Question

下面均是正丁烷与氧气反应的热化学方程式(25℃，101 kPa)：

①C4H10(g)＋O2(g)=4CO2(g)＋5H2O(l) ΔH＝－2878 kJ/mol

②C4H10(g)＋O2(g)=4CO2(g)＋5H2O(g) ΔH＝－2658 kJ/mol

③C4H10(g)＋O2(g)=4CO(g)＋5H2O(l) ΔH＝－1746 kJ/mol

④C4H10(g)＋O2(g)=4CO(g)＋5H2O(g) ΔH＝－1526 kJ/mol

由此判断，正丁烷的燃烧热是

A．－2878 kJ/mol B．－2658 kJ/mol

C．－1746 kJ/mol D．－1526 kJ/mol

Answer 1