ÌâÄ¿ÄÚÈÝ

£¨20·Ö£©ÒÔÅäÖÆ250 mL 1mol /LÇâÑõ»¯ÄÆÈÜҺΪÀý¡£ÊµÑé²½Öè
¢Ù¼ÆË㣺ÐèÒªNaOH¹ÌÌåÖÊÁ¿¡£
¢Ú³ÆÁ¿£ºÓÃÍÐÅÌÌìƽ³ÆÈ¡___________gNaOH¹ÌÌ壬³ÆÁ¿Ê±Òª×¢ÒâÁ½¸öÎÊÌ⣺һҪװÔÚ________Àï³Æ£¬¶þҪѸËÙ¡£
¢ÛÈܽ⣺ÓÃÁ¿Í²Á¿È¡ÕôÁóË®×¢ÈëÉÕ±­ÀÓò£Á§°ô½Á°è¡£
¢ÜÀäÈ´£º½«ÈÜÒºÀäÈ´ÖÁÊÒΡ£
¢ÝÒÆÒº£º½«ÀäÈ´ÈÜÒºÓÃ_____      ÒýÁ÷µ½____________ ÖС£ÔÚ²Ù×÷¹ý³ÌÖв»ÄÜËðʧµãµÎÒºÌ壬·ñÔò»áʹÈÜÒºµÄŨ¶ÈÆ«      £¨¸ß»òµÍ£©¡£
¢ÞÏ´µÓ£ºÓÃÊÊÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô_____      ´Î£¬²¢½«Ï´µÓҺעÈëÈÝÁ¿Æ¿Àï¡£
¢ßÕñµ´£ºÊÖ³ÖÈÝÁ¿Æ¿ÇáÇáÕñµ´£¬Ê¹ÈÜÒº³ä·Ö»ìºÏ¾ùÔÈ¡£
¢à¶¨ÈÝ£º¼ÌÐø¼ÓÕôÁóË®ÖÁ¾à¿Ì¶ÈÏß_____     ´¦£¬È»ºó£¬¸ÄÓÃ____   µÎ¼ÓÕôÁóË®ÕýºÃÖÁ¿Ì¶ÈÏß¡£Èô¼ÓË®³¬¹ý¿Ì¶ÈÏߣ¬»áÔì³ÉÈÜҺŨ¶ÈÆ«          £¨¸ß»òµÍ£©£¬Ó¦¸Ã              ¡£
¢áÒ¡ÔÈ£º¸ÇºÃ²£Á§Èû£¬·´¸´ÉÏϵߵ¹£¬Ê¹ÈÜÒº¾ùÔÈ¡£

10.0£»Ð¡ÉÕ±­£»²£Á§°ô£»250mLÈÝÁ¿Æ¿£»Æ«µÍ£»   2-3´Î£»1-2cm £»½ºÍ·µÎ¹Ü£»µÍ£»ÖØÐÂÅäÖÆ

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÀûÓû¯Ñ§Ô­Àí¿ÉÒÔ¶Ô¹¤³§ÅŷŵķÏË®¡¢·ÏÔüµÈ½øÐÐÓÐЧ¼ì²âÓëºÏÀí´¦Àí¡£Ä³¹¤³§¶ÔÖƸ﹤ҵÎÛÄàÖÐCr(III)µÄ´¦Àí¹¤ÒÕÈçÏ£º

ÆäÖÐÁòËá½þÈ¡ÒºÖеĽðÊôÀë×ÓÖ÷ÒªÊÇCr3+£¬Æä´ÎÊÇFe3+¡¢Al3+¡¢Ca2+ºÍMg2+¡£

£¨1£©ÊµÑéÊÒÓÃ18.4 mol¡¤L¨D1µÄŨÁòËáÅäÖÆ250 mL 4.8 mol¡¤L¨D1µÄÁòËáÈÜÒº£¬ËùÓõIJ£Á§ÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ôºÍ½ºÍ·µÎ¹ÜÍ⣬»¹Ðè                       ¡£

£¨2£©Ëá½þʱ£¬ÎªÁËÌá¸ß½þÈ¡ÂʿɲÉÈ¡µÄ´ëÊ©ÓР                               ¡¢

                                      ¡£(д³öÁ½¸ö´ëÊ©)

£¨3£©H2O2µÄ×÷ÓÃÊǽ«ÂËÒº¢ñÖеÄCr3+ת»¯ÎªCr2O72¨D£¬Ð´³ö´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ£º

