ÌâÄ¿ÄÚÈÝ

ÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£¬ÕýÈ·µÄÊÇ£º
A£®4g¹ÌÌåÁòÍêȫȼÉÕÉú³ÉSO2£¬·Å³ö37 kJÈÈÁ¿£ºS(s)+O2(g)=SO2(g)¦¤H= -296kJ/mol
B£®1molN2Óë3molH2ÔÚijÃܱÕÈÝÆ÷Öз´Ó¦·Å³ö73kJÈÈÁ¿£¬Ôò·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º
N2(g)+3H2(g)2NH3(g)¡÷H= -73kJ/mol
C£®¼×ÍéµÄ±ê׼ȼÉÕÈÈΪ-890.3kJ¡¤mol-1£¬Ôò¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ¿É±íʾΪ£ºCH4(g)+2O2(g) ==CO2(g)+ 2H2O(g)¦¤H=-890.3kJ¡¤mol-1
D£®Ç¿ËáÇ¿¼îµÄÖкÍÈÈΪ- 57.3 kJ/mol£º
Ba(OH) 2(aq)+H2SO4(aq)=BaSO4(S)+2H2O(l) ¦¤H="-114.6" kJ/mol
A

ÊÔÌâ·ÖÎö£ºA£®4g¹ÌÌåÁòÍêȫȼÉÕÉú³ÉSO2£¬·Å³ö37 kJÈÈÁ¿£¬1mol¹ÌÌåÁòÍêȫȼÉÕÉú³ÉSO2£¬·Å³ö37 ¡Á8kJÈÈÁ¿£ºS(s)+O2(g)=SO2(g)¦¤H= -296kJ/mol£¬¹ÊÕýÈ·£»B£®1molN2Óë3molH2ÔÚijÃܱÕÈÝÆ÷Öз´Ó¦·Å³ö73kJÈÈÁ¿£¬ÒòΪ·´Ó¦ÊÇ¿ÉÄæµÄ£¬²»ÄܽøÐе½µ×£¬¹Ê·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£ºN2(g)+3H2(g)2NH3(g)  ¡÷H£¼-73kJ/mol£¬Ô­Ëµ·¨²»ÕýÈ·£»C£®¼×ÍéµÄ±ê׼ȼÉÕÈÈΪ-890.3kJ¡¤mol-1£¬H2OΪҺ̬£¬¹Ê¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ¿É±íʾΪ£ºCH4(g)+2O2(g) ==CO2(g)+ 2H2O(l) ¦¤H=-890.3kJ¡¤mol-1£¬Ô­Ëµ·¨²»ÕýÈ·£»D£®Ç¿ËáÇ¿¼îµÄÖкÍÈÈΪ- 57.3 kJ/mol£¬¶øBa(OH) 2(aq)+H2SO4(aq)=BaSO4(s)+2H2O(l)ÓÐBaSO4(s)Éú³É£¬¹Ê¦¤H£¼-114.6 kJ/mol£¬Ô­Ëµ·¨²»ÕýÈ·£»
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø