ÌâÄ¿ÄÚÈÝ

¢ñ£®ÈçͼËùʾΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹£®
£¨1£©Çëд³öÏÂÁÐÒÇÆ÷µÄÃû³Æ£ºA
Á¿Í²
Á¿Í²
£¬B
ÈÝÁ¿Æ¿
ÈÝÁ¿Æ¿
£¬C
ζȼÆ
ζȼÆ
£®
£¨2£©ÒÇÆ÷BÉϱê¼ÇÓÐ
¢Ú¢Û¢Ý
¢Ú¢Û¢Ý
£¨ÌîÐòºÅ£©£®
¢ÙÖÊÁ¿    ¢ÚζȠ   ¢Û¿Ì¶ÈÏß    ¢ÜŨ¶È    ¢ÝÈÝ»ý
£¨3£©ÒÇÆ÷BʹÓÃÇ°±ØÐë
¼ì²éÊÇ·ñ©ˮ
¼ì²éÊÇ·ñ©ˮ
£®
¢ò£®ÏÖÓÃ98%µÄŨH2SO4£¨ÃܶÈΪ1.84g/cm3£©À´ÅäÖÆ480mL0.2mol/LµÄÏ¡H2SO4£®
ÓйزÙ×÷Ϊ£º¢Ù¼ÆËãËùÐèŨÁòËáµÄÌå»ý  ¢ÚÁ¿È¡Ò»¶¨Ìå»ýµÄŨÁòËá  ¢ÛÏ¡ÊÍ¡¢ÀäÈ´  ¢ÜתÒÆ¡¢Ï´µÓ  ¢Ý¶¨ÈÝ  ¢ÞÒ¡ÔÈ
»Ø´ðÏÂÁÐÎÊÌâ
£¨4£©Ó¦Á¿È¡µÄŨÁòËáÌå»ýÊÇ
5.4mL
5.4mL
£¬ÊµÑéÖÐËùÓõIJ£Á§ÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢Á¿Í²¡¢½ºÍ·µÎ¹ÜÍ⻹ÓÐ
500mLÈÝÁ¿Æ¿
500mLÈÝÁ¿Æ¿
£»
£¨5£©µÚ¢Û²½ÖÐÏ¡ÊÍŨÁòËáµÄ²Ù×÷ÊÇ
½«Å¨ÁòËáÑØÉÕ±­ÄÚ±ÚÂýÂý¼ÓÈëË®ÖУ¬±ß¼Ó±ßÓò£Á§°ô½Á°è
½«Å¨ÁòËáÑØÉÕ±­ÄÚ±ÚÂýÂý¼ÓÈëË®ÖУ¬±ß¼Ó±ßÓò£Á§°ô½Á°è

£¨6£©½«ËùÅäÖƵÄÏ¡H2SO4½øÐвⶨ£¬·¢ÏÖʵ¼ÊŨ¶È´óÓÚ0.2mol/L£®ÇëÄã·ÖÎöÏÂÁÐÄÄЩ²Ù×÷»áÒýÆðËùÅäŨ¶ÈÆ«´ó£¨Ìîд×Öĸ£©
ACF
ACF
£®
A£®ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬ÑöÊÓÁ¿Í²µÄ¿Ì¶È
B£®ÈÝÁ¿Æ¿Î´¸ÉÔï¼´ÓÃÀ´ÅäÖÆÈÜÒº
C£®Å¨ÁòËáÔÚÉÕ±­ÖÐÏ¡Êͺó£¬Î´ÀäÈ´¾ÍÁ¢¼´×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬²¢½øÐж¨ÈÝ
D£®ÍùÈÝÁ¿Æ¿×ªÒÆʱ£¬ÓÐÉÙÁ¿ÒºÌ彦³ö
E£®ÉÕ±­Î´½øÐÐÏ´µÓ
F£®ÔÚÈÝÁ¿Æ¿Öж¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß
G£®¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏߣ®
·ÖÎö£º¢ñ¡¢¸ù¾ÝÈÝÁ¿Æ¿µÄ½á¹¹¡¢ºÍʹÓÃ×¢ÒâÊÂÏÈÝÁ¿Æ¿Éϱê¼ÇÓÐζȡ¢¿Ì¶ÈÏß¡¢ÈÝ»ý£¬¸ù¾ÝËùÅäÈÜÒºÌå»ýÑ¡ÔñºÏÊʵÄÈÝÁ¿Æ¿£¬ÈÝÁ¿Æ¿ÔÚʹÓÃÇ°Òª¼ì²éÊÇ·ñ©ˮµÈ£»
¢ò¡¢ÓÃ98%µÄŨH2SO4£¨ÃܶÈΪ1.84g/cm3£©À´ÅäÖÆ480mL0.2mol/LµÄÏ¡H2SO4£¬
£¨4£©¸ù¾ÝÅäÖƲ½ÖèºÍËùÅäÈÜÒºµÄÌå»ýÑ¡ÔñËùÓò£Á§ÒÇÆ÷ΪÉÕ±­¡¢²£Á§°ô¡¢Á¿Í²¡¢½ºÍ·µÎ¹ÜºÍ500mLÈÝÁ¿Æ¿£»¸ù¾ÝÏ¡ÊͶ¨ÂÉ£¬Ï¡ÊÍÇ°ºóÈÜÖʵÄÁ¿²»±ä¼ÆËãÓ¦Á¿È¡Å¨ÁòËáµÄÌå»ý£»
£¨5£©Å¨ÁòËáÃܶȱÈË®´ó£¬ÈÜÓÚË®·Å³ö´óÁ¿µÄÈÈ£¬Ï¡ÊÍʱ½«Å¨ÁòËáÑØÉÕ±­ÄÚ±ÚÂýÂý¼ÓÈëË®ÖУ¬±ß¼Ó±ßÓò£Á§°ô½Á°è£»
£¨6£©¸ù¾Ýc£¨ÁòËᣩ=
n(ÁòËá)
V
£¬µ±ÈÜÖʵÄÁ¿Ôö¼Ó»òÈÜÒºµÄÌå»ý¼õСʱ£¬Êµ¼ÊÈܶÈÆ«´óÀ´·ÖÎöÅжϣ®
½â´ð£º½â£º¢ñ£¨1£©¸ù¾ÝÒÇÆ÷µÄͼÐοÉÖª£ºAΪÁ¿Í²£¬BΪÈÝÁ¿Æ¿¡¢CΪζȼƣ»
£¨2£©BΪÈÝÁ¿Æ¿£¬ÈÝÁ¿Æ¿Éϱê¼ÇÓУºÎ¶ȡ¢¿Ì¶ÈÏß¡¢ÈÝ»ý£¬¹ÊÌî¢Ú¢Û¢Ý£»
£¨3£©ÈÝÁ¿Æ¿ÔÚʹÓÃÇ°±ØÐëÒª¼ì²éÊÇ·ñ©ˮ£»
¢ò£¨4£©ÅäÖÆ480mL0.2mol/LµÄÏ¡H2SO4£¬ÐèÑ¡Ôñ500mLÈÝÁ¿Æ¿£¬
¸ù¾ÝÏ¡ÊͶ¨ÂÉ£¬Ï¡ÊÍÇ°ºóÈÜÖʵÄÁ¿²»±ä£¬À´¼ÆËãŨÁòËáµÄÌå»ý£¬
ÉèŨÁòËáµÄÌå»ýΪxmL
xmL¡Á1.84g/cm3¡Á98%=500mL¡Á1000-3L/mL¡Á0.2mol/L¡Á98g/mol
½âÖ®µÃ£ºx¡Ö5.4
ËùÒÔÓ¦Á¿È¡µÄŨÁòËáÌå»ýÊÇ5.4mL£»
£¨5£©Å¨ÁòËáÃܶȱÈË®´ó£¬ÈÜÓÚË®·Å³ö´óÁ¿µÄÈÈ£¬Ï¡ÊÍʱ½«Å¨ÁòËáÑØÉÕ±­ÄÚ±ÚÂýÂý¼ÓÈëË®ÖУ¬±ß¼Ó±ßÓò£Á§°ô½Á°è£»
£¨6£©c£¨ÁòËᣩ=
n(ÁòËá)
V
£¬µ±ÈÜÖʵÄÁ¿Ôö¼Ó»òÈÜÒºµÄÌå»ý¼õСʱ£¬Êµ¼ÊÈܶÈÆ«´ó£»
A¡¢ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬ÑöÊÓÁ¿Í²µÄ¿Ì¶È£¬Ê¹ËùÁ¿È¡µÄŨÁòËáµÄÌå»ýÆ«´ó£¬Ôì³ÉÅäÖÆÈÜҺʵ¼ÊŨ¶ÈÆ«´ó£»
B¡¢ÈÝÁ¿Æ¿Î´¸ÉÔï¼´ÓÃÀ´ÅäÖÆÈÜÒº¶ÔËùÅäÈÜҺŨ¶ÈûÓÐÓ°Ï죻
C¡¢Å¨ÁòËáÔÚÉÕ±­ÖÐÏ¡Êͺó£¬Î´ÀäÈ´¾ÍÁ¢¼´×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬²¢½øÐж¨ÈÝ£¬ÈÝÁ¿Æ¿ÄÚÈÜҺζȸßÓÚ20£®C£¬Ôì³ÉËùÅäÖÆÈÜÒºÌå»ýСÓÚÈÝÁ¿Æ¿ÉÏËù±ê×¢µÄÒºÌåÌå»ý£¬Ê¹ÈÜҺŨ¶ÈÆ«¸ß£»
D¡¢ÍùÈÝÁ¿Æ¿×ªÒÆʱ£¬ÓÐÉÙÁ¿ÒºÌ彦³ö£¬Ê¹ÈÜÖʵÄÁ¿¼õÉÙ£¬Ôì³ÉÈÜҺŨ¶ÈÆ«µÍ£»
E¡¢ÉÕ±­Î´½øÐÐÏ´µÓ£¬ÉÕ±­ÄÚ±ÚÓÐÉÙÁ¿ÈÜÖÊ£¬Ê¹ÈÜÖʵÄÁ¿¼õÉÙ£¬Ôì³ÉÈÜҺŨ¶ÈÆ«µÍ£»
F¡¢ÔÚÈÝÁ¿Æ¿Öж¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏߣ¬Ê¹ÈÜÒºÌå»ý¼õС£¬Ôì³ÉÈÜҺŨ¶ÈÆ«¸ß£»
G¡¢¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏߣ¬Ê¹ÈÜÒºÌå»ýÔö´ó£¬Ôì³ÉÈÜҺŨ¶ÈÆ«µÍ£»
¹ÊÑ¡ACF£®
¹Ê´ð°¸Îª£º£¨1£©Á¿Í²£¬ÈÝÁ¿Æ¿£¬Î¶ȼƣ»
£¨2£©¢Ú¢Û¢Ý£»
£¨3£©¼ì²éÊÇ·ñ©ˮ£»            
£¨4£©5.4mL£¬500mLÈÝÁ¿Æ¿£»         
£¨5£©½«Å¨ÁòËáÑØÉÕ±­ÄÚ±ÚÂýÂý¼ÓÈëË®ÖУ¬±ß¼Ó±ßÓò£Á§°ô½Á°è£®
£¨6£©ACF£®
µãÆÀ£º±¾Ì⿼²éÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒº£¬ÒªÕÆÎÕÈÝÁ¿Æ¿µÄʹÓÃÓëÑ¡Ôñ¡¢Å¨ÁòËáµÄÏ¡ÊÍ¡¢Îó²î·ÖÎöµÈ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©ÈçͼËùʾΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹£¨ÓеÄÒÇÆ÷±»·Å´ó£© ¾«Ó¢¼Ò½ÌÍø
DµÄÒÇÆ÷Ãû³ÆÊÇ
 
¡¢AͼÖÐÒºÃæËùʾÈÜÒºµÄÌå»ýΪ
 
mL£¬CͼÖеÄÒºÃæÓë¡°0¡±¿Ì¶ÈÖ®¼äµÄÌå»ý²îΪ
 
mL£®£¨ÉèA¡¢CÖзֱðÊ¢ÓÐÎÞÉ«ÈÜÒº£©£®
£¨2£©Ä³ÉÕ¼îÑùÆ·Öк¬ÓÐÉÙÁ¿²»ÓëËá×÷ÓõĿÉÈÜÐÔÔÓÖÊ£¬ÎªÁ˲ⶨÆä´¿¶È£¬½øÐÐÒÔÏµζ¨²Ù×÷£º
A£®ÔÚÈÝÁ¿Æ¿ÖÐÅäÖÆA mLÉÕ¼îÈÜÒº
B£®ÓÃÒÆÒº¹Ü£¨»ò¼îʽµÎ¶¨¹Ü£©Á¿È¡£¼¡°m¡°£ºmath dsi£ºzoomscale=150 dsi£º_mathzoomed=1£¾110
110
¡ÁA mLÉÕ¼îÈÜÒºÓÚ׶ÐÎÆ¿Öв¢¼Ó¼¸µÎ·Óָ̪ʾ¼Á
C£®ÔÚÌìƽÉÏ׼ȷ³ÆÈ¡ÉÕ¼îÑùÆ·wg£¬ÔÚÉÕ±­ÖмÓÕôÁóË®Èܽâ
D£®½«ÎïÖʵÄÁ¿Å¨¶ÈΪm mol/LµÄ±ê×¼ÑÎËáÈÜҺװÈëËáʽµÎ¶¨¹Ü£¬µ÷ÕûÒºÃ棬¼ÇÏ¿ªÊ¼¿Ì¶ÈV1 mL
E£®µÎ¶¨µ½Öյ㣬¼Ç¼ÖÕµã¿Ì¶ÈΪV2 mL
ÇëÍê³ÉÏÂÁÐÎÊÌ⣺
¢ÙÕýÈ·µÄ²Ù×÷²½ÖèÊÇ£¨Ìîд×Öĸ£©
 
¡ú
 
¡ú
 
¡úD¡ú
 
£®
¢Ú²Ù×÷ÖÐÑÛ¾¦Òª×¢ÊÓ
 
£®
¢ÛµÎ¶¨ÖÕµãµÄÅжÏ
 
£®
¢ÜÈôËáʽµÎ¶¨¹ÜûÓñê×¼ÑÎËáÈóÏ´£¬»á¶Ô²â¶¨½á¹ûÓкÎÓ°Ïì
 
£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£¬ÆäËû²Ù×÷¾ùÕýÈ·£©£®
¢Ý¸ÃÉÕ¼îÑùÆ·µÄ´¿¶È¼ÆËãʽÊÇ
 
£®

¢ñ£¨4·Ö£©¢Åͨ³£×´¿öÏ£¬¼×ͬѧȡ1 mol H2O¼ÓÈȵ½100¡æʱ£¬ÒºÌ¬Ë®»áÆû»¯ÎªË®ÕôÆø£¨ÈçͼËùʾ£©£¬¸Ã¹ý³ÌÊôÓÚ ¡ø  ±ä»¯¡£

ÔÚ±£³Öѹǿ²»±äµÄÇé¿öÏ£¬Ë®ÕôÆøµÄÌå»ý      ¡ø        
£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©22.4L ¡£
¢ÆÒÒͬѧ×öH2ÔÚO2ÖÐȼÉÕµÄʵÑ飬¸ÃʵÑé¹ý³ÌÊôÓÚ  ¡ø   ±ä»¯£¬Ôڸñ仯¹ý³ÌÖУ¬Ò»¶¨±£³ÖÏàµÈµÄÊÇ     ¡ø       £¨ÌîÐòºÅ£©¡£

A£®·´Ó¦Îï·Ö×ÓÊýÄ¿ÓëÉú³ÉÎï·Ö×ÓÊýÄ¿B£®·´Ó¦ÎïÔ­×Ó×ÜÎïÖʵÄÁ¿ÓëÉú³ÉÎïÔ­×Ó×ÜÎïÖʵÄÁ¿
C£®·´Ó¦Îï×ÜÖÊÁ¿ÓëÉú³ÉÎï×ÜÖÊÁ¿D£®·´Ó¦ÎïÌå»ýÓëÉú³ÉÎïÌå»ý
¢ò£¨6·Ö£©ÈçͼËùʾΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹¡£