                                       ¡£    

£¨4£©³£ÎÂÏ£¬²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpHÈçÏ£º

ÑôÀë×Ó

Fe3+

Mg2+

Al3+

Cr3+

¿ªÊ¼³ÁµíʱµÄpH

2.7

¡ª¡ª

¡ª¡ª

¡ª¡ª

³ÁµíÍêȫʱµÄpH

3.7

11.1

8

9£¨£¾9Èܽ⣩

 

¼ÓÈëNaOHÈÜҺʹÈÜÒº³Ê¼îÐÔ£¬Cr2O72¨Dת»¯ÎªCrO42¨D¡£ÂËÒº¢òÖÐÑôÀë×ÓÖ÷ÒªÓР     £»µ«ÈÜÒºµÄpH²»Äܳ¬¹ý8£¬ÆäÀíÓÉÊÇ              ¡£

£¨5£©ÄÆÀë×Ó½»»»Ê÷Ö¬µÄ·´Ó¦Ô­ÀíΪ£ºMn+£«nNaR¡úMRn£«nNa+£¬ÀûÓÃÄÆÀë×Ó½»»»Ê÷Ö¬³ýÈ¥ÂËÒº¢òÖеĽðÊôÑôÀë×ÓÊÇ                   ¡£

£¨6£©Ð´³öÉÏÊöÁ÷³ÌÖÐÓÃSO2½øÐл¹Ô­µÄ»¯Ñ§·½³Ìʽ                          ¡£

 

ÀûÓû¯Ñ§Ô­Àí¿ÉÒÔ¶Ô¹¤³§ÅŷŵķÏË®¡¢·ÏÔüµÈ½øÐÐÓÐЧ¼ì²âÓëºÏÀí´¦Àí¡£Ä³¹¤³§¶ÔÖƸ﹤ҵÎÛÄàÖÐCr(III)µÄ´¦Àí¹¤ÒÕÈçÏ£º

ÆäÖÐÁòËá½þÈ¡ÒºÖеĽðÊôÀë×ÓÖ÷ÒªÊÇCr3+£¬Æä´ÎÊÇFe3+¡¢Al3+¡¢Ca2+ºÍMg2+¡£

£¨1£©ÊµÑéÊÒÓÃ18.4 mol¡¤L¨D1µÄŨÁòËáÅäÖÆ250 mL 4.8 mol¡¤L¨D1µÄÁòËáÈÜÒº£¬ËùÓõIJ£Á§ÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ôºÍ½ºÍ·µÎ¹ÜÍ⣬»¹Ðè                       ¡£

£¨2£©Ëá½þʱ£¬ÎªÁËÌá¸ß½þÈ¡ÂʿɲÉÈ¡µÄ´ëÊ©ÓР                               ¡¢

                                      ¡£(д³öÁ½¸ö´ëÊ©)

£¨3£©H2O2µÄ×÷ÓÃÊǽ«ÂËÒº¢ñÖеÄCr3+ת»¯ÎªCr2O72¨D£¬Ð´³ö´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ£º

                                       ¡£    

£¨4£©³£ÎÂÏ£¬²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpHÈçÏ£º

ÑôÀë×Ó

Fe3+

Mg2+

Al3+

Cr3+

¿ªÊ¼³ÁµíʱµÄpH

2.7

¡ª¡ª

¡ª¡ª

¡ª¡ª

³ÁµíÍêȫʱµÄpH

3.7

11.1

8

9£¨£¾9Èܽ⣩

 

¼ÓÈëNaOHÈÜҺʹÈÜÒº³Ê¼îÐÔ£¬Cr2O72¨Dת»¯ÎªCrO42¨D¡£ÂËÒº¢òÖÐÑôÀë×ÓÖ÷ÒªÓР     £»µ«ÈÜÒºµÄpH²»Äܳ¬¹ý8£¬ÆäÀíÓÉÊÇ              ¡£

£¨5£©ÄÆÀë×Ó½»»»Ê÷Ö¬µÄ·´Ó¦Ô­ÀíΪ£ºMn+£«nNaR¡úMRn£«nNa+£¬ÀûÓÃÄÆÀë×Ó½»»»Ê÷Ö¬³ýÈ¥ÂËÒº¢òÖеĽðÊôÑôÀë×ÓÊÇ                   ¡£

£¨6£©Ð´³öÉÏÊöÁ÷³ÌÖÐÓÃSO2½øÐл¹Ô­µÄ»¯Ñ§·½³Ìʽ                          ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø