题目内容
|
已知硫酸铅(PbSO4)不溶于盐酸也不溶于硝酸,但可溶于醋酸铵(CH3COONH4)溶液中形成无色溶液,其化学方程式为PbSO4+2CH3COONH4=(CH3COO)2Pb+(NH4)2SO4.当在(CH3COO)2Pb溶液中通入H2S气体时,有黑色PbS沉淀生成,则此反应的离子方程式为 | |
| [ ] | |
A. |
(CH3COO)2Pb+H2S=PbS↓+2CH3COOH |
B. |
Pb2++H2S=PbS↓+2H+ |
C. |
Pb2++2CH3COO-+H2S=PbS↓+2CH3COOH |
D. |
Pb2++2CH3COO-+2H++S2-=PbS↓+2CH3COOH |
答案:A
练习册系列答案
相关题目