¢ÅÇëд³öÏÂÁÐÒÇÆ÷µÄÃû³Æ£º A     ¡ø     £¬B      ¡ø    £¬C     ¡ø     ¡£
¢ÆÒÇÆ÷BÉϱê¼ÇÓР  ¡ø      £¨ÌîÐòºÅ£©¡£
¢ÙÖÊÁ¿      ¢ÚζȠ    ¢Û¿Ì¶ÈÏß     ¢ÜŨ¶È    ¢ÝÈÝ»ý
¢Ç¼ìÑéÒÇÆ÷BÊÇ·ñ©ˮµÄ·½·¨ÊÇ                    ¡ø                     
                                                                                      
                                                                                      

£¨18·Ö£©¢ñ.ÈçͼËùʾΪ³£¼ûÒÇÆ÷µÄ²¿·Ö½á¹¹¡£

£¨1£©Çëд³öÏÂÁÐÒÇÆ÷µÄÃû³Æ£ºA           £¬B           £¬C            ¡£

£¨2£©ÒÇÆ÷BÉϱê¼ÇÓР           £¨ÌîÐòºÅ£©¡£

¢ÙÖÊÁ¿    ¢ÚζȠ   ¢Û¿Ì¶ÈÏß    ¢ÜŨ¶È    ¢ÝÈÝ»ý

£¨3£©ÒÇÆ÷BʹÓÃÇ°±ØÐë                ¡£

¢ò.ÏÖÓÃ98%µÄŨH2SO4£¨ÃܶÈΪ1.84g/cm3£©À´ÅäÖÆ480mL0.2mol£¯LµÄÏ¡H2SO4¡£

ÓйزÙ×÷Ϊ£º¢Ù¼ÆËãËùÐèŨÁòËáµÄÌå»ý  ¢ÚÁ¿È¡Ò»¶¨Ìå»ýµÄŨÁòËá  ¢ÛÏ¡ÊÍ¡¢ÀäÈ´  ¢ÜתÒÆ¡¢Ï´µÓ  ¢Ý¶¨ÈÝ  ¢ÞÒ¡ÔÈ

»Ø´ðÏÂÁÐÎÊÌâ

£¨4£©Ó¦Á¿È¡µÄŨÁòËáÌå»ýÊÇ         £¬ÊµÑéÖÐËùÓõIJ£Á§ÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢

Á¿Í²¡¢½ºÍ·µÎ¹ÜÍ⻹ÓР               £»

£¨5£©µÚ¢Û²½ÖÐÏ¡ÊÍŨÁòËáµÄ²Ù×÷ÊÇ                                                      

£¨6£©½«ËùÅäÖƵÄÏ¡H2SO4½øÐвⶨ£¬·¢ÏÖʵ¼ÊŨ¶È´óÓÚ0.2mol£¯L¡£ÇëÄã·ÖÎöÏÂÁÐÄÄЩ²Ù×÷»áÒýÆðËùÅäŨ¶ÈÆ«´ó£¨Ìîд×Öĸ£©                              ¡£

A£®ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬ÑöÊÓÁ¿Í²µÄ¿Ì¶È

B£®ÈÝÁ¿Æ¿Î´¸ÉÔï¼´ÓÃÀ´ÅäÖÆÈÜÒº

C£®Å¨ÁòËáÔÚÉÕ±­ÖÐÏ¡Êͺó£¬Î´ÀäÈ´¾ÍÁ¢¼´×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬²¢½øÐж¨ÈÝ

D£®ÍùÈÝÁ¿Æ¿×ªÒÆʱ£¬ÓÐÉÙÁ¿ÒºÌ彦³ö

E£®ÉÕ±­Î´½øÐÐÏ´µÓ

F£®ÔÚÈÝÁ¿Æ¿Öж¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß

G£®¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏß¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø