ÌâÄ¿ÄÚÈÝ
¹úÎñԺǿµ÷£¬¡°ÄÏË®±±µ÷¡±¹¤³Ì±ØÐë¼á³Ö½ÚË®¡¢ÖÎÎÛºÍÉú̬»·¾³±£»¤Ó빤³Ì½¨ÉèÏàе÷£¬ÒÔË®×ÊÔ´ºÏÀíÅäÖÃΪÖ÷Ïߣ¬°Ñ½ÚË®¡¢ÖÎÎÛ¡¢Éú̬»·¾³±£»¤Óëµ÷Ë®×÷Ϊһ¸öÍêÕûµÄϵͳÀ´·ÖÎöµÄÔÔò£®ÔÚµ÷Ë®¹¤³ÌÖУ¬ÑØ;¹¤ÒµÎÛË®µÄÈÎÒâÅÅ·ÅÊÇÔì³ÉË®Öʶñ»¯µÄ×î´óÒþ»¼£®¼ì²âij¹¤³§·ÏÒºÖУ¬º¬ÓдóÁ¿µÄMg2+¡¢Al3+¡¢Cu2+¡¢Ag+£®ÊÔ·ÖÎö»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸Ã·ÏÒºÖпÉÄÜ´óÁ¿´æÔÚµÄÒ»ÖÖÒõÀë×ÓÊÇ
A£®SO42- B£®CO32- C£®Cl- D£®NO3-
£¨2£©¾¼ì²â·ÏÒºÖÐÂÁÔªËصĺ¬Á¿½Ï¸ß£¬Ð轫ÆäÓëÆäËûÈýÖÖÀë×Ó·Ö¿ª£¬ÇëÑ¡ÓúÏÊʵÄÊÔ¼Á£¬Ð´³öÂÁÔªËØÓë¸ÃÊÔ¼Á·´Ó¦Ê±µÄÀë×Ó·½³Ìʽ£º
£¨3£©ÎªÁË»ØÊÕ·ÏÒºÖеĽðÊôÒø£¬Ä³Í¬Ñ§Éè¼ÆÁËÈçͼËùʾµÄ·½°¸£®ÈôÒÀ¸Ã·½°¸»ñµÃ½ðÊôÒø10.80g£¬Îª±£Ö¤²»ÎÛȾ»·¾³ºÍCl2µÄÑ»·ÀûÓã¬ÀíÂÛÉÏÓ¦Ìṩ±ê×¼×´¿öϵÄH2Ìå»ýΪ
£¨1£©¸Ã·ÏÒºÖпÉÄÜ´óÁ¿´æÔÚµÄÒ»ÖÖÒõÀë×ÓÊÇ
D
D
£¨Ñ¡ÌîÐòºÅ£©?A£®SO42- B£®CO32- C£®Cl- D£®NO3-
£¨2£©¾¼ì²â·ÏÒºÖÐÂÁÔªËصĺ¬Á¿½Ï¸ß£¬Ð轫ÆäÓëÆäËûÈýÖÖÀë×Ó·Ö¿ª£¬ÇëÑ¡ÓúÏÊʵÄÊÔ¼Á£¬Ð´³öÂÁÔªËØÓë¸ÃÊÔ¼Á·´Ó¦Ê±µÄÀë×Ó·½³Ìʽ£º
Al3++4OH-=AlO2-+2H2O
Al3++4OH-=AlO2-+2H2O
£®£¨3£©ÎªÁË»ØÊÕ·ÏÒºÖеĽðÊôÒø£¬Ä³Í¬Ñ§Éè¼ÆÁËÈçͼËùʾµÄ·½°¸£®ÈôÒÀ¸Ã·½°¸»ñµÃ½ðÊôÒø10.80g£¬Îª±£Ö¤²»ÎÛȾ»·¾³ºÍCl2µÄÑ»·ÀûÓã¬ÀíÂÛÉÏÓ¦Ìṩ±ê×¼×´¿öϵÄH2Ìå»ýΪ
1.12
1.12
L£®·ÖÎö£º£¨1£©ÓëMg2+¡¢Al3+¡¢Cu2+¡¢Ag+ÖÐÈκÎÀë×Ó¶¼²»·´Ó¦µÄÀë×Ó¿É´óÁ¿¹²´æ£»
£¨2£©¸ù¾ÝÇâÑõ»¯ÂÁΪÁ½ÐÔÇâÑõ»¯ÎïµÄÐÔÖʽøÐзÖÀ룻
£¨3£©n£¨Ag£©=
=0.1mol£¬½áºÏ·´Ó¦µÄ¹Øϵʽ2AgCl¡«Cl2¡«H2¼ÆË㣮
£¨2£©¸ù¾ÝÇâÑõ»¯ÂÁΪÁ½ÐÔÇâÑõ»¯ÎïµÄÐÔÖʽøÐзÖÀ룻
£¨3£©n£¨Ag£©=
10.80g |
108g/mol |
½â´ð£º½â£º£¨1£©ÌâÖÐSO42-¡¢CO32-¡¢Cl-¶¼¿ÉÓëAg+·´Ó¦Éú²úÄÑÈÜÓÚË®»ò΢ÈÜÓÚË®µÄ³Áµí£¬Ö»ÓÐD·ûºÏ£¬¹Ê´ð°¸Îª£ºD£»
£¨2£©ÇâÑõ»¯ÂÁΪÁ½ÐÔÇâÑõ»¯Î¿ÉÓÃÇ¿¼î·ÖÀ룬Ïà¹Ø·´Ó¦µÄÀë×Ó·½³ÌʽΪAl3++4OH-=AlO2-+2H2O£¬
¹Ê´ð°¸Îª£ºAl3++4OH-=AlO2-+2H2O£»
£¨3£©n£¨Ag£©=
=0.1mol£¬·´Ó¦µÄ¹ØϵʽΪ2AgCl¡«Cl2¡«H2£¬Ôòn£¨H2£©=0.05mol£¬
V£¨H2£©=0.05mol¡Á22.4L/mol=1.12L£¬
¹Ê´ð°¸Îª£º1.12£®
£¨2£©ÇâÑõ»¯ÂÁΪÁ½ÐÔÇâÑõ»¯Î¿ÉÓÃÇ¿¼î·ÖÀ룬Ïà¹Ø·´Ó¦µÄÀë×Ó·½³ÌʽΪAl3++4OH-=AlO2-+2H2O£¬
¹Ê´ð°¸Îª£ºAl3++4OH-=AlO2-+2H2O£»
£¨3£©n£¨Ag£©=
10.80g |
108g/mol |
V£¨H2£©=0.05mol¡Á22.4L/mol=1.12L£¬
¹Ê´ð°¸Îª£º1.12£®
µãÆÀ£º±¾Ì⿼²é½ÏΪ×ۺϣ¬Éæ¼°Àë×Ó¹²´æ¡¢Àë×Ó·½³ÌʽµÄÊéд¼°¼ÆË㣬Ϊ¸ß¿¼³£¼ûÌâÐÍ£¬²àÖØÓÚѧÉúÔªËØ»¯ºÏÎï֪ʶµÄ×ÛºÏÔËÓã¬ÄѶȲ»´ó£¬×¢Òâ°ÑÎÕÌâ¸øÐÅÏ¢ÒÔ¼°Ïà¹ØÀë×ÓµÄÐÔÖÊ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
|