ÌâÄ¿ÄÚÈÝ
ij´ß»¯¼ÁÖк¬ÓеĻîÐÔ×é·ÖΪNi¡¢CuºÍZnµÄ»¯ºÏÎ¿ÉÓÃÓÚ¶þÑõ»¯Ì¼¼ÓÇâÖÆÈ¡¼×ÃÑ£®¼×ÃÑÊÇÒÒ´¼µÄͬ·ÖÒì¹¹Ì壬ÆäÈÛµã-141.5¡æ£¬·Ðµã-24.9¡æ£¬ÔÚ¼ÓÈÈÌõ¼þÏ¿ɷֽâ³É¼×Íé¡¢ÒÒÍé¡¢¼×È©µÈ£®
£¨1£©ÈçͼÊÇCuµÄijÖÖÑõ»¯ÎïµÄ¾§°û½á¹¹Ê¾Òâͼ£¬ÑõµÄÅäλÊýΪ
£¨2£©ÒÒ´¼µÄ·Ðµã±È¼×ÃѸߣ¬ÆäÖ÷ÒªÔÒòÊÇ
£¨3£©¼×È©·Ö×ÓÖÐ̼Ô×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍΪ
£¨4£©´¢Çâ²ÄÁÏ»¯ºÏÎïAÊÇÒÒÍéµÄµÈµç×ÓÌ壬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª30.8£¬ÇÒAÊÇÓɵڶþÖÜÆÚÁ½ÖÖÇ⻯ÎïÐγɵĻ¯Ì¨Î¼ÓÈÈA»á»ºÂýÊÍ·ÅÇâÆø£¬Í¬Ê±Aת»¯Îª»¯ºÏÎïB£¬BÊÇÒÒÏ©µÄµÈµç×ÓÌ壮»¯ºÏÎïAµÄ½á¹¹Ê½Îª£¨Èôº¬ÓÐÅäλ¼ü£¬ÒªÇóÓüýÍ·±íʾ£©£¬1mol»¯ºÏÎïBÖЦҼüµÄÊýÄ¿ÊÇ
£¨1£©ÈçͼÊÇCuµÄijÖÖÑõ»¯ÎïµÄ¾§°û½á¹¹Ê¾Òâͼ£¬ÑõµÄÅäλÊýΪ
4
4
£®£¨2£©ÒÒ´¼µÄ·Ðµã±È¼×ÃѸߣ¬ÆäÖ÷ÒªÔÒòÊÇ
ÒÒ´¼ÐγɷÖ×Ó¼äÇâ¼ü
ÒÒ´¼ÐγɷÖ×Ó¼äÇâ¼ü
£®£¨3£©¼×È©·Ö×ÓÖÐ̼Ô×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍΪ
sp2
sp2
£®£¨4£©´¢Çâ²ÄÁÏ»¯ºÏÎïAÊÇÒÒÍéµÄµÈµç×ÓÌ壬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª30.8£¬ÇÒAÊÇÓɵڶþÖÜÆÚÁ½ÖÖÇ⻯ÎïÐγɵĻ¯Ì¨Î¼ÓÈÈA»á»ºÂýÊÍ·ÅÇâÆø£¬Í¬Ê±Aת»¯Îª»¯ºÏÎïB£¬BÊÇÒÒÏ©µÄµÈµç×ÓÌ壮»¯ºÏÎïAµÄ½á¹¹Ê½Îª£¨Èôº¬ÓÐÅäλ¼ü£¬ÒªÇóÓüýÍ·±íʾ£©£¬1mol»¯ºÏÎïBÖЦҼüµÄÊýÄ¿ÊÇ
5NA
5NA
£®·ÖÎö£º£¨1£©¸ù¾Ý¾§°û½á¹¹ÅжÏÑõÔ×ÓÅäλÊý£»
£¨2£©Çâ¼üÓ°ÏìÎïÖʵķе㣻
£¨3£©¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÈ·¶¨ÆäÔÓ»¯·½Ê½£»
£¨4£©ÐγÉÅäλ¼üµÄÌõ¼þÊÇÓпչìµÀºÍ¹Âµç×Ó¶Ô£»Ò»¸öBH2=NH2·Ö×ÓÖк¬ÓÐ5¸ö¦Ò¼ü£®
£¨2£©Çâ¼üÓ°ÏìÎïÖʵķе㣻
£¨3£©¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÈ·¶¨ÆäÔÓ»¯·½Ê½£»
£¨4£©ÐγÉÅäλ¼üµÄÌõ¼þÊÇÓпչìµÀºÍ¹Âµç×Ó¶Ô£»Ò»¸öBH2=NH2·Ö×ÓÖк¬ÓÐ5¸ö¦Ò¼ü£®
½â´ð£º½â£º£¨1£©¸ù¾Ý¾§°û½á¹¹Öª£¬ÑõÔ×ÓµÄÅäλÊýÊÇ4£¬¹Ê´ð°¸Îª£º4£»
£¨2£©ÒÒ´¼·Ö×Ó¼äÄÜÐγÉÇâ¼ü£¬¶ø¼×ÃÑ·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü£¬Çâ¼üµÄ´æÔÚʱÎïÖʵķеãÉý¸ß£¬
¹Ê´ð°¸Îª£ºÒÒ´¼ÐγɷÖ×Ó¼äÇâ¼ü£»
£¨3£©¼×È©£¨H2C=O£©·Ö×ÓÄÚ̼Ô×ÓÐγÉ3¸ö¦Ò¼ü£¬Î޹¶Եç×Ó£¬ÔÓ»¯·½Ê½Îªsp2ÔÓ»¯£¬¹Ê´ð°¸Îª£ºsp2£»
£¨4£©AÊÇÓɵڶþÖÜÆÚÁ½ÖÖÇ⻯ÎïÐγɵĻ¯ºÏÎAÊÇÒÒÍéµÄµÈµç×ÓÌ壬Ӧº¬ÓÐ18µÄµç×Ó£¬ÎªBH3?NH3£¬BÊÇÒÒÏ©µÄµÈµç×ÓÌ壬ӦΪBH2=NH2£¬AÖÐBº¬ÓпչìµÀ£¬Nº¬Óйµç×Ó¶Ô£¬¿ÉÐγÉÅäλ¼ü£¬ËùÒÔAµÄ½á¹¹Ê½Îª£¬Ò»¸öBH2=NH2·Ö×ÓÖк¬ÓÐ5¸ö¦Ò¼ü£¬ËùÒÔ1mol»¯ºÏÎïBÖк¬ÓЦҼüµÄÊýÄ¿5NA£¬
¹Ê´ð°¸Îª£º£»5NA£®
£¨2£©ÒÒ´¼·Ö×Ó¼äÄÜÐγÉÇâ¼ü£¬¶ø¼×ÃÑ·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü£¬Çâ¼üµÄ´æÔÚʱÎïÖʵķеãÉý¸ß£¬
¹Ê´ð°¸Îª£ºÒÒ´¼ÐγɷÖ×Ó¼äÇâ¼ü£»
£¨3£©¼×È©£¨H2C=O£©·Ö×ÓÄÚ̼Ô×ÓÐγÉ3¸ö¦Ò¼ü£¬Î޹¶Եç×Ó£¬ÔÓ»¯·½Ê½Îªsp2ÔÓ»¯£¬¹Ê´ð°¸Îª£ºsp2£»
£¨4£©AÊÇÓɵڶþÖÜÆÚÁ½ÖÖÇ⻯ÎïÐγɵĻ¯ºÏÎAÊÇÒÒÍéµÄµÈµç×ÓÌ壬Ӧº¬ÓÐ18µÄµç×Ó£¬ÎªBH3?NH3£¬BÊÇÒÒÏ©µÄµÈµç×ÓÌ壬ӦΪBH2=NH2£¬AÖÐBº¬ÓпչìµÀ£¬Nº¬Óйµç×Ó¶Ô£¬¿ÉÐγÉÅäλ¼ü£¬ËùÒÔAµÄ½á¹¹Ê½Îª£¬Ò»¸öBH2=NH2·Ö×ÓÖк¬ÓÐ5¸ö¦Ò¼ü£¬ËùÒÔ1mol»¯ºÏÎïBÖк¬ÓЦҼüµÄÊýÄ¿5NA£¬
¹Ê´ð°¸Îª£º£»5NA£®
µãÆÀ£º±¾Ì⿼²é½ÏΪ×ۺϣ¬Éæ¼°ÔÓ»¯·½Ê½µÄÅжÏÒÔ¼°Åäλ¼üµÈ֪ʶ£¬ÌâÄ¿ÄѶȽϴ󣬱¾ÌâҪעÒâÅäλ¼üµÄÐγÉÌõ¼þÒÔ¼°ÔÓ»¯ÀàÐ͵ÄÅжϷ½·¨£¬ÎªÒ×´íµã£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