÈçͼËùʾ£¬Ôò´ËʱµÄ¶ÁÊýΪ0.60mL¡£´ð°¸Îª£º0.60£»
(4)µÎ¶¨Ê±£¬µ±µÎ¼Ó×îºóÒ»µÎNaOHÈÜҺʱ£¬ÈÜÒºÓÉÎÞÉ«Ç¡ºÃ±äΪdzºìÉ«£¬²¢ÔÚ°ë·ÖÖÓÄÚ²»ÍÊɫʱ£¬Í£Ö¹µÎ¶¨¡£´ð°¸Îª£ºµ±µÎ¼Ó×îºóÒ»µÎNaOHÈÜҺʱ£¬ÈÜÒºÓÉÎÞÉ«Ç¡ºÃ±äΪdzºìÉ«£¬²¢ÔÚ°ë·ÖÖÓÄÚ²»ÍÊÉ«£»
(5)µÚÒ»´ÎʵÑéËùÓÃNaOHÌå»ýÓëÁíÈý´ÎÏà±È£¬Îó²îÃ÷ÏÔ£¬²»ÄÜʹÓã¬ÔòËûµÄ¼ÆËãµÄ²»ºÏÀíÖ®´¦£ºµÚ1´ÎµÎ¶¨Îó²îÃ÷ÏÔ´ó£¬ÊôÒì³£Öµ£¬Ó¦ÉáÈ¥¡£´ð°¸Îª£ºµÚ1´ÎµÎ¶¨Îó²îÃ÷ÏÔ´ó£¬ÊôÒì³£Öµ£¬Ó¦ÉáÈ¥£»
ƽ¾ùÏûºÄµÄNaOHÈÜÒºµÄÌå»ýV=mL=15.00mL
Ôòc(´ý²â°×´×)==0.075mol¡¤L£1£¬c(ÊÐÊÛ°×´×)=
=0.75mol¡¤L£1£»
ÊÐÊÛ°×´××ÜËáÁ¿==4.50g¡¤100mL-1¡£´ð°¸Îª£º0.75£»4.50£»
(6) ·ÖÎö²Ù×÷Îó²îʱ£¬¿ÉÀûÓù«Ê½c(CH3COOH)=½øÐзÖÎö
a£®¼îʽµÎ¶¨¹ÜÔڵζ¨Ê±Î´Óñê×¼NaOHÈÜÒºÈóÏ´£¬V(NaOH)Æ«´ó£¬c(CH3COOH)Æ«´ó£»
b£®¼îʽµÎ¶¨¹ÜµÄ¼â×ìÔڵζ¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ£¬V(NaOH)Æ«´ó£¬c(CH3COOH)Æ«´ó£»
c£®×¶ÐÎÆ¿ÖмÓÈë´ý²â°×´×ÈÜÒººó£¬ÔÙ¼ÓÉÙÁ¿Ë®£¬V(NaOH)²»±ä£¬c(CH3COOH)²»±ä£»
d£®×¶ÐÎÆ¿Ôڵζ¨Ê±¾çÁÒÒ¡¶¯£¬ÓÐÉÙÁ¿ÒºÌ彦³ö£¬V(NaOH)ƫС£¬c(CH3COOH)ƫС£»
×ÛºÏÒÔÉÏ·ÖÎö£¬ab·ûºÏÌâÒ⣬´ð°¸Îª£ºab¡£
![](http://thumb2018.1010pic.com/images/loading.gif)