ÌâÄ¿ÄÚÈÝ

»¯Ñ§¿ÆѧÔÚÒ©ÎïµÄ¿ª·¢¡¢ºÏ³ÉºÍʹÓÃÖÐÆð×ÅÖÁ¹ØÖØÒªµÄ×÷Óá£ÈçСËÕ´ò¡¢ÇâÑõ»¯ÂÁ¡¢Èý¹èËáþµÈ¿ÉÖÎÁÆθËá¹ý¶à£¬ÁòËáÑÇÌú¿É²¹Ìú¡¢·ÀÖÎƶѪ¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öСËÕ´òÓëθËá×÷ÓõÄÀë×Ó·½³Ìʽ£º
                                                                        ¡£
£¨2£©ÏÖÓÐһƿθÊæƽҩƬ£¨¸´·½ÇâÑõ»¯ÂÁ£©£¬ÇëÉè¼ÆʵÑéÑéÖ¤ÆäÖ÷Òª³É·Ö¡££¨Ð´³öʵÑé²½ÖèºÍʵÑéÏÖÏ󣩣º½«Ò©Æ¬ÄëË飬                                                      £¬Ôò˵Ã÷ÆäÖ÷Òª³É·ÖΪÇâÑõ»¯ÂÁ¡£
£¨3£©×ÔÑ¡ºÏÊʵÄÑõ»¯¼Á£¬½«²¹Ìú¼ÁÖеÄFe2+Ñõ»¯³ÉFe3+£¬Ð´³öÏà¹ØµÄÀë×Ó·´Ó¦·½³Ìʽ£º
________________                 ______¡£
£¨1£©HCO3¡ª + H+ ="=" CO2 ¡ü+ H2O  £¨2£©È¡ÉÙÁ¿ÄëËéµÄҩƬ·ÛÄ©Èܽ⵽¹ýÁ¿Ï¡ÑÎËáÖУ¬¹ýÂË£¬È¡ÂËÒºÉÙÐí£¬²¢ÏòÆäÖÐÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒº£¬ÈôÏȳöÏÖ°×É«³Áµí£¬ºó³ÁµíÈܽ⡣£¨ÆäËüºÏÀí´ð°¸¾ù¸ø·Ö£© £¨3£©2Fe2+ + Cl2 = 2Fe3++2Cl¡ª£¨ÆäËüºÏÀí´ð°¸¾ù¸ø·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø